Hi
It's roulette player, that system works, I tried it; it don't take long to win. Stay at 1 unit per street until you have to bet 6 street. In that case, double all the bets to insure a profit upon a win.
On a win, you balance increases according to the following formula. It's bet size multiplied by the number of empty spots on the board. Keep track of your last high balance anytime.
For example, if your last high balance was $50 and you current balance is $48, you are 20 units behind at 10 cents a bet. If you have to bet on 6 streets, you have 6 empty spots and in order to make a profit on a win, the bet size have to be 4 units. Your balance will increase by 4 multiplied by 6 empty spots for a total of 24 units. That brings you 4 units ahead.

If you don't understand, just try it for fun. Because sometime you bet on 3 streets and sometime on 6 streets, there is no fixed progression to follow. Use the formula to ensure a profit on a win.

Good luck

Quote from: Dane on November 16, 2014, 09:43:01 AM
I have seen all twelve streets within twelve spins!
If you continue long enough, you may see something similar and LOSE.
Losing with progression happens sooner or later.

You must have played a lot to see that. Also the 0 cannot be in that sequence. The 0 ends the progression right away because of the profit.

Roulette player

To reply to green guy
  First of all, you bet on streets, not on single numbers. With a 10 cents minimum starting bet on streets, you never have to bet that high. The highest total bet is $144 on 11 streets and the 0.
The only way to bet $14,400 is by starting at $10 minimum bet on 9 streets.The bet amount of the third step of the progression would be over the table limit. If there is something you don't understand, read my post again and practice for fun.

Good luck
Roulette Player

Hi
  It's roulette player again. Ihave a very powerful way to bet on street.
  It requires a $152.30 minimum bankroll with 10 cents minimum bet on streets.
It's a slow bankroll building strategy that requires a lot of patience
  The trigger is that you spin without betting and mark down in which street the number came.
From street 1 to 12 reading the board from left to right. You wait until the number shows up in 9 different streets in the previous 9 spin. It's hard enough to do because there is a lot of repeats before it happens.
  When you meet the condition of your trigger, you are on your way to a profit. You will see why.
You bet 10 cents on each of you 9 different streets and 10 cents on the 0 for a total of $1.00 Most of the time, you will win on the next spin because there is a big chance the number will fall in one of your selected streets. You make 20 cents profit on any street you bet on and $2.60 if the 0 hits.
  The only way to loose is if the number shows up in a new different street. You then go in the second step of your progression. You bet 70 cents on the steet where the ball landed in the last spin and also the same amount on each of the first 9 streets. So you bet on 10 streets and 30 cents on the 0 for a total of $7.30. At this point the chance of a repeat is even bigger and you win. You make 10 cents profit on any street and $2.50 profit if the 0 hits. Very rarely, you will loose as this point. If it's the case, you bet on the 11th different street where the number showed up. You go on the last step of your progression, you bet $12.70 on the last street where the ball landed in the last spin and also the same amount on each of the streets that you bet before and $4.30 on the 0 for a total of $144. I never seen a lost at this point because the odds of having the number falling in all 12 different streets in 12 consecutive spins is  1/18613.92623. I used a random number generator in Excel which generates many sets of spins per second and that never happened. The best I have seen is 11 differents streets in 12 spins and not very often. That's why you need the third step of your progression.
  So try it for fun and make sure you understand this strategy in full before trying it for real money. Good luck with this. I attach also the Excel file for that particular progression. All the formulas are in place for you, I did the hard part. You can change the amounts in each steps for bigger profit but you need a bigger bankrool. Right now my bankroll is $133 just playing the powerful pattern breaker strategy. I am only $20 away to have enough for playing this streets system.

Good luck
Rouletteplayer[smiley]aes/money.png[/smiley]

For your information, the statistic average is1 single loss in 32 games, 1 double loss in 1024 gamesand 1 triple loss in over 32,000 games.

Roulette Player[smiley]aes/evil.png[/smiley]

Hi;
Thanks for this ingenious idea, In order to be safe with that, I tried it with 32 patterns of RB. I look at the last 5 spins.I made a chart so I can check mark the patterns as they show up.But it take more time to cross all the patterns except the last one. The chance that the last pattern will show up during the next 5 spins is extremely small. So I use a 5 steps progression. I win almost immediatly by betting the opposite of the last pattern. Use the playtech French roulette because you can spin without betting and bet on the 0 at every step of your progression. If the 0 hits, it's a nice profit, you get paid 36 times your bet plus half of your bet on the color. It's only on the French roulette. I hitted the 0 twice with a profit of around $5 each time. I made $20 total profit today using that concept with a $1 minimun bet on colors. Every time I win a session I make at least $1.50 profit.
With a spread sheet like Excel, you can built up your progression, so you know how much to bet after a loss to finish with a profit after a win.

