Consider the following example valid for every even chance game (roulette,baccarat,craps,blackjack,coin tossing)
R=result B=bet T=total
     R   B   T
1)  L   1   -1
2)  L   1   -2
3)  L   1   -3
4)  L   1   -4
5)  L   1   -5
6)  L   1   -6
7)  L   1   -7
8 )  L   1   -8
9)  L   1   -9
10) L   1   -10
11) L   1   -11
12) L   1   -12
13) L   1   -13
14) L   1   -14
15) L   1   -15
16) L   1   -16
17) L   1   -17
18) L   1   -18
19) L   1   -19
20) L   1   -20
21) L   1   -21
22) L   1   -22
23) L   1   -23
24) W  1   -22
25) L   1   -23
26) L   1   -24
27) W  1   -23
28) L   1   -24
29) L   1   -25
30) L   1   -26
31) L   1   -27
32) W  1   -26
33) L   1   -27
34) W  1   -26
35) L   1   -27
36) L   1   -28
37) L   1   -29
38) L   2   -31
39) W  2   -29
40) L   2   -31
41) L   2   -33
42) W  2   -31
43) L   2   -33
44) L   2   -35
45) L   2   -37
46) L   2   -39
47) L   2   -41
48) L   2   -43
49) W  2   -41
50) W  2   -39
51) L   2   -41
52) L   2   -43
53) L   2   -45
54) W  2   -43
55) L   2   -45
56) L   2   -47
57) W  2   -45
58) L   2   -47
59) W  2   -45
60) L   2   -47
61) W  2   -45
62) L   2   -47
63) L   2   -49
64) L   2   -51
65) L   2   -53
66) W  2   -51
67) L   2   -53
68) L   2   -55
69) W  2   -53
70) L   2   -55
71) L   2   -57
72) W  2   -55
73) L   2   -57
74) L   2   -59
75) L   4   -63
76) W  4   -59
77) L   4   -63
78) L   4   -67
79) W  4   -63
80) L   4   -67
81) L   4   -71
82) W  4   -67
83) L   4   -71
84) L   4   -75
85) L   4   -79
86) W  4   -75
87) L   4   -79
88) L   4   -83
89) L   4   -87
90) W  4   -83
91) L   4   -87
92) L   4   -91
93) W  4   -87
94) L   4   -91
95) L   4   -95
96) L   4   -99
97) W  4   -95
98) L   4   -99
99) W  4   -95
100)L  4   -99
101)W 4   -95
102)W 4   -91
103)L  4   -95
104)L  4   -99
105)W 4   -95
106)L  4   -99
107)W 4   -95
108)W 4   -91
109)L  4   -95
110)L  4   -99
111)W 4   -95
112)L  8   -103
113)L  8   -111
114)L  8   -119
115)L  8   -127
116)L  8   -135
117)W 8   -127
118)L  8   -135
119)L  8   -143
120)W 8   -135
121)W 8   -127
122)L  8    -135
123)W 8   -127
124)L  8   -135
125)L  8   -143
126)L  8   -151
127)L  8   -159
128)L  8   -167
129)W 8   -159
130)L  8   -167
131)W 8   -159
132)W 8   -151
133)W 8   -143
134)L  8   -151
135)W 8   -143
136)W 8   -135
137)L  8   -143
138)W 8   -135
139)L  8   -143
140)L  8   -151
141)W 8   -143
142)L  8   -151
143)W 8   -143
144)L  8   -151
145)W 8   -143
146)L  8   -151
147)W 8   -143
148)L  8   -151
149)W 16 -135
150)L  16 -151
151)L  16 -167
152)W 16 -151
153)L  16  -167
154)L  16  -183
155)L  16  -199
156)L  16  -215
157)L  16  -231
158)L  16  -247
159)L  16  -263
160)L  16  -279
161)L  16  -295
162)L  16  -311
163)W 16  -295
164)L  16  -311
165)W 16  -295
166)W 16  -279
167)W 16  -263
168)L  16  -279
169)W 16  -263
170)W 16  -247
171)W 16  -231
172)L  16  -247
173)W 16  -231
174)W 16  -215
175)L  16  -231
176)L  16  -247
177)W 16  -231
178)L  16  -247
179)W 16  -231
180)L  16  -247
181)W 16  -231
182)L  16  -247
183)L  16  -263
184)W 16  -247
185)L  16  -263
186)L  32  -295
187)L  32  -327
188)W 32  -295
189)L  32  -327
190)W 32  -295
191)W 32  -263
192)L  32  -295
193)W 32  -263
194)L  32  -295
195)W 32  -263
196)L  32  -295
197)L  32  -327
198)W 32  -295
199)W 32  -263
200)W 32  -231
201)L  32  -263
202)W 32  -231
203)L  32  -263
204)L  32  -295
205)W 32  -263
206)W 32  -231
207)L  32  -263
208)W 32  -231
209)W 32  -199
210)L  32  -231
211)W 32  -199
212)L  32  -231
213)W 32  -199
214)L  32  -231
215)W 32  -199
216)W 32  -167
217)W 32  -135  <----- NEEDS TO CONTINUE

