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[Mr J]

Some may call this an UPDATED version, some may not even care to look it over and some might be reading it for the first time. Every decent method (like this one) should be looked at for some tweaking. Its our GOAL to improve our methods!! The method is a bit boring/slow but if your unit size is large enough, well worth it (in my opinion).

Anyways, most of the time we will be betting on 2 numbers with this method (not a system). Sometimes, 0-1 numbers. All flat betting, no progressions please.

Your history board MUST be working and working correctly, you'll need it. Most boards hold the last 10-15 numbers, I PREFER the last 12 hit. We will be betting to COMPLETE a street within the last 12. (I'll use the last 12 as my example because that's what our boards here post). 

VERY, VERY often, a complete street hits in a short period of time (like 12 spins).
I did not say it always hits, try not to attack me.

Lets say we have the 17 & 18 hit within the last 12. We bet on the 16 UNTIL either a win or the 17 or 18 DROPS from the board, then stop betting on the 16. We do this style of betting for a max of TWO incomplete streets PER the last 12.

Sometimes there will only be one number to bet on and sometimes, NO numbers to bet. What if there are 3 or more, what is the tie breaker? I choose the two that will be on the history board the longest BEFORE DROPPING. Always choose the two that last the longest on the board !!

Lets say you got a hit on that 16....a couple spins later, the 18 drops off. Yep, bet on that 18 now. The 34 & 36 might be on the board, bet on the 35 UNTIL either a win or the 34 or 36 drops off. I'll give an example >>

6
31
2
21
20
27
11
33
35
21
22
00......What do we bet? The 32 (until the 33 drops off) and the 19 (until the 20 drops off). Next spin >>

3
6
31
2
21
20
27
11
33
35
21
22.....What do we bet? The 1 because the 2 will remain on the board longer than the 33 AND still bet the 19. A bit tricky but here is our next number (33) >>

33
3
6
31
2
21
20
27
11
33
35
21......What do we bet? Its now BACK TO the 32 and the 1. Sometimes that 19 will then hit and it ain't so funny but that's roulette for ya.

Pay attention to what just hit and what number dropped off, easy as pie.

Ken

[Proofreaders2000]

Test: Dublinbet Euro #1-Monday, August 26, 2013 @ 5:17am CDT US

*12 number revolving tracking, no more than two numbers bet at a time

...27,20,10,21 (trigger)

Bet #19:    1.) 34(x)-5               2.) 29(x)-5               3.) 3(x)-5

4.) 17(x)-5               5.) 3(x)-5               6.) 36(x)-5*new trigger number

Bet 19,35:    7.) 1(x)-10*               8.) 17(x)-10*trigger number change

Bet 35,2:    9.) 4(x)-10               10.) 17(x)-10               11.) 2(win)+170
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+100
====================================
Test: Celtic Casino 00 Wheel-Monday, August 26, 2013 @ 5:42am CDT US

*12 number revolving tracking, no more than two numbers bet at a time

...14,34,00,19,33,32 (trigger)

Bet #31:    1.) 0(x)-5               2.) 19(x)-5               3.) 6(x)-5

4.) 33(x)-5               5.) 5(x)-5*new trigger number active

Bet 31,4:    6.) 14(x)-10               7.) 17(x)-10               8.) 19(x)-10

9.) 10(x)-10               10.) 23(x)-10               11.) 1(x)-10

12.) 20(x)-10*trigger number change.  Bet 4,21:    13.) 9(x)-10

14.) 17(x)-10               15.) 9(x)-10*trigger number change

Bet #21:    16.) 1(x)-5               17.) 13(x)-5*trigger number change

Bet 21,15:    18.) 21(win)+170
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+35

[AMK]

Glad to see you getting down to business Mr J!

Very interesting aspect of  roulette which is not contemplated often, if at all?

The casino only shows you the last +-12 spins.

[AMK]

Congrates Proofreaders on the 22K you won recently!

This method might also help a lot : )

[Proofreaders2000]

Congrates Proofreaders on the 22K you won recently!

This method might also help a lot : )

I did not win 22K, Mr. J did.

[Mr J]

18K was a very decent day. ($100 units, don't forget that)

Ken

[Dane]

"VERY, VERY often a complete street hits in a short period of tme (like 12 spins)"
                                            Ken
Such a statement ought to be a challenge for every reader with a basic knowledge of probabilities. I do not have a maths degree; but I am able to play with my cheap electronic calculator with 12 digits. No. 1 might be absent in the first 12 spins: (36/37)^12 = 0.71979582014. By subtracting this result from 1 I find the probability, that this number comes within this 12 spins: 0.28020417986.
The chance that all three numbers in street 1-3 come in that period: 0.28020417986^3 = 0.02200005813.
By subtracting this result from 1 I find the probability, that the street is not complete:      0.97799994187.
There are twelve streets. So the chance that no street comes with all three numbers within 12 spins must be 0.97799994187^12 = 0.76571287166.

A street might not complete  itself in spins 2-13, in spins 3-13 .....One visit might last 105 spins. 105 = 93+12.
0.76571287166^93 = 0.00000000001. My cheap calculator has reached its limit. Are we losing every time within the 105 spin? The probability of 0.00000000001 suggests, that it does not happen "VERY, VERY often"! ACCORDING TO THIS KEN IS RIGHT!