THis is a quite long post, please read carefully not reaching quick conclusions.

Let's talk about a specific bac method derived from an old craps interesting system very few people know about.

**Craps system**

The system works against the probability that four consecutive craps players will make 4 or more passes each (pass=wins on the pass line bet).

Whenever each player reaches the four pass level, we are not interested anymore on what happens next about this shooter, we'll wait the next shooter.

Thus we'll place our bets only on the don't pass line.

When such thing will happen we'll lose our entire bankroll.

The betting multilayered progression is:

$10, $20, $40, $80

$20, $40, $80, $160

$30, $60, $120, $240

$40, $80, $160, $320

Total bankroll at risk = $1500

Anytime we lose a bet we'll step forward the next progressive amount, when we win a bet at any level we'll go back to the first original progressive line ($10, $20, etc)

To lose the entire bankroll we need a 16-consecutive losing sequence, and this thing surely will happen but at a very very low degree of probability.

In any case, even when this nasty thing happens, we could be in the positive field as it's likely we have accumulated many wins on the more likely positive situations.

Comments

You can notice that wins made on a given level will cancel just the previous same level losing bets.

For example, after getting 6 losing hands in a row followed by a win ($80 bet on second level), we are still behind $130 that in a way or another must be recovered by the first level progression.

Actually only the first level progression will make us pure winners, subsequent levels diminish the deficit just by small loss percentages.

Per each level we're proportionally win $10, or recover from the overall losing situation respectively $20 (second level), $30 (third level) and $40 (final level).

It's a long waiting process as it could take several rolls to produce either a single win or a single loss. Not mentioning that placing progressive don't pass bets will arise other players hostility.

Who gives a fk about other players, but prolonging too much our betting frequency is a bigger issue.

Moreover, it's quite difficult to accept the idea that after a $450 loss (two full progressions that went wrong) the system dictates to wager just $30 (first step of the third progression level).

Believe it or not, the probability such system will bring us in the positive side are quite interesting, even though we know that sooner or later s.hit will happen. (but even in this scenario we could be winners).

Finally it's obvious to state that craps is just made by endless independent random successions.

Therefore, odds to lose our entire bankroll are nearly 1 : 65.536.

**Modeling this system to baccarat**

Good news are that baccarat isn't an independent and random game, moreover is a finite card game.

Bad news are that each bet isn't following precise probability percentages, as a strong dynamic probability could affect the outcomes in either a positive or a negative way.

And of course the irregular asymmetrical BP probability and the constant asymmetrical payment will make a huge role along the way.

Nonetheless, I see a common important trait between our strategies and this craps method inventor: when considering gambling games, after a cutoff point is surpassed and incorporated into a finite field, we shouldn't be interested anymore to register the results.

In addition, notice the important parameter assumed by the craps expert: he or she didn't want to challenge a single player getting a 16-passes streak in some way, he preferred to split his/her strategy by spreading it on consecutive different limited random sources.

In a nutshell, the probability a single craps shooter will get a 16-pass streak is higher than the probability that four distinct consecutive shooters will get 4 passes each.

Scientifically speaking this craps method inventor indirectly doubted about the place selection and probability after events tools confirming or not the perfect randomness of the results.

Back to baccarat.

We have to choose the procedures to transfer at baccarat those craps ideas.

First, we should define any single craps shooter as a first B or P appearance.

Any new shooter won't act as long as a new BP shift come out (an exception is about the very first B or P result).

Therefore we need a 5 same streak apperance happening on either side to lose our first level progression. (First hand is just a non-bet signal to classify a new player)

Say the first hand is B. Now we'll play against a B streak of 5+, stopping if a 5-streak happened.

The same about P. And so on.

In a word, we're challenging every shoe dealt to produce back to back 5+ streaks happening consecutively and we need four consecutive 5+ B/P streaks to lose our entire bankroll.

Notice that at craps each sevening-out shooter will make a end of his/her winning streak, now at baccarat we'd classify as a new shooter the next BP shift.

Even though we're classifying mere BP results (and you well know there are greater better random walk lines to wager into) the probability to get four or more 5+ B or P consecutive streaks is almost not existent.

Now we know that the losing bankroll probability won't happen at humanly considered ranges.

But wait.

In order to get an edge, we need that first level progression will get more wins than expected. In poorer word that streaks are cumulatively not reaching the 5+ degree level.

Not mentioning that every B result is burdened by a 5% vig.

If a simple B/P consecutive winning streak pattern should be affected by a lack of proper randomness and/or affected by the bac rules, is any distinct back to back B or P succession following more detectable patterns?

A thing we'll consider on the next post.

as.