Author Topic: PA's FOUR-NUMBERS BET.  (Read 10739 times)

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Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #15 on: February 21, 2016, 08:22:40 am »
Helo Crow,
that pw 14,25,36,already stale since,


Let me brag a little.
I, PA,
the first person, in this world to post the ,
how to bet the pinwheel....
and  he admitted,
 that I had revealed them to the public, for the first time.
He, himself never, tell anyone openly how to bet the pw.

But I must admit, its his original ideas, and a HG, indeeed.




Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #16 on: February 21, 2016, 08:25:45 am »
No,no,no
CROW,
this thread about how to bet 4numbers,
may u please STOP crowing,   about that Nono please???

People may think I am promoting that momo system!
Duh, no more no nono, and no more momo please!

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #17 on: February 21, 2016, 08:31:11 am »
Gentlemen,
If we look at the long list,
we may see, 4numbers, will hit almost equally,

but there will be variance,
meaning a 4numbers group, may sleep,
up to 45spins!!!

and then wake up...
of course some may say,
this a fallacy, a bull, and what's not.

No, a wheel, is still a wheel,
and we may see the
 law of probability,
 present himself here.
Avoid a long sleeping group,
and then bet them,
when they wake,
hoping they will hit whithin expectation,
will be the answer.

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #18 on: February 21, 2016, 09:29:10 am »

Gentlemen,
below a typical win/loss, that I observed.
If we are LUCKY, we will win FLATBET,
and since we not always lucky, we may only win if we could avoid losses,
since the wins, tend to CLUSTER.

Spielbank Hamburg
Tisch 0001
 
Gewinnzahlen:


LOSE
   LOSE
     LOSE
      LOSE
      LOSE
      LOSE
      LOSE
     LOSE
      LOSE
     LOSE
    LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
==WIN=1
==WIN=2
     LOSE
 LOSE
     LOSE
  ==WIN=3
     LOSE
 
     LOSE
      LOSE
     LOSE
     LOSE
      LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
      LOSE
     LOSE
  ==WIN=4
     LOSE
     LOSE
 
     LOSE
      LOSE
     LOSE
     LOSE
  ==WIN=5
==WIN=6
 LOSE
     LOSE
      LOSE
      LOSE
     LOSE
  ==WIN=7
     LOSE
 
      LOSE
     LOSE
      LOSE
     LOSE
     LOSE
     LOSE
 LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
 
    LOSE
     LOSE
     LOSE
     LOSE
  ==WIN=8
      LOSE
   
     LOSE
      LOSE
     LOSE
     LOSE
    LOSE
  ==WIN= 9
     LOSE
     LOSE
     LOSE
      LOSE
  LOSE
   LOSE
     LOSE
      LOSE
 ==WIN= 10
   ==WIN= 11
     LOSE
     LOSE
   LOSE
     LOSE
     LOSE
     LOSE
     LOSE
    LOSE
    LOSE
      LOSE
    LOSE
  LOSE
     LOSE
    LOSE
    LOSE
 ====WIN= 12
    LOSE
     LOSE
    LOSE
  LOSE
     LOSE
    LOSE
  LOSE
  LOSE
   LOSE
   LOSE
   LOSE
     LOSE
   LOSE
    LOSE
   LOSE
   LOSE
     LOSE
==WIN=13
      LOSE
     LOSE
    LOSE
   LOSE
   LOSE
     LOSE
   ==WIN=14   
   LOSE
   LOSE
   LOSE
     LOSE
    LOSE
   LOSE
   LOSE
    LOSE
     LOSE
 ==WIN=15 
  LOSE
     LOSE
  ==WIN=16   
   LOSE
   LOSE
 ==WIN=17   
    LOSE
   LOSE
      LOSE
   LOSE
   LOSE
==WIN= 18     
     LOSE
     LOSE
   LOSE
    LOSE
     LOSE
     LOSE
   LOSE
     LOSE
     LOSE
   LOSE
   LOSE
   LOSE
     LOSE
      LOSE
     LOSE
      LOSE
     LOSE
     LOSE
 
     LOSE
     LOSE
      LOSE
     LOSE
   ==WIN= 19
     LOSE
     LOSE
     LOSE
     LOSE
   ==WIN=20
 ==WIN=21
 
     LOSE
     LOSE
     LOSE
     LOSE
==WIN= 22
     LOSE
 LOSE
      LOSE
 LOSE
     LOSE
     LOSE
   ==WIN=23
     LOSE
      LOSE
 
     LOSE
     LOSE
     LOSE
 LOSE
     LOSE
      LOSE
      LOSE
     LOSE
      LOSE
      LOSE
     LOSE
     LOSE
 LOSE
==WIN= 24
     LOSE
 
