Bally!!


Thanks for sharing this great system.


I think it will be very consistent......

Bally

"The  ( ) contain the furthest back dozen and/or column."

There is always a furthest back dozen and column, but many times you only list one.  Why?

20 2B (3C) S
22 2A (3C) S
26 3B (C) O<-------------In this case, is not the 1 the furthest back?

Sam

Sam

33 3C (1) S............the C is the furthest back here...........
14 2B (1) S
4 1A (3C) O
20 2B (3C) S
22 2A (3C) S
26 3B (C) O............the 3 appeared here. So I take the 3 out from 3C leaving C........


The 1 is not the furthest back if you look at the number 4.

33 3C (1) S
14 2B (1) S
4 1A (3C) O ..........the 1 appeared here.............
20 2B (3C) S
22 2A (3C) S
26 3B (C) O

cheers

A quick run.....

3 1C
13 2A  (3B).......so now the 3 and B are equal furthest back.........
11 1B  (3).........the B appeared here now leaving the 3 on it's own.........
30 3C  (2A).....the 3 appeared and now 2 and A are equal furthest back........
11 1B  (2A).......2A is still the equal furthest back................
24 2C  (A).....the 2 appeared here now leaving the A on it's own........
34 3A  (1B)......the A appeared and now 1 and B are the equal furthest back......
3 1C  (B).......the 1 appeared here now leaving B on it's own......
31 3A  (B).....the B is still the furthest back..........

Now if I add the O (opposite) and S (same) to the mix.

3 1C
13 2A  (3B).......so now the 3 and B are equal furthest back.........
11 1B  (3)  O.........the B appeared here now leaving the 3 on it's own.........
30 3C  (2A)  O.....the 3 appeared and now 2 and A are equal furthest back........
11 1B  (2A)  S.......2A is still the equal furthest back................
24 2C  (A)  O.....the 2 appeared here now leaving the A on it's own........
34 3A  (1B)  O......the A appeared and now 1 and B are the equal furthest back......
3 1C  (B)  O.......the 1 appeared here now leaving B on it's own......
31 3A  (B)  S.....the B is still the furthest back..........

You can see the run of three O's and then it went to S.

You would just back for the B to remain absent leaving you to bet columns A + C.

That worked out nicely! I just downloaded them from random.org 

cheers

This system, "Run of Three", is this still being used by some people and still proven to be efficient?

Bally, thanks for sharing your idea, I'm not a creator of systems myself, but I'm a tester of good ideas that I find in the forum, with my real and very own actuals. Your game plan is slow but seems to be a winner, one of the safest that I had in my long experience as a player, if I could have two formats as winners like yours, I think it would be unbeatable for roulette, a big hug

Miguel