QuoteYes, Target Gap Size = 9 means you wait until you have 9 Blacks and 1 Red.

However, you do not start betting until you have reached another streak of 5 Blacks (Betting Gap Size = 5).  In other words, after having achieved the Gap 9 of 9 Blacks and 1 Red, you wait until you have another streak of 5 Blacks, which is the Betting Gap Size = 5.

Then after you have a second 5 Blacks you start betting on Red. (similar to virtual betting).  You would then bet on Red for 5 spins which is the "Maximum # of Spins = 5".  Therefore you have 5 Blacks already spun and if you lose all 5 of your bets on Red you would then have 10 Blacks.

In my observations,  you seldom have two streaks of 9 or more in 500 spins.

Cheers

Nick

Hello Nick.
Thanks for the nice explination and now i understand.

I want to test this, but i have one more question.

First i track to get a gap of 9 with one colour, then i wait for a trigger/gap with 5 and then start betting.
But i bet against that a gap of 9 will not appear again with this colour, then i only need to bet 4 times (but you say against 10 gap) this is confusing.
5+4 = 9

The only reason i can think of playing for 10 times is as follows.

Lets say i get a gap of 9 blacks.
Then i wait for 5 blacks to show and start betting red for 4 times.
Assume i lose does 4 times then i have a gap of 9 blacks, then i bet my last bet on black and hope it will become 10 blacks in a row (5 bets) and preventing a 9 black gap to appear twice.

Can you put some light on this.

Many Thanks

Cheers

Also, what type of betting progression do you use (betting 4-5 times in this example)?

Do you link each sequence together with a continuous bet, or restart after 4-5 (again, from the above example)?

Thanks - Very interesting topic!

"Then i wait for 5 blacks to show and start betting red for 4 times.
Assume i lose does 4 times then i have a gap of 9 blacks, then i bet my last bet on black and hope it will become 10 blacks in a row (5 bets) and preventing a 9 black gap to appear twice"

Patrik . . .This is not the way I coded this sheet.  My thinking was that if we happen to get a second 9 Gap then I choose to bet Red one more time gambling that we won't get a streak of 10 blacks.  Your suggestion is another way to play this.

What I tried to do is to allow you to Choose and Test what ever Gap size you want, to Choose and Test whatever Betting Gap Size and to Choose and Test for what ever number of spins you think might win.

I have not tested all scenarios but have shown some that look pretty good.

TheLaw . . . The way that I have tested so far is with a progression that links each bet outcome to the next so the progression continues after a loss but stops on a win.

However, this can also be tested to stop after each betting sequence.  For example, if you choose "Maximum # of Spins to Bet" = 3 and you are flat betting, then if you lose all 3 spin you would have a loss of -3.  Therefore, set the "Stop Loss" in the Sheet to (-3) and it will stop and start a new session.  To Flat Bet, simply enter 1000 in the Progression Divisor shown at the top in cell AU3.

Thanks

Nick

Hello Nick.

Thanks again for a nice explination, now i fully understand how you did your way using 9 gap.
I think this method looks great.

Many thanks

Cheers

Thanks for the info!

So what would your w/L record look like for the progression (and what is the most losses you have seen)?

Something like this : LLLLLWLLLLLLLWLLWLLLLW.....etc?

Sorry TheLaw, the bot I use does not generate a W/L register so I have no idea what it would be like.

Cheers

NIck

 Hello Nick.

I have one more question.

1. Do you wait for a gap of 9 then wait for a gap of 5 then betting, now do you continue waiting for gaps of 5 and continue betting against a gap of 9 (or do you only play once against a gap of 9 and wait for a new gap of 9)?

Many Thanks

Cheers

Good Question, Patrik . . .

Normally I set the Profit Target = 1 so that when we get any profit, it will reset and start tracking the 9 Gap again.

If we set the Profit Target higher, like Profit Target = 10, then it will continue to bet the 5 Gaps until we hit the 10 Unit Profits or the Stop Loss.

My earlier testing was with a Profit Target = 1.  I am currently retesting with a Profit Target = 10 to see how much difference this approach will produce.

Nick

 Hello Nick - i been thinking about practical solutions as i don't like wait to long before i start to play.
A gap of 9 can look as anything as all patterns has same probability.
Any gap can be random pick.

Lets say i walk into the casino and walk to a roulette table and look at the board and write down the last 9 hitting colours.
Then the future results has to match that random sequense 9 times to be a complete match.
Now all i have to do is to wait until i get 5 matching results and start to play.



Cheers

Quote from: Sputnik on February 12, 2015, 01:18:20 PM
Hello Nick - i been thinking about practical solutions as i don't like wait to long before i start to play.
A gap of 9 can look as anything as all patterns has same probability.
Any gap can be random pick.

Lets say i walk into the casino and walk to a roulette table and look at the board and write down the last 9 hitting colours.
Then the future results has to match that random sequense 9 times to be a complete match.
Now all i have to do is to wait until i get 5 matching results and start to play.



Cheers

You could also play 3 sets at once - one for each ec

Yes.
But would we bet once and then start over or would we continue betting until a loss.
Two 9 gaps following by each other would be extreme, so i like the idea betting once and after that pick a new random sequense.

I need to test this one.

Great Idea Patrik . .

I will code up and test out for all 3 EC.

Cheers

Nick

Sound super Nick :-)

Cheers

Hi Patrick . . .

I tested your idea of using the first 9 spins as a Gap 9 and while it started it well it did not end well.  Tried several scenarios and progressions but could not get any of them to work consistently.

While the first 9 spins should equate to a 9 Gap, I think the problem was WHEN the 9 Gap occurs and WHEN the first 9 spins occur.

The thinking was that a 9 Gap usually appears only once in 500 spins so if it appears on the 200th spin then we have only 300 spins left for another one to appear.

The first nine spins always occurs first and then we would always have 493 spins left for another one to appear.  So you would easily get 2 or more of them in the 500 spins.

Still, it was a good thought.

Cheers

Nick

You are right Nick and thanks for your effort.

Cheers