     LOSE
     LOSE
     LOSE
    LOSE
     LOSE
    LOSE
     LOSE
     LOSE
     LOSE
     LOSE
      LOSE
==WIN=25
      LOSE
     LOSE
      LOSE
      LOSE
      LOSE
 LOSE
==WIN= 26
      LOSE
  ==WIN=27
     LOSE
  LOSE
     LOSE
      LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
      LOSE
  ==WIN= 28
      LOSE
     LOSE
      LOSE
  LOSE
      LOSE
   LOSE
   ==WIN=  29
     LOSE
      LOSE
     LOSE
     LOSE
     LOSE
      LOSE
     LOSE
    LOSE
     LOSE
  LOSE
   LOSE
  LOSE
    LOSE
    LOSE
   LOSE
     LOSE
     LOSE
      LOSE
     LOSE
    LOSE
    LOSE
     LOSE
     LOSE
     LOSE
     LOSE
   LOSE
==WIN=30
   LOSE
     LOSE
      LOSE
   LOSE
      LOSE
     LOSE
      LOSE
   LOSE
    LOSE
     LOSE
  ==WIN= 31   
   LOSE
   LOSE
   LOSE
     LOSE
  LOSE
 LOSE
   LOSE
   ==WIN=32   
     LOSE
      LOSE
      LOSE
    LOSE
     LOSE
    LOSE
    LOSE
     LOSE
    LOSE
   LOSE
      LOSE
      LOSE
    LOSE
   LOSE
   LOSE
    LOSE
    LOSE
     LOSE
   ==WIN=33 
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
     LOSE
    LOSE
     LOSE
      LOSE
     LOSE
    LOSE
   LOSE
     LOSE
     LOSE
   LOSE
    LOSE
   LOSE
     LOSE
    LOSE
     LOSE
     LOSE
 LOSE
     LOSE
    LOSE
  ==WIN= 34   
     LOSE
     LOSE
    LOSE
    LOSE
====
343x4=-1372LOSSES
34x36=1224 WIN

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #19 on: February 21, 2016, 09:51:02 am »
34/343=9.91%
343/34=10.08
STILL WITHIN EXPECTATION.


Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #20 on: February 21, 2016, 10:25:04 am »
THE ideas is 1/9=probability.
thus in long run,
the hit will be 1/9spins.
But variance, plus the GREEN,
will kill any mm.
Thus the answer lies in the ''variance MANAGEMENT''.

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #21 on: February 23, 2016, 10:32:38 am »

and now we see how  they clustered in 36spins

-------------
------------------

a0b1c1d2e1f2g0h1x1
a0b1c1d1e1f1g3h0x1
a0b0c1d1e2f1g1h1x2
a2b0c2d1e0f0g2h0x2-------------
==================
a2b2c5d5e4f4g6h2x6=36hit
=====================
------------------
a1b1c1d2e1f0g1h1x1
a2b0c0d0e3f0g1h1x2
a1b2c1d0e0f1g1h1x2
a0b0c0d1e2f2g0h3x1-------------
------------------
a1b1c0d1e2f1g2h0x1
a2b0c0d0e1f1g2h0x3
a0b2c3d0e1f0g2h0x0 zero=1
a0b1c2d1e1f0g0h1x3-------------
------------------
a1b0c1d1e1f0g0h2x3
a0b0c1d1e1f2g0h1x2  zero=1
a0b3c1d2e0f1g0h2x0
a4b2c0d1e2f0g0h0x0-------------
------------------
a2b2c1d0e0f0g2h1x1
a1b1c2d0e0f0g2h2x1
a1b1c1d0e1f2g1h1x1
a1b1c2d0e0f2g2h0x1-------------
------------------
a0b2c2d2e0f0g1h0x1 zero=1
a0b1c0d1e3f0g2h2x0
a0b3c0d2e0f0g2h2x0
a1b0c0d2e3f1g1h0x1 -------------
------------------
a2b1c0d1e1f2g0h1x1
a0b1c1d0e2f1g1h2x1   
a0b0c0d4e1f1g0h2x1
a0b0c2d2e2f1g0h1x0 zero=1-------------
------------------
a1b1c1d2e1f0g1h2x0
a1b0c2d1e1f2g1h1x0
a1b1c3d1e0f1g0h2x0
a1b1c3d0e1f1g0h2x0 -------------
------------------
a0b1c0d3e0f2g0h1x1 zero=1

Offline Blue_Angel

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Re: PA's FOUR-NUMBERS BET.
« Reply #22 on: February 23, 2016, 07:12:15 pm »
How do you select which 4 numbers to bet? Randomly??
''For after all what is man in nature?
A nothing in relation to infinity, all in relation to nothing, a central point between nothing and all and infinitely far from understanding either.
The ends of things and their beginnings are impregnably concealed from him in an impenetrable secret.
He is equally incapable of seeing the nothingness out of which he was drawn and the infinite in which he is engulfed.'' B.Pascal

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #23 on: February 24, 2016, 02:46:08 am »
How do you select which 4 numbers to bet? Randomly??

Hi BA,

The four straight =eurowheel.

group of...
a =-32--6-5--22
b=--15--27--24--18
c=--19--13--16--29
d=--4-36--33-7
e=--21--11--01--28
f=--2---30--20--12
g=-25-8-14--35
h=--17-23-31-3
x=--34-10-9-26-------

those four number =evenly spaced on the wheel, if zero ignored.