Of course with very few more wins would have finished in positive, if you could post the next spins here I'm going to show you what I mean.

However, you got the point about how my progression handles such bad results, also important to mention is that it remained within reasonable table and bankroll limits.

The max drawdown was 327 units and the max bet 32, not so big if we consider that the results were almost unrealistically bad.

I'm going to post 2 more examples and once again please post a few more spins from the above session because I want to prove you that it would have won!

I've to admit, betselection.cc is the place where great roulette spirits are coming together!;-)

Quote from: RouletteGhost on February 19, 2016, 11:51:21 PM
please see my column method in my blog, thanks

Your method isn't better than mine, why should I bother??

When a lot of posts have been removed by the author of this topic, how do you expect democracy of different opinions and approaches to be alive??

Perhaps it's best, according to the author of this topic, to speak and listen to ONLY what he wants, but this has never helped to evolve in any way, at any time.

Common sense after all.

Instructions:

Every third bet raise each position by 3 units.

Continue to do so till you broke or till the bank breaks.

I wish you enjoy it as I did!;-)[attachimg=1]

There has been a mistake in my calculations when I said that recommended bankroll is 320 units, actually is much less, for example let's say your unit value is 10 $, on stage 1 you are risking 2 units, on stage 2 you are risking 3 units and on final stage 3 you are risking 14 units (if arrived from stage 1) or 21 units (if arrived from stage 2).

This adds up to 24 units maximum if value of unit is 10 $, for unit value of 5 $ double the overall amount of units, thus 48 units.

Another thing which I'd like to clarify is the amounts regarding "LAY" bets, I know that casinos don't have the same betting limits and commissions to be paid, therefore you should do a little homework in order to increase or decrease proportionally those amounts in order to yield approximately the same profit for every possible result.

If you still looking for results,I've s lot from brick and mortar casinos (single 0)

So a 150 Euro bankroll would be sufficient for betting 0.01 units?
By the way,do you know any casino which offers 0,01 bets at all betting sectors?
Ophis,are you Greek? Because I'm.

I never joke about my job

Actually we were both wrong because RNG stands for Random Number Generator,
but it's not really Random because it's a predetermined string of Numbers.

But my mistake was not because I didn't know, but because I was typing quickly.
Thanks for your comments, I will reform it in order All of you can read it comfortably.

INTRODUCTION

First of all, for those who don't know what the initials R.N.G. mean is: Random Number Generator.
RNG is a program and like any other program, which has been created by humans, has vulnerabilities because is in the human nature to generates faults.
The purpose of this manual is to exploit those "vulnerabilities" by interpreting properly the signs we are receiving while gambling online and offline.With a different perspective, the same outcomes would produce different results...
Imagine roulette as transmitter and you the receiver, the "contact" would fail only if you wouldn't "decode" the "messages".
Thus it's a constant update of the statistical data, or the "signs" if you prefer.#In order you to be Up-to-date you should have 100 % concentration on the time of action and keep a record till you stop gambling.
Roulette has no memory but the repetition of certain patents is totally irrelevant with memory.

ABOUT RNG

The programmers have decided that they would let the RNG do all the dirty work.
The game of roulette will use the next RNG on the list to determine how the path is created.
If the path ends in a vertical direction (upwards or downwards), the RNG will be any number from 19 through 36 which means HIGH.
If the path is horizontal (leftwards or rightwards), the RNG will be any number from 1 through 18
(LOW, including number 0).
If the last two numbers generated a path with direction from up to right, right-up, left-down,down-left, left-up, up-left, right-down and down to right, then this means NO BET!
Note that this doesn't pinpoint the exact number.