Wish good luck, works fine for me, make a constant profit, started with $13 and now I have $60, in less that a week just playing about 1 hour at a time. You have to be accurate and very patient to get your last pattern. Always bet the opposite color. That very important.
I will give you an example, let's say that your last pattern is Red, Red, Black, Black, Red, you bet on Black with the amounts in the first level of your progression. You win ya, game over, take your profit and start a new session or stop. You lose, bet on Black with the second level of your progression, you loose again, bet on Red, you loose again, bet on Red and if you loose again, bet on Black. If you loose the fifth step of your progression it's because the last pattern showed up. That's really unlikely to happen. When you have 4 or 5 patterns left to cross, there is a lot of 5 spins sequences for crossing a new pattern. There is a lot of repeats of patterns that you have already crossed.

Again good luck

It's worth a try with play money first

Roulette player

  In order to make some money on the long term playing roulette, you have win more than that you loose. I found a way to play where you win more often than you loose.

  Let's calculate the probabilities for dozens or row bets.

  First of all, because there is 3 dozens and 3 rows, everyone has a 33% chance of winning.
But if you bet on 2 dozens or rows at the same same time, you probability of winning is 66%.
You have a %66 chance to make a 1 unit profit, you understand so far.

  First, play the same 2 dozens or rows until you are 1 or 2 units behind.

  When you loose, you loose 2 units. Now if you go back 6 spins and write down in which dozen or row the wining number was, the chances are slim that in the next 6 spins, the winning number will fall in the exact dozen or row sequence as the last 6 spins. The chance are 1/3^6 or 1/729. That's the only way you would loose a 6 levels progression to recover your deficit. Your chance of recovering the deficit is 728/729 or around %99.86 a lot higher than %66. It's also recommended to bet on the 0 also at any stage of your progression.

  When you loose your starting bet and are behind, you can start a 6 levels progression. One thing to mention is that the more levels you have in your progression, the higher your bankroll has to be but the smaller the chance to loose all the levels in your progression.

  I will give you an example on how you place your bets on the progression. First of all, look at the pattern of the dozens that hit during the last 6 spins because we bet on dozens. The sequence might be from the last spin to the sixth previous spins. Low(1-12), medium(13-24), medium(13-24), low(1-12), low(1-12), high(25-36). You start at the first level of your progression and you bet the opposite of low which is medium and high, bet also on the 0, it's anice profit when hit. If you loose, you follow the sequence and bet the opposite of medium which is low and high. Simple but powerful. Whwn you win, you recovered your deficit and go to you starting bets again. Because you are only using your progression to recover a deficit, you chance of losing all the levels are very slim. So good luck and try it for fun first.

Roulette Player

Hi

I suggest an improvement to this strategy;

Trigger; Spin without betting until the number falls 3 times in a row in the same double street.
Bet all the other double streets with 2 units each and 1 unit on the 0 as an insurance.
If the 0 hits twice in a row and you didn't bet on hit, the bet size of your progression can go very high if you loose again.
If the 0 hits, it's a 25 units profit on the first level of your progression.

If you loose the first level of your progression, go to the second level; bet 16 units on each double streets and 3 units on the 0.

Most of the time, I won at the first level and just a few times I had to go at the second level of the progression. I never lost at that point by getting 5 number in a row in the same double street. A rare event.

There is a third level of my progression that I never had to go so far. I have it calculated in case of a lost at the second level.

On the third level, you bet 118 units on each double street and 20 units on the 0. If you loose this one you are extremely badlucky because the chance of losing again is extremely low.

At this point, you would get 6 numbers in a row in the same double street which is an extremele rare event.

  To be able to afford the progression, I have to go with 10 cents minimum bets. The minimum bankroll needed is $70.40 and I started with $100. Just by tryings strategies a bit at a time my bankroll is actually $108.50

That's are there is for now, and I hope you will try this improvement and keep checking because I have an extremely powerful strategy for streets that I will post pretty soon.

Good luck with this improvement

Hi
  Here is a simple even money betting strategy that's worked pretty good so far.
It's similar to the d'Alembert system.

  I recommend a minimum starting bet of 10 cents. Casino Tropez and Noble are 2 casinos offering 10 cents minimum bets on roulette.

  Here is how it works.

  You choose an even money bet; red, black, even, odd, high or low.

  Let's say you bet on red.

  You start at 1 unit, if you win you stay at 1 unit. When you loose, you increase the bet size by 1 unit. In this case, it will be 2 units. Let say you have lost 5 times in a row, your bet size is now 5 units.

  When you win, you decrease your bet size by 2 units, so you next bet will be 3 units.
If your bet size is 2 units, you go at 1 unit after a win. Even after a series of losses and a bet size of 12 units, your bet will always reach 1 unit eventually after a few wins, it don't matter the sequences of wins and loses.

  But the thing is that most of the time, you will be in deficit when you go back at 1 unit bet.
Wait until you win that 1 unit bet bet. Check you deficit which can be 7 units.

  Bet 7 units which is the deficit amount and if you win, you break even and restart at 1 unit.
If you loose, increase to 8 units. It don't' take a lot of wins to break even.

  The worst deficit I got has been 40 units that I recovered.
Always start at 1 unit when you break even or you are in profit.

It worths trying with play money first until you understand the mechanism of this system.
It's something new and unique that I designed.

Good Luck