Zumma,
American table,
roulette, no.3,
only 329hit in 15000spins.
Albalaha' challange,
how to win, at least 1u?

I will bet this way,
(though impossible to play, just academic solution)..

329hit x 35=11515u.

thus 11515-15000=-3485deficit...if flatbet 1u all the way.


since we know only 329 hit,
we will try to squeeze the losses, into 329hit.

1) bet 329x35=11515spin.
bet 11515spin flat , 1unit.

after 11515spins,
How many hit? (of number3.)=(x)
How many losses?(of units)=(y).

after 11515spins,
329-(x)=(n).
(n)=remaining hit.

then losses,
(y) divided, by (n).
====================

below an OVERSIMPLIFIED,
calculation,
of what we supposed, to see...
Mind you, I say,
OVERSIMPLIFIED.

11515/45.59=252.58hit
252.58hit x35=8840unit,
minus 11515=-2675units losses...

2675+3485=6160.


thus 252-329=77hit left.in 3485spins

6160/77=80u. per hit
==============o

one of the simple solution, is virtual bet the first 11515spins,
and then see how much losses incurred,
and the bet the remaining,

Trying to curve fit a given data is not a wise idea. Different set of 15k may have very different scatter or wins of a number. Only that strategy is good strategy that can be played all over with all the rules being consistent. Making one way to play for one set of data is like fooling yourself. No wonder none could do my challenge in any sane manner.