Just imagine roulette wheel as a compass,with its top on the number Zero, now split the wheel in four parts, upper, down, left and right.
Take the last two numbers and connect them with a line on the wheel...how is the direction you've just created?
Towards what direction?
Maybe sounds complicated and confusing, but it's really easy and like every other thing in life, it could be a habit after some practice.
So how can we exploit this theory to predetermine pseudo-random numbers?
To fully manipulate the RNG sequence, we need to make a list of numbers.
I will designate the letter L to represent the range of 0-18 (whenever the reconstructed RNG path makes a vertical path) and the letter H to represent the range of 19-36 whenever the reconstructed RNG path makes a horizontal path).
Once we have written down our first RNG, press the spin button to generate another one.
Make another loop (spin) like the previous example and record the next RNG.
(Remember that the RNG sequence is pre-determined)
Take a look at this example:H - L - H - L - L - H - H - H - L - L
Depending on the situation, you may want to make this list shorter or longer.

But before that, let's see how the RNG is actually used in roulette.
What is the RNG used for?
One of the more prominent uses of the RNG is in calculating hit rate.
When betting, both your prediction and the opposite outcome will have a hit rate, the percentage or likelihood that a wheel's section will hit or miss.
While the RNG does NOT calculate these predetermined stats (those are based on actual odds),
it does determine a number that will be used to see if your bet will succeed or not.
Let's use the example we had earlier only this time, we'll make up numbers to better illustrate it.
H   L   H   L   L   H   H   H   L   L
24 18 32 14 15 33  31 27  12  4
You can use RNs (Random Numbers) the same way you found them, by forcing the game to reconstruct a path with two possibilities.
If you wish to use 2 RNs (Random Numbers) in a list, make a loop (spin) until the path is made (up to down or left to right and vice versa), press spin again, make another loop until the path is remade, press spin, then bet accordingly.
The game uses the previous numbers in the sequence and averages them to determine hit rate odds.
If this number is smaller than a bet's hit rate percentage, the prediction will hit (succeed).
If this number is equal to or larger than your bet's hit rate percentage, the bet will miss (fail).
When predicting correctly the game will use 3 RNs, two for updating outside bets odds and one for the numbers.
If you loose, the game will only use the 2 RNs for updating hit rate odds.
Any predicted straight up number hit will use 4 RNs.The RNG is also used when your units are growing, once you gain 100 units, the stats will be updated.
When updating, the odds may increase and/or decrease accordingly any of the six possible stats (outside bets).
The game will use the next 6 RNs (random numbers) in the RNG sequence to determine the odds that each stat's (outside bets) odds will go up and/or down.
The order of the level-up/down sequence is LOW,EVEN, BLACK, HIGH, ODD, RED.
It's slightly different than the order presented in the table layout (which is LOW, EVEN, BLACK, RED, ODD, HIGH from the left to right).
Let's say you won your bet, how many numbers you should calculate to determine next spin's hit rate (odds)?
If you answered 3, you are right.
For example the last three outcomes were 24 plus 36 plus 7 to get 22.33 % (24 + 36 + 7 = 67 / 3 = 22.33)
Since 22.33 % is smaller than approximately 50 %, an outside bet (low/high,black/red,even/odd) will be successful.
Skipping 2, 3, 4 or 6 RNs (Random Numbers) will produce the hit rate odds of the next spin.
You get the picture now?This is the idea behind the linear congruential generator (pseudo-random-number-generator).

