Author Topic: Why bac could be beatable itlr  (Read 60390 times)

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Offline alrelax

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Re: Why bac could be beatable itlr
« Reply #255 on: January 28, 2021, 12:48:39 pm »
Let's compare baccarat with two casino games that have demonstrated to get players an edge.


From one part certain very rare math distributions will favor B or P, but we know this feature isn't exploitable.

Yet, itlr key cards will affect the real outcomes not in the way studied so far (one side should be mathematically more likely than the other one) but in term of gaps probability intervening between two different situations not belonging to B and P.


as.

Asym,

It is exploitable as long as it is happening.

The confusion, frustration and of course the disbelief comes to players when they attempt situation after situation after situation. 

But it is definitely exploitable.  Small sections, sometimes and no rhyme or reasons in so many words as to when those do appear.
 
My Blog within BetSelection Board: https://betselection.cc/alrelax's-blog/

Played well over 33,770 shoes of baccarat since I started playing at B&M USA casinos.

"Don't say it's a winning hand until you are getting paid for it".

Played numerous properties in Las Vegas, Reno, Southern California, Atlantic City, Connecticut, South Florida, The South/Southeast as well as most areas of The Midwest.

Baccarat, actually a mixture of Watergate, attacking the Gotti Family and the famous ear biting Tyson fight leading to disqualification and a near riot.  Bac has all that more.
 
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Offline alrelax

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Re: Why bac could be beatable itlr
« Reply #256 on: January 28, 2021, 01:04:56 pm »
A baccarat shoe is formed by a finite amount of two-card 'states', that is high card situations math  favoring remarkably the side where the highest point will fall at. 



Now we take a step further.
We want to discard some A or B events according to a precise plan. If the game is perfect randomly dealt and/or perfect flawless at any spot, the resulting registration shouldn't be affected by any means, and actually itlr A=B yet.
It remains to assess the very important AB distribution that should be insensitive to our place selection artifice that must confirm the randomness. That is increment steps of A or B. 

A simple combinatorial analysis show that whenever some spots are not included in our chosen data, some patterns are more likely than others. That is we can get a sure edge over the house.
I mean a great edge, not that miserable bj card counting edge.


as.

Asym,

And that is exactly correct, a GREAT EDGE over the house and on your side.

However, almost all players will outdo themselves as this is only possible to achieve when in a certain mind frame. 

There are several different distributions of the cards that can be defined.  But the problem arises most all the time as not holding any pattern or trend whatsoever to follow with or against.  So win one, lose one or win a few and lose a few, etc. 

Players believe they can affect the registrations of the winning or losing hands into their winning wagers.  But in reality they cannot.  The players fuel their own downfall because they believe themselves and their new magical powers they convince themselves they founded at the table.  So, when someone is able to define what caused him to win and that just plays and plays upon themselves until they really do believe they have finally founded the Holy Grail, etc., etc.  even experienced players repeat that exact same scenario, session after session after session after session.  They will not admit it, but an outside person can spot it if you truly take the time to look around the table and watch.     

There are several, probably 4 or 5 registrations (if we are talking the same things) that come about and they are so opposite of each other and so impossible to blanketly predict or expect, etc., a player cannot wager systematically hand after hand, section after section, wager using all of them together and come out ahead.   
My Blog within BetSelection Board: https://betselection.cc/alrelax's-blog/

Played well over 33,770 shoes of baccarat since I started playing at B&M USA casinos.

"Don't say it's a winning hand until you are getting paid for it".

Played numerous properties in Las Vegas, Reno, Southern California, Atlantic City, Connecticut, South Florida, The South/Southeast as well as most areas of The Midwest.

Baccarat, actually a mixture of Watergate, attacking the Gotti Family and the famous ear biting Tyson fight leading to disqualification and a near riot.  Bac has all that more.
 
EMAIL: Betselectionboard@Gmail.Com

Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #257 on: January 31, 2021, 08:18:26 pm »
Definitely true what you have posted Al, but in the process of getting an edge we must discard some shoes from the play as no section or no portion of some single shoes will get the room and/or the possibility to get valuable card combinations to bet into.

