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To all maths expert in roulette.....

Started by Rouletta, November 25, 2015, 12:41:26 AM

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Rouletta

Hi everyone

By playing 9 lines, or 27 numbers ( 9x3=27) on european wheel; (the 0 is being covered with 0/1/2/3),
Does anyone know what is the probability to miss the 9 lines 3 times in a row.  Assuming during the 3
spins the bets are not moved.

Does anyone know the formula to calculate the probability for losing 3 times when betting 27 numbers.
Thanks.


Rouletta


AsymBacGuy

Ignoring zero, it should be around 1.56%.
And of course there's no difference to change or not moving bets.   

as.

Baccarat is 99% skill and 1% luck

CLEAR EYES, FULL HEARTS. CAN'T LOSE
(Friday Night Lights TV series)

I NEVER LOSE.
I EITHER WIN OR LEARN
(Nelson Mandela)

Winners don't do different things, they do things differently (Albalaha)

Rouletta

@ AsymBacGuy - Thanks for the reply. Is it possible to explain how do u come up with the 1.56% please.

It seems to me that by playing 9 lines, or 27 numbers for 3 spins with a light progression, the probability for
losing is extremely low. Do u agree....?

Cheers

Rouletta

AsymBacGuy

Quote from: Rouletta on November 25, 2015, 01:47:42 AM
@ AsymBacGuy - Thanks for the reply. Is it possible to explain how do u come up with the 1.56% please.

It seems to me that by playing 9 lines, or 27 numbers for 3 spins with a light progression, the probability for
losing is extremely low. Do u agree....?

Cheers

Rouletta

Hi rouletta!

Considering an european wheel and zero excluded, betting 27 numbers out of 36 means to have a 25% probability of losing each time. So 0,25 x 0.25 x 0.25 = 1.5625%.

To get an easier example, let's say you want to hope not to get three red in row.

So 0.50% x 0.50% x 0.50% = 12.5% of losing, that is 1 time every 8.

In fact there are 8 possible dispositions of 3 spins in a row: BBB, BBR, BRB, BRR, RBB, RBR, RRB and RRR. Just one disposition is a losing one.

Since your probability is right the half of the above situation everytime, you'll divide 12.5% 3 times getting 6.25, 3.125 and the final 1.5625 probability.

Unfortunately no matter how many numbers you'll wager, the probability of losing will be proportionally placed.

The highest probability to win when betting roulette numbers on an european wheel is placing 36 numbers out of 37, but it needs 144 units to win just one unit.
The trick to get a profit even betting 36 numbers relies on the fact that some bets are cumulatively placed on 50/50 chances, so getting a 50% return when the zero comes out.

Cheers

as.   
     
Baccarat is 99% skill and 1% luck

CLEAR EYES, FULL HEARTS. CAN'T LOSE
(Friday Night Lights TV series)

I NEVER LOSE.
I EITHER WIN OR LEARN
(Nelson Mandela)

Winners don't do different things, they do things differently (Albalaha)