ROULETTE WHEELS
My theory is a careful calculation and not a guesswork based on hunches and telepathy.
Furthermore it's much more simpler, easier and faster than any other VB method out there, thus more practical and better.
A small note for those who don't know what the initials VB mean is: Visual Ballistics.
A big number (corresponding to the circumference of the wheel) times a big number (the number of trips made around the wheel before the ball comes to rest) yields a very big number (the total distance that the ball travels).
Adding this distance to the starting point (the release point of the ball) determines exactly where the ball will end up.
Taking the remainder of this total with respect to the wheel circumference determines the final position of the ball, by subtracting off all the loops made around the wheel by the ball.
Once you clock the rotor's speed you won't have to re-calculate it because rotor's speed is stable.
Croupier's or if you prefer, ball's speed is slightly different on every spin.
Since we can't bet during the last rotation of the ball before it rests on one of the 37 pockets, we have to take the average speed of the current croupier.
Therefore we have to update/re-calculate the ball's speed with every new croupier or whenever we think it's necessary.In order to time the rotor and the ball, it's much better to use a digital timer because even fractionsof the second do count towards a significant difference on the outcome.
Therefore you can't perform this calculation so precisely in your mind, the easiest and better way of a digital timer is strongly recommended.
Watch closely the spinning rotor, watch for the zero,or any other number of your choice, to start and pass a specific point A of the wheel,this point could be a deflector.
Zero is easier to mark because of the green color.When zero reaches that specific point A (deflector), push your timer's stop button immediately.
That concludes the timing of the rotor, from my experience, it's usually around 1.2 seconds for a full rotation (from point A back to the same point A).
The rotor's speed won't change, so now you must focus on timing the ball which is harder.
Like you did for timing the rotor, the same way you will time the ball, watch closely where the croupier is releasing the ball on the wheel, start timing from that number till the ball returns to the same number after the first rotation around the wheel's rim.
Not every croupier is throwing the ball with the same power, neither is exactly the same power from spin to spin.
An average release power is 14 full rotations, when you have a croupier who from the time he/she releases the ball till the time the ball lands in one of the 37 pockets, makes 14 full rotations which is equal with an average time of 0.8 seconds per rotation.
The time of the first rotation is the fastest till the time of the last before it falls, which is the slowest.
So not every rotation is the same speed but we need the average, in order to achieve this you need to time the first and last spin, add the two durations and divide the sum by two.
Now you have the average time per rotation, multiply this duration by the total number of rotations and you have the total rotation time of the ball.Like I said the release power is not the same, that's why you need to time the croupier from 5 up to 10 spins before you place your first bet.
This way you will have the average timing of your croupier.
Next thing to do is to divide the total rotation time of the ball by the rotors spinning time.
For example the croupier is throwing the ball with such power which makes the ball rotating 14 times before it lands and this happens 7 out of 10 times, 2 times makes 13 rotations and 1 time 15, the calculation would be the following:
14 (rotations) x 0.8 (average secs/rotation) = 11.213 (rotations) x 0.9 (average secs/rotation) = 11.715 (rotations) x 0.7 (average secs/rotation) = 10.5(11.2 x 7) + (11.7 x 2) + (10.5 x 1) / 10(78.4 + 23.4 + 10.5) / 10112.3 / 10 = 11.23
This is the average timing of your croupier, in order to pre-determine where the ball will fall, you should divide the average timing of your croupier by the rotors time.11.23 / 1.2 = 9.35
This means that the ball will land 35 % further from the release point.
If you wonder what means 35 % further, then consider that the wheel has a total of 37 numbers,so the 100 % is 37 numbers, how much would be the 35 % ?35 % is something more than the 1/3(one third) of the wheel, if we divide 37 by 3 equals 12.33, thus approximately 13.
Which means 13 numbers after the releasing point, when saying after I mean towards the ball's direction and not towards the rotor's.
Due to the deflectors it's strongly advisable to place your bets on 12 numbers, 3 numbers before the number we found from the aforementioned calculations plus 9 numbers after the same number (including the pinpointed number)
When you win, you will earn two times your bet (net profit) or three times your bet accumulated profit (including your bet).
The way you bet it's totally up to you, to bet on twelve numbers is just my suggestion, you may bet as many or as few numbers you wish, with or without any betting progressions.
Like I said from the beginning, my aim is to reveal you a way of determining the outcome and not to tell you HOW MUCH but WHERE to bet.
The quantity is better being determined by your budget / bankroll.

Suggested bankroll is 320 units per session.
Unit could be 1 $ or 5 $ or 10 $...etc
For example,if you decide that your unit value is 5 $,then you would need 320 x 5 = 1600 $ plus proper table limits.
I would like to add that what it matters most of all is the overall,the total result.
So you have to calculate this system as a whole and not partially,the stage 1 and 2 by their one have a negative expectation,indeed.
When you proceed to stage 3 for the recoup,you have 7 chances with you and only 1 against you.
They used to say that the "chain" is as strong as the weakest link...the worst case scenario is to proceed on stage 3, which eventually happens, but there we have 87.5 %
against 12.5% rate of success,even if this would not been confirmed by the first set of 3 consecutive outcomes,we may proceed to a 2nd set of 3 outcomes.
Two times in a row to happen a 12.5% against the 87.5% is an extremely rare occasion!

