and

0.X.0
B.P.P
P.P.B   +- + -
X    I

to sum up "+ -"

B.B.B

B.B.B   this gives  : ++++



P.B.P.B

B.P.B.P this gives  : ++++++



P.P.P

B.B.B   this gives : ----



P.B.P

B.B.B  this gives; + - - +

Quote from: Sputnik on January 22, 2014, 01:18:52 PM

If i understand you correct so is AS game more common and we should take advantage out of this phenomena.
To illustrate this:

Asymmetric game ''....'.'....''..'''''.'...'.'''''''''..'''.'....''.'..''....'.'''''....''....'...'''.''...

Symmetric game ''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..''..

Is that what you aim at or did i misunderstand you ?

there are many symmetrical positions in your "asymmetric game":

"....'.'...."

'''''.'...'.'''''

'....''....'    _____and others

you will lose your underwear with this method

34        
27   
32   
36           10
10           10
0           -2
11           -2
12           -2
9           no bet
6           no bet
10           10
26            -2
25            -2
2             -2
21            -2
10            10
7            -2
9            -2
25            10
19            -2

I look at the last three numbers and I bet on the street who has not touched its opposite or herself.

The street 1 is the opposite of street 12
       street 2                             street  11 
       street 3                             street   10   .....etc

     I tested this on 1980 spins (random . org)  :  results  +134

            what do you think ?

    Best regards

I quote  Dane :
Sorry. What I meant  to write in my initial post was of course
that within two spins you´ll PROBABLY hit the chosen dozen.
And if we ignore zero the probability is 0.55555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555555
______________________________________________________________________________________
Yes it is true but there is no avavantage to this because you hire 2 bets to win one.
You will lose 2 put a little less than half the time.
Ie 45% (excluding zero).
Sorry

"last dozen hit"  is not a "repeat" 

22         
          27
          23
15         
          7
          14
          23
          34
          5
          25
          21
          19
          7
          18
13         
          34
4         
33         
24         
          5
   
          16
          1
          19
33         
31         
     0    
35         
--    --    --
20         
8         
4         
4         
17         
29         
24         
8         
4         
          19
20         
          18can anyone show how the method works only on R and N ? Thanks

say it another way:
36 times the same EC happens very often, but these series appear in disguise.
18 numbers = 18 numbers
It's a fact .

1         6                 
2         6              
3         26         
4          29         
   
5          24         
6          24         
7         19
8          19
9            1
10          8         
11        24            
12         16
13        24         
14        30
15        30
16        16
17         10         
18          8         
19          6         
20          4         
21           6         
22           6         
23           2         
24         33         
   
--    --    --
25         16
26        5
27        1
28           36
29           8         
30            8         
31         5
32           14
--    --    --
33           33         
34           15         
35             4      ......18 numbers different .This corresponds to a séries of 35 red

Tisch 4" vom 02.09.2014 (extract)
     
        

I am sorry but I think that you ought to look longer!
I don´t have a degree in math,
but I am sure that there are MANY possible combinations with 18 different numbers.

______________________________________________________________________________________________

Yes  ...
I say something else ?

T3 wiesbaden 02/09/2014 (extract)
1
20
28
20
1
13
21
34
1
26
1
26
2
26
1
31
31
9
0
3
10
19
18
25
30
14
27
28
14
31 ...........30 spins  18 different numbers
This corresponds to a séries of 30 red
I did not look long.
To make 6 more is a breeze for roulette!

Yesterday T3 wiesbaden

can you choose your attacks  please ;

N
N
R
R
N
R
R
N
N
N
R
R
N
R
N
R
R
N
N
N
R
N
R
R
N
R
R
N
N
N
N
N
R
R
N
N
R
N

Interesting, but we don't understand your attack logic .
I resume your last exemple .

1
2
2
1
1 ...L  ?   why bet for a single?
2
2...W     .... OK
2
1
1....W ...OK
1
1
1
2
1...L ...OK
1 .............. why you don't bet for 1 ?
1
1
2
1 ....L  ...
2 ...L ....OK
2

I like your théorie of departure .
But  the tests must always attack the same procédure .
What you say ?
Thank you .

Basic Premise:   The majority of systems on this forum are capable of delivering 1 unit profit.
if this is the case, why switch methods?
I know of no method that can ensure certainty of winning a bet.
which one?