Author Topic: Bally's final solution (hopefully!)  (Read 6012 times)

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Offline horus

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Bally's final solution (hopefully!)
« on: May 01, 2015, 02:14:04 pm »
Hello guys,

 Not been around much lately what with one thing and another. Sorry about not continuing on with my ec challenge for anybody that was going to follow. It was a bit complicated and so I rejigged the idea to something a bit easier to operate and play.

As some of you will know, I really like the idea of using pairs.

I used to look at them like this......RR, RB, BB, BR....OO, OE, EE, EO....LL, LH, HH, HL to cover all of the 3 even chances. But to be honest, it can all get a bit stressful checking 12 pairs like this in live conditions if you don't have much time.

So what I do now is to look at them like this....

RO (red odd)
RE (red even)
BO (black odd)
BE (black even)

and I also incorporate the 4 groups 1-9, 10-18, 19-27, 28-36.

So there are only two sets operating instead of the three sets using all three e.c's.

I have enclosed a book at the bottom to show you all how this thing works.

Using 4 groups like this produces some long absences. They can go 20+ at times. But quite often you get runs of 9,10,11 etc......

If you look at the book from spin 19 through to spin 26, you can see that group 19-27 is absent and looking across to the right, you can also see that the BE (BLACK EVEN) is absent. So that would leave you with any numbers that are not BLACK EVEN in groups 1-9, 10-18, 28-36.

These numbers would be 1,3,5,7,9,11,12,13,14,15,16,17,18,29,30,31,32,33,34,35,36. (you can throw in the 0 if you like as well)

You get some really good runs like this.

One thing that I have noticed is how sometimes you will get two of these pairs going absent in a set.

So in those same spins that I just showed you....19-27 and 28-36 both went missing at the same time for a while.

So now let's suppose you leave out 19-27, 28-36 and BLACK EVEN.

That only now leaves you with 1,3,5,7,9,11,12,13,14,15,16,17,18 = 13 numbers (14 including the 0)

So it always pays to watch what is going on among these two sets of pairs.

I like this concept because like I say, it's not as complicated as some of my other ideas and is relatively easy to track and see what's unfolding as the game goes along.

There are a few other things that I have noticed which happen with a degree of frequency using these two sets however at the moment I am not sure if it is just some variance from the norm or not. So I will do some more testing and live play with it to get a better idea.

I will ask Nicksmi if he has the time to make a tracker for this and upload it so anybody else interested can test it / play it as well.

cheers
If you fail to know, fail to prepare, fail to plan and practice, then know full well that you are knowingly preparing and planning to lose. What you don't know and don't do will be your undoing.

Offline VLS

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Re: Bally's final solution (hopefully!)
« Reply #1 on: May 01, 2015, 04:54:33 pm »
Thanks for sharing your ways with us dear friend.

Kudos to you for sticking to the creative side :thumbsup: :thumbsup:

Keep 'em coming! Gladly, we can track basically everything these days thanks to computers  :)
Email: betselectiongmail.com
-- Victor

Offline horus

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Re: Bally's final solution (hopefully!)
« Reply #2 on: May 01, 2015, 05:12:49 pm »
Thanks Vic  :thumbsup:

I have to say I really like the possibilities with this.

Betting against what isn't coming up seems the most logical solution to me at least.

Here is another book with some numbers from yesterday.

You can see how many times in this example that you are getting two pairs from each set missing. That would filter out a lot of sleepers.

It depends how many numbers (or how few) you are happy playing.

cheers

If you fail to know, fail to prepare, fail to plan and practice, then know full well that you are knowingly preparing and planning to lose. What you don't know and don't do will be your undoing.

Offline RouletteFan

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Re: Bally's final solution (hopefully!)
« Reply #3 on: May 01, 2015, 09:01:48 pm »
Thank for sharing
 
and for all your innovatives post

best from Monte Carlo

Offline horus

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Re: Bally's final solution (hopefully!)
« Reply #4 on: May 02, 2015, 10:52:20 am »
Thanks Shaft,

 I am enclosing the tracker that Nick kindly provided for anyone who wants to input some of their own numbers and have a look.

With this tracker, you just input your numbers starting from the A5 cell and away you go.

One thing that ties in well with what I am doing here are the following 8 number groups.

1,3,5,7,9 (red, odd, low)
2,4,6,8,10 (black, even, low)

So in the 1-9 group....you have the 1,3,5,7,9 and the 2,4,6,8. (The 10 is the odd one out)

11,13,15,17 (black, odd, low)
12,14,16,18 (red, even, low)

In the 10-18 group....you have the 11,13,15,17 and the 12,14,16,18.

19,21,23,25,27 (red, odd, high)
20,22,24,26,28 (black, even, high)

In the 19-27 group....you have the 19,21,23,25,27 and the 20,22,24,26. (The 28 is the odd one out)

29,31,33,35 (black, odd, high)
30,32,34,36 (red, even, high)

In the 28-36 group....you have the 29,31,33,35 and the 30,32,34,36.

Now here is the thing....

Suppose the RE is absent and the 10-18 section is absent. There are already four RE numbers in the 10-18 section which are 12,14,16,18.

So you could just play 0,1,2,3,4,5,6,7,8,9,19,20,21,22,23,24,25,26,27,28,29,31,33,35 =24 numbers.

But you are not really getting full value because of those four RE numbers in the 10-18 section.

But now let's suppose the BE is absent and also the 10-18 section. There are no BE numbers in the 10-18 section (apart from the 10). So this is going to reduce the outlay of the bet.

It would now be 0,1,3,5,7,9,19,21,23,25,27,29,30,31,32,33,34,35,36 = 19 numbers. So that's a 5 number difference.

So like I said in the original post, it pays just to watch what is going on and look for the permutations which can give you a bet with a low outlay because you will still get good runs with the lower outlay.

cheers

If you fail to know, fail to prepare, fail to plan and practice, then know full well that you are knowingly preparing and planning to lose. What you don't know and don't do will be your undoing.

Offline klw

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Re: Bally's final solution (hopefully!)
« Reply #5 on: May 02, 2015, 08:23:22 pm »
Thank you once again horus.