Suppose we play the 1st and 2nd dozen dozen. These are the balls that come out (spins):


1) 16 1
2) 24 1
3) 0 -2
4) 0 -2
5) 30 -2
6) 35 -2
7) 24 1


"I chose wrong, it seems ... two zeros just  spun... hahaha)", the next time I like to make like system sellers who exemplify with actuals  right for the system to work perfectly.


We start recovery with a positive, according to the balls played and Ecart.


Next bet (NB) = 1.5 (spins played - spins lost)


NB = 1.5 (7-4) = 1.5 * 3 = 4.5 we round it to 5. This is our next bet


8)  16 5


NB = 1.5 (8-4) = 1.5 * 4 = 6 This is our next bet


9) 30 -12


NB = 1.5 (9-5) = 1.5 * 4 = 6 This is our next bet


10) 12 6


NB = 1.5 (10 - 5) = 1.5 * 5 = 7.5 -> 8


11) 34 -16


NB = 1.5 (11 - 6) = 1.5 * 5 = 7.5 -> 8


12) 9 8


NB = 1.5 (12 - 5) = 1.5 * 7 = 10.5 -> 11


13) 9 11


We gain  9 chips with 6 wins and 7 losses.


Kind regards, Edgardo.


______________________


Anyway, do not worry much because of the set of actuals that was elected, as I said above it is pretty bad. You know that the odds are ....  ... I forgot.


Well if anyone reads this, please refresh me...

http://www.vlsroulette.com/index.php?topic=519.0

As per request of: Dave.