=====================
What the probability,
  how many 37spins-cycle,
 for all the "4-numbers group" ,
to have almost equal hit in how many 37-spins cycles?

eg. it take about 3000spins, for all single-number to have almost equal hit.

then how many 37-spins-cycle, to have all '4number',
 groups to have almost equal hit?

is it, say 3000/9=333 spins, or about 10cycles?

thanks.

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #24 on: February 24, 2016, 02:51:25 am »
Hi BA,
Using your  cycles betting strategy,

 we wait for, say a X cycles, wait for sleeper,
then bet the least hit 4-nimbers,
and bet them till they win?
With what progression?
Thanks in advance.

Offline Blue_Angel

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Re: PA's FOUR-NUMBERS BET.
« Reply #25 on: February 24, 2016, 03:31:59 am »
To be true I wouldn't select this way, also don't confuse my bet progression for EC's with 4 numbers.

Any EC includes 18 numbers which need much less time to average out than 4 numbers, in fact an EC needs 4.5 times less spins.

In other words, even if you had the required bankroll and proper table limits, you would not play for 27 consecutive cycles of 37 spins each!

Always keep in mind the extremes, that's how I have calculated.

However, betting straight up numbers provides an advantage which EC's don't, you can pick all cold (underperforming) or all hot (overperforming) numbers.

Cold and hot EC"s never contain all hot or every cold number, thus improved selection accuracy.

It seems that you cannot have one without the other, but what if we could combine both advantages into one selection??
How you might ask, the answer is by selecting 18 least shown numbers, those which appeared less than their probability (1/37)

Of course you would need also 18 times the bankroll of an EC, if for example you need 600 units in order to come on top even with the most extreme deviations, for singles you would need 10800 units for applying my progression in the same manner as on EC's.

The much higher bankroll is being compensated by equivalently higher profit, your lows will be lower and your highs will be higher.
Greater volatility doesn't affect the wins to losses ratio, this remains the same.
''For after all what is man in nature?
A nothing in relation to infinity, all in relation to nothing, a central point between nothing and all and infinitely far from understanding either.
The ends of things and their beginnings are impregnably concealed from him in an impenetrable secret.
He is equally incapable of seeing the nothingness out of which he was drawn and the infinite in which he is engulfed.'' B.Pascal

Offline Blue_Angel

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Re: PA's FOUR-NUMBERS BET.
« Reply #26 on: February 24, 2016, 04:12:42 am »
An EC contains 18 times more numbers than a single number but its payout is 35 times less.

A cycle for any EC is two spins with 72.97% probability of at least one hit, (72.97 * 1) - (27.03 * 3) = 72.97 - 81.09 = -8.12
(72.97 + 81.09) / 8.12 = 154.06 / 8.12 = 18.97% disadvantage

A cycle for any single number is 37 spins with 64.86% probability of at least one hit, (64.86 * 17) - (35.14 * 37) = 1102.62 - 1300.18 = -197.56
(1102.62 +1300.18) / 197.56 = 2402.80 / 197.56 = 12.16% disadvantage

The aftermath is that higher amount is not equivalent with higher disadvantage, neither more numbers with more advantage.
More important is the what than how much.
''For after all what is man in nature?
A nothing in relation to infinity, all in relation to nothing, a central point between nothing and all and infinitely far from understanding either.
The ends of things and their beginnings are impregnably concealed from him in an impenetrable secret.
He is equally incapable of seeing the nothingness out of which he was drawn and the infinite in which he is engulfed.'' B.Pascal

Offline BEAT-THE-WHEEL

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Re: PA's FOUR-NUMBERS BET.
« Reply #27 on: February 24, 2016, 04:51:36 am »
How do you select which 4 numbers to bet? Randomly??
that's the real problem.

Since every group will RTM in 'certain' CYCLES-of-37spins.

We may wait for a few 37spins cycle, say, Y cycles,

then look for sleeper group, and bet that group,

for X spins, hoping the sleeper will wake up, and , or cluster,
thus bring in profit.


Thus the question, is HOW, to determine the Y and X.
Thanks in advance.


Offline Blue_Angel

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Re: PA's FOUR-NUMBERS BET.
« Reply #28 on: February 24, 2016, 05:11:07 am »
that's the real problem.

Since every group will RTM in 'certain' CYCLES-of-37spins.

We may wait for a few 37spins cycle, say, Y cycles,

then look for sleeper group, and bet that group,

for X spins, hoping the sleeper will wake up, and , or cluster,
thus bring in profit.


Thus the question, is HOW, to determine the Y and X.
Thanks in advance.



My approach in the game is very different than what you present.
''For after all what is man in nature?
A nothing in relation to infinity, all in relation to nothing, a central point between nothing and all and infinitely far from understanding either.
The ends of things and their beginnings are impregnably concealed from him in an impenetrable secret.
He is equally incapable of seeing the nothingness out of which he was drawn and the infinite in which he is engulfed.'' B.Pascal