For example, when almost every 8 and 9 had shown and no longer available, next outcomes will be affected by a huge degree of volatility, say a huge degree of randomness.

No 8 or 9 available = more hands will involve the use of six cards, the highest degree of randomness.
And it's not a coincidence that ties are well more likely when hands got to use six cards.

It could happen that very talented players might get the best of it by ascertaining valuably those rare deviated shoes, we prefer to bet toward the remaining more predominant part of shoes where an event A is a long term favorite over the counterpart B.
After vig, of course.

as.
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Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #258 on: January 31, 2021, 08:42:33 pm »
Imo, it's of paramount importance to know that the baccarat model can be beaten ONLY in selected circumstances capable to enhance the probability to get a more likely card distribution.

We can't beat every shoe dealt and let alone we can't think that those deviated shoes will get us a greater amount of wins than the more likely losing counterparts.

Either we discard from our play the more likely world or we discard those very deviated shoes.
I guess we'll do better by adopting the latter line.

Btw: since this fkng covid-19 won't get away so fast, we're ready to set up an online team to teach the world how things really work at baccarat so anyone can see for free how to win at this game.
Without utilizing those ridicolous idi.o.t fkng utube videos.
 
as.
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Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #259 on: February 02, 2021, 11:25:17 pm »
Comparing our live shoes dataset with either pc simulated shoes and deeply shuffled manually shoes, we've seen that the former category differs from the latter by two specular probabilities:

- the probability to get long streaks (it was demonstrated to be greater at live shoes)

- the probability to get long "chopping" patterns (it was demonstrated to be lower at live shoes)

That doesn't mean that live shoes tend to produce more streaks than singles, just that our significance statistical tools informed us that after some cutoff points were surpassed, live shoes need a lesser amount of hands to form, say, an 8 streak or conversely a greater amount of hands to produce an 8 chopping pattern.

Given the relative mediocrity of our live shoes sample compared to the endless pc simulated and self manual shuffled shoes samples, we were interested to find whether such peculiarity would be present in every live casino shoe registration.
And we were impressed to get an affirmative answer. (Even more when other scholars have found the same feature).

In essence, many live shoes are affected by a bias acting at various degrees and we think the reason belongs to the difficulty to shuffle key cards in a proper randomly fashion.

Of course not every live shoe is shuffled badly and there's always the probability that a biased shoe will produce seemingly "random" results.

Since live shoes tend to produce a proportional lesser amount of long chopping lines and a greater amount of long streaks than expected, we might set up a betting plan that doesn't involve the short chopping situations and the streaks that surpass a given lenght.
Now we are playing at a restricted field, from one part getting rid of many short single sequences and from the other one by considering streaks after x and up to y.

Nonetheless, only a derived AB plan could further restrict the variance as it gets rid of many unpolarized situations enhancing the uncertainty.

as.
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Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #260 on: February 07, 2021, 11:35:07 am »
Given the astounding asymmetrical and finite features working at baccarat, the only possibility to lose is whenever the card distribution remains so hugely polarized for long that no betting plan could get the edge we're looking for.

Curiously those last are the bread and butter situations that recreational players are looking for: a kind of endless jackpots, in the meanwhile trying to survive into the most likely non-jackpot successions.

Actually I have nothing against it: in some casinos, cards are so badly shuffled that peddling a long streak gets a way larger probability than expected.
Such casinos use a same shoe that is manually shuffled very quickly only by halves.

The problem is that most casinos where some serious money might be wagered at, apply more deep "independent" shuffles.

Anyway and without any shadow of doubt, real advantage players know that the average probability to get a given event along certain portions of the shoe is well greater than expected.
Not a serious threat for casinos as the remaining 99.9% of players (quite probably more than that) will be eager to get their money separated from them.

That means that per every shoe you'll decide to play at, the more you want to be right higher will be the probability to be wrong. 
Especially if you'd force the probability to be right by adopting a betting progression without a proper and very diluted bet selection.

Low and high asymmetrical distributions can't get us any edge, our edge comes out from more likely moderate asymmetrical distributions.
The 'low' world could be easily get rid of by starting our registration after a given deviation had started to appear.
The 'high' world must be restricted by trying to put a stop by wagering a very limited amount of bets up to a point.