This is a very strong system,but what it could make it INVISIBLE are additional 2 things:
1) Set your LIMITS according to your budget, the STOP limits must be exactly the SAME!
For example you set your limits to 320 units whether you win or loose,every session must be +320 OR -320!!
This way you don't have to win every session,but to win the most of them.
If for example after 10 sessions you won 7 and lost 3,you would have a net of 1280 units. (7 x 320)-(3 x 320) => 2240 - 960 = 1280
These numbers are very REALISTIC! To win 7 sessions out of 10 it's an average result regarding my experience.
2) If you combine this system with dice setting/control and the stop limits like described above,then you have a full time gambling income for life!

My system in combination with Dice Setting, it's the best possible option, not only in CRAPS, but for every gambling game which has ever been offered by the casinos!
You could ask me why I say so.
The answer actually is very obvious if you think it for a while...Craps is the only game which PLAYERS are determining the outcome!
YOU roll the dice! Setting and rolling the dices according your desired result could be taught like a child is learning to speak, like a tiger is learning to jumb through a fired ring, like aiming a target with a gun or a crossbow...and so on.
No other game, the final outcome depends on you and I don't mean by using illegal devices and cheating!

Perhaps some of you have heard about the Parity Hedge System and almost all of you think that this is similar of the Doey / Don'ts system, but you are wrong...
I don't like long intros and big words,so let's get straight to the point.
This system consists of 3 different but unified stages:

Stage 1 }  Place 10 units on Pass Line plus 10 on Field.
Let's take a look by betting so,what's every possible outcome.

TWO >  1-1 }  I'm losing my Pass Line bet -10 but winning +20 from the field,which is a total of +10

THREE >1-2 / 2-1 }  I'm losing my Pass Line bet, but winning my field bet for 0 result (no profit/loss)

FOUR > 2-2 / 1-3 / 3-1 }  I'm winning my Field bet + 10 and the point goes to 4,here instead of risking our already earned profit,we are going to "lock" it by laying 14 units on 4,whether a 7 or a 4 appears,we will loose 6 units,but since we won 10 from the field before,we'll have a net of +4

FIVE >  2-3 / 3-2 / 1-4 / 4-1 }  I loose my Field bet -10 and making a point to 5 which if 5 rolls out again,we will break even,if not,we proceed to stage 3 which will be explained later

SIX >  1-5 / 5-1 / 2-4 / 4-2 / 3-3 }  The same here as above,losing the Field bet and want a repeat to break even,or if I loose both (-10 + -10 = -20) moving to the third stage

SEVEN > 1-6 / 6-1 / 2-5 / 5-2 /3-4 / 4-3 } I'm winning my Pass Line bet but losing my Field,so I break even

EIGHT > 2-6 / 6-2 / 3-5 / 5-3 / 4-4 }  In this case is the same as on 5 and 6,see above

NINE >  3-6 / 6-3 / 4-5 / 5-4 } I'm winning my field bet +10 and making my point on 9,this time I'm going to Lay the 9 with 12 units in order to create a sure win of +6,whether the 7 or the 9 will come out first,I'll loose 4,but since I won 10 from the Field,I'm an overall winner of +6 for this rollout

TEN >    4-6 / 6-4 / 5-5 } Here is the same situation as on 4,winning 10 from Field and Laying the 10 for 14 units,whether it will be a 7 or 10,I'm losing 6, but 10 (field) -6 = +4 net profit

ELEVEN > 5-6 / 6-5 } I'm winning both,my Pass Line and my Field bet for a total of 10 = 10 = 20 net profit

TWELVE > 6-6 } I'm losing my Pass Line bet -10 bu I'm winning my Field for a overall net profit of +10 or +20,this depends from the variations of the table,some tables paying x2 while others paying x3


STAGE 2 } Place 30 units on Don't Pass Line

Let's see one by one every possible outcome:

TWO > 1-1 }  I'm winning +30

THREE > 1-2 / 2-1 } I'm winning with Craps +30 net profit

FOUR > 1-3 / 3-1 / 2-2 } I'm making my point on 4,so here what I have to do in order to create a risk-free profit is to buy 4 for 21,thus +9 on either case (7 or 4)

