Hi Dilon, thanks!
Let's take the shoe as a succession of fresh decks, the card distribution is A,2,3,4,5....K
We'll deal the cards in a baccarat game.
First hand: Player A, 3 Banker 2,4 drawing card is 5. Player wins by 9 over B 6.
Second hand: Player 6, 8 Banker 7, 9. drawing card is a 10. Banker wins with a 6.
Third hand: Player J, K Banker Q, A. Drawing cards are 2 and 3. Banker wins with 4 vs P 2.
Fourth hand: Player 4, 6 Banker 5, 7. drawing cards are 8 and 9. Player wins with 8 vs 1.
Fifth hand: Player 10, Q banker J, K. Drawing cards are A and 2. Banker wins with 2 vs 1.
Sixth hand: Player 3,5 Banker 4,6. Player wins by a natural 8.
Seventh hand: 7, 9 Banker 8, 10 Banker wins with a natural 8.
Eight hand: Player J, K Banker Q-A Drawing cards are 2 and 3. Banker wins with 4 vs 2.
After this hand the process repeats infinitely up to the end of the shoe.
Let's see what happened in those eight hands:
We see that only hand #2 produced an asymmetrical hand and such probability is way larger than expected (12.5% vs the real 8.4%).
The increasing rank order of the deck of course helps the side acting last (Banker) but it's more interesting to notice what an homogeneous rank distribution (13/13) will act in terms of outcomes even though the cards are not featuring a perfect increasing order.