Think that in order to get an edge itlr, we must prove that after adopting a given discontinued registration (limited random walks), there will be a finite number of either increments or decrements not corresponding to the expected values.


as.
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Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #261 on: February 11, 2021, 11:09:19 pm »
THis is a quite long post, please read carefully not reaching quick conclusions.

Let's talk about a specific bac method derived from an old craps interesting system very few people know about.

Craps system

The system works against the probability that four consecutive craps players will make 4 or more passes each (pass=wins on the pass line bet).
Whenever each player reaches the four pass level, we are not interested anymore on what happens next about this shooter, we'll wait the next shooter. 

Thus we'll place our bets only on the don't pass line.
When such thing will happen we'll lose our entire bankroll.

The betting multilayered progression is:

$10, $20, $40, $80

$20, $40, $80, $160

$30, $60, $120, $240

$40, $80, $160, $320

Total bankroll at risk = $1500

Anytime we lose a bet we'll step forward the next progressive amount, when we win a bet at any level we'll go back to the first original progressive line ($10, $20, etc)

To lose the entire bankroll we need a 16-consecutive losing sequence, and this thing surely will happen but at a very very low degree of probability.
In any case, even when this nasty thing happens, we could be in the positive field as it's likely we have accumulated many wins on the more likely positive situations.

Comments

You can notice that wins made on a given level will cancel just the previous same level losing bets.
For example, after getting 6 losing hands in a row followed by a win ($80 bet on second level), we are still behind $130 that in a way or another must be recovered by the first level progression.

Actually only the first level progression will make us pure winners, subsequent levels diminish the deficit just by small loss percentages.
Per each level we're proportionally win $10, or recover from the overall losing situation respectively $20 (second level), $30 (third level) and $40 (final level).

It's a long waiting process as it could take several rolls to produce either a single win or a single loss. Not mentioning that placing progressive don't pass bets will arise other players hostility.
Who gives a fk about other players, but prolonging too much our betting frequency is a bigger issue.
Moreover, it's quite difficult to accept the idea that after a $450 loss (two full progressions that went wrong) the system dictates to wager just $30 (first step of the third progression level).

Believe it or not, the probability such system will bring us in the positive side are quite interesting, even though we know that sooner or later s.hit will happen. (but even in this scenario we could be winners).

Finally it's obvious to state that craps is just made by endless independent random successions.
Therefore, odds to lose our entire bankroll are nearly 1 : 65.536. 

Modeling this system to baccarat

Good news are that baccarat isn't an independent and random game, moreover is a finite card game.
Bad news are that each bet isn't following precise probability percentages, as a strong dynamic probability could affect the outcomes in either a positive or a negative way.
And of course the irregular asymmetrical BP probability and the constant asymmetrical payment will make a huge role along the way.

Nonetheless, I see a common important trait between our strategies and this craps method inventor: when considering gambling games, after a cutoff point is surpassed and incorporated into a finite field, we shouldn't be interested anymore to register the results.

In addition, notice the important parameter assumed by the craps expert: he or she didn't want to challenge a single player getting a 16-passes streak in some way, he preferred to split his/her strategy by spreading it on consecutive different limited random sources.
In a nutshell, the probability a single craps shooter will get a 16-pass streak is higher than the probability that four distinct consecutive shooters will get 4 passes each.
Scientifically speaking this craps method inventor indirectly doubted about the place selection and probability after events tools confirming or not the perfect randomness of the results.

Back to baccarat.

We have to choose the procedures to transfer at baccarat those craps ideas.

First, we should define any single craps shooter as a first B or P appearance.
Any new shooter won't act as long as a new BP shift come out (an exception is about the very first B or P result).

Therefore we need a 5 same streak apperance happening on either side to lose our first level progression. (First hand is just a non-bet signal to classify a new player) 
Say the first hand is B. Now we'll play against a B streak of 5+, stopping if a 5-streak happened.
The same about P. And so on.

In a word, we're challenging every shoe dealt to produce back to back 5+ streaks happening consecutively and we need four consecutive 5+ B/P streaks to lose our entire bankroll.
Notice that at craps each sevening-out shooter will make a end of his/her winning streak, now at baccarat we'd classify as a new shooter the next BP shift.