FIVE >  1-4 / 4-1 / 2-3 / 3-2 } Here goes the same as above,but instead of 21  for the 5 to come,I'm placing 25, thus a risk free profit of +5 either way

SIX > 1-5 / 5-1 / 2-4 / 4-2 / 3-3 } The same as above but instead of 25,I'm betting 28 to create a sure win of +2 net profit

SEVEN > 1-6 / 6-1 / 2-5 / 5-2 / 3-4 / 4-3 } I'm losing -30 from my Don't Pass bet and proceed to stage number 3 which will be explained later

EIGHT >  2-6 / 6-2 / 3-5 / 5-3 / 4-4 } It's the same situation like on 6, see above

NINE >  3-6 / 6-3 / 4-5 / 5-4 }  It's the same situation as with 5

TEN >    4-6 / 6-4 / 5-5 } It's the same as 4, see above

ELEVEN > 5-6 / 6-5 } I'm losing -30 from my Don't Pass bet and proceed to the third stage

TWELVE > 6-6 } This is a push (break even)

An alternative option for stage 2 is to bet Pass line odds instead of Buy and Place bets, if you prefer this way then bet 30 $ on Don't Pass and 10 $ to Pass line.

If your point is 4 or 10, bet 13 $ on the Pass odds for a risk free profit of 7$ (with 7) or 6$ with 4 or 10.
If your point is 5 or 9, bet 15 $ on the Pass odds for a risk free profit of 5$ (with 7) or 5$ with 5 or 9.
If your point is 6 or 8, bet 18 $ on the Pass odds for a risk free profit of 2$ (with 7) or 2$ with 6 or 8.

STAGE 3 }

Between 2 possible outcomes (P / DP) there are 8 possible combinations of results in a set of 3 consecutive outcomes:
1) P - P - P
2) DP - DP - DP
3) P - P - DP
4) DP - DP - P
5) P - DP - DP
6) DP - P - P
7) P - DP - P
DP - P - DP

To win 3 consecutive times you need dice setting or a great deal of luck!:-)
But what if we needed only 1 win out of 3 (1 win/2 losses) in order to be overall winners?!
On stages 1 & 2,there are certain outcomes which have negative influence on our bankroll,particularly 16 out of 36 times from the stage 1 we will be break even or -20
On stage 2, eight times out of thirty-six, our bankroll will be depleted by -30 or -20 with the alternative method.

So each and every time a negative outcome occurs we bet 20 or 30, depends from the lost amount of your last outcome, on Pass Line if your last lost bet was on Don't Pass or on Don't Pass line if your last lost bet was on Pass Line.
Remember the 8 combinations I've told you above? We are not looking for 3 consecutive,but only 1 out of 3!

What are the chances to get 1 out of 3? You have 7 chances against only 1 out of the total 8 combinations!
For example I lost 10 on Field plus 10 when my point didn't make it, now I'm betting 20  on Don't Pass / First roll 7,I'm losing -20

Second bet should go to Pass Line for 40 / Second roll 3, I'm losing -40

Third bet should be on Don't Pass for 80 units, third roll points to 4 and a few rolls after sevens out!

So let's calculate from the beginning, (-20 stage 1) + (-60 stage 3) = 80, deduct the net profit of our final win,which is 80 and we break even.
What we have done is to neutralize the minority negative outcomes (16 out of 36) of stage 1 in our favor.

Second example with stage 2, I'm losing 30 on Don't Pass line, first bet should go to Pass Line for 30 (or 20 by using the alternative way), remember the opposite of the last lost bet, first roll 7 and break even immediately!
We have recovered our initial bet from stage 2.

You may ask "why to use the combination of DP-P-DP or P-DP-P and not one of the other combinations?"
In theory,all of the 8 combinations have the same chances;
7 against 1,but from my experience I've seen long streaks of Passes and Don't Passes, therefore if you bet only on one side all the time, sooner or later you will get burned!
By sharing our bets on this pattern: P/DP/P or DP/P/DP we are heavy favorites to get just 1 win out of 3 consecutive outcomes!
Last but not least, I would like to mention that you must not underestimate the effectiveness of Hedge Parity System just because I'm offering it for free.
Perhaps, I wouldn't and you would still banging in the dark...!

I would like to hear your comments, thank you.