Assuming that the playing hands per shoe are from 45 up to 55, we take an average of 50 hands/shoe.

Assuming that the least wins we can expect during any given shoe is 10 out of 50 decisions then how many would be the equivalent for betting simultaneously 5 boxes?

5 * 50 = 250 bets approximately per shoe.

My estimation is 104 wins in 250 decisions, that's 42 more losses.

10 wins in 50 decisions, that's 40 more losses.

**According my calculations this would be the worst possible scenario during any shoe, but if you believe otherwise then please explain your reasoning.**

An accumulated bust probability for player and dealer when player is using basic strategy is as follows:

1) Player_No-bust AND Dealer_No-bust: 0.665 * 0.665 = 44% of hands (half favorable to Dealer, half favorable to Player)

2) Player_No-bust AND Dealer_Bust: 0.665 * 0.335 = 22% (all favorable to Player)

3) Player_Bust AND Dealer_No-bust: <0.335 * 0.665 => 18% (all favorable to Dealer)

4) Player_Bust AND Dealer_Bust: <0.335 * 0.335 => 8% (all favorable to Dealer).

In situation 1), Dealer and Player have an equal opportunity to win, lose, or tie.

Let's divide the 44 out of 100 hands equally:

22 favorable to Dealer, 22 in favor of Player, thus Player wins 22 + 22 = 44 hands

Dealer wins 22 + 18 + 8 = 48 hands

We notice now only 92 hands out of 100, mystery? NO!

The 8 missing hands are those 8 cases when the Dealer does NOT even play his/her hands out — the simultaneous bust cases.

But what if we would not play by the book and decide to adapt a conservative approach in order not to have busted hands **at all**?

In order to do it properly we should not hit when we have 12 or more, all the rest we hit.

We should always split 6's, 7's and 8's, we should split Aces only if we could hit optionally additional card after the first dealt.

In order to do this you must take the decisions for all 5 boxes/bets, if others taking decisions and you only wager on their boxes then they could take the wrong decisions at your expense.

Thus since we are not going to get busted at any hand the key to success is **33.61%** is the average probability for the dealer to get busted, or once per 3 hands approximately.

Total BJ Actions: 594,768

Hits to 1st 2-Cards: 297,153

Total Non-Bust Hands: 97,735

Total Dealer Bust Hands (*): 199,880

Percentage Dealer Bust: 199,880 / 594,768 = **33.61%**

Natural Blackjacks (10+A): 64 / 1,326 = 4.83%

Total Complete BJ Hands: 297,615

Out of 10,000,000 simulated decisions the maximum delay for the dealer to get busted was 1 in 46 hands/decisions.

46 hands are about 1 shoe, in other words, we should expect at least 1 dealer's bust per shoe.

By combining the accumulated wins and losses after every hand for each box, we are calculating the overall balance and divide it by 5.

If you are in positive balance then you keep flat betting, when you get in negative divide your loss by 5 and bet the calculated sum on all your 5 boxes.

If the sum is less than minimum bet then keep betting the minimum, when the sum is decimal round it up to the closest whole number.

You keep this ongoing calculation only when in loss and till the dealer gets busted, after he/she get busted you restart the count/calculation from scratch.

We divide by 5 simply because we are betting on 5 boxes, therefore when the dealer gets busted we will get paid the amount in all 5 boxes.

steps bet unit$ lost / net profit

1 5*1 -1 / 5

2 5*1 -2 / 4

3 5*1 -3 / 3

4 5*1 -4 / 2

5 5*1 -5 / 1

6 5*2 -7 / 5

7 5*2 -9 / 3

8 5*2 -11 / 1

9 5*3 -14 / 4

10 5*3 -17 / 1

11 5*4 -21 / 3

12 5*5 -26 / 4

13 5*6 -32 / 4

14 5*7 -39 / 3

15 5*8 -47 / 1

16 5*10 -57 / 3

17 5*12 -69 / 3

18 5*14 -83 / 1

19 5*17 -100 / 2

20 5*21 -121 / 5

21 5*25 -146 / 4

22 5*30 -176 / 4

23 5*36 -212 / 4

24 5*43 -255 / 3

25 5*52 **-307** / 5

26 **5*62** -369 / 3

(5*62)+307= **617 units BR** should be sufficient even for most tough shoes.

So what are you waiting for??

Go out there and make some money, enjoy yourselves!