Even though we're classifying mere BP results (and you well know there are greater better random walk lines to wager into) the probability to get four or more 5+ B or P consecutive streaks is almost not existent.
Now we know that the losing bankroll probability won't happen at humanly considered ranges. 

But wait.

In order to get an edge, we need that first level progression will get more wins than expected. In poorer word that streaks are cumulatively not reaching the 5+ degree level.
Not mentioning that every B result is burdened by a 5% vig.

If a simple B/P consecutive winning streak pattern should be affected by a lack of proper randomness and/or affected by the bac rules, is any distinct back to back B or P succession following more detectable patterns?

A thing we'll consider on the next post.

as. 
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Offline alrelax

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Re: Why bac could be beatable itlr
« Reply #262 on: February 11, 2021, 11:27:13 pm »
1-3-2-6 and then if successful, use 4 or 6 units out of the 12 win and adhere to the 1/3-1/3-1/3rd I have discussed.  Or, use a 2-4-6 in the beginning and then devote 4 or 6 units out of the win and pull down subsequent wins, etc.
My Blog within BetSelection Board: https://betselection.cc/alrelax's-blog/

Played well over 33,770 shoes of baccarat since I started playing at B&M USA casinos.

"Don't say it's a winning hand until you are getting paid for it".

Played numerous properties in Las Vegas, Reno, Southern California, Atlantic City, Connecticut, South Florida, The South/Southeast as well as most areas of The Midwest.

Baccarat, actually a mixture of Watergate, attacking the Gotti Family and the famous ear biting Tyson fight leading to disqualification and a near riot.  Bac has all that more.
 
EMAIL: Betselectionboard@Gmail.Com

Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #263 on: February 18, 2021, 11:55:14 pm »
That's my 1k post on this wonderful site, congratulations to this forum upgrade.

@Al: 1-3-2-6 betting approach is useful as long as we are sure we can get an edge by flat betting, thus it's just a profit scheme enhancer (more WW situations than WL spots, etc)

Win frequency

Most part of money won by casinos derives from an improper W/L assessment and not for the math advantage we must endure.
Take the 16-step betting scheme I was talking about above.

Say that after 8 bets that went wrong (that is a -$450 deficit) the plan dictates our next bet will be $30.
Basically we're betting only the 6.66% percentage of what we're losing.
Now tell me whether a -$450 losing player will place just a fkng $30 wager.

Actually that's the wisest move he/she can take (as long as we know to play with an advantage).
First, a huge deficit must be compensated slowly as the probability to get a quick kind of symmetrical WL ratio is very low, secondly risking too much money in order to get a fast recover will expose us to the fatal risk of losing our entire bankroll.

When our random walks-whatever running- reach some extremes, the probability to get a "balanced" or more likely status is generally small and quite diluted.

To get a vulgar example of this, think about how many times we'll face a BBBBBBBB sequence (we'd bet P every hand causing us eight losses) suddendly followed by a specular PPPPPPPP or PPPPPPP pattern (again we always bet P).
Yes, it could happen, the same way slots can give you a kind of little jackpot.

Actually, all baccarat systems rely upon the probability that things must change in player's favor with no regards about the important time factor (number of shoes dealt, or better sayed, number of hands really wagered).

Let me present a real example of this.

Several years ago, a bunch of japanese players joined one of the Vegas HS baccarat room, they managed to fill all the table seats.
A leader instructed all his peers to bet the same side he had chosen to wager and btw all bet were made at the maximum limit.
Things went out that a couple of consecutive shoes produced a very strong Player predominance, at the end casino lost the like of $1.4 millions.

Such players kept playing baccarat for the next few days of their trip, and not surprisingly they'd lost some of the money won, anyway they quit Vegas as huge overall winners.

The question is about how many days this casino had managed to recover such a loss: many.
Despite of the sure math advantage, the casino needed several days to recover that loss and we are talking about players getting a win by playing the strongest uphill percentages.

Back to the 4 step x 4 step betting sequence.

At baccarat and differently to craps, when utilizing a proper bet selection the probability to be wrong 16 times in a row is not existent at all, and I'm not referring to the probability to cross a 16 streak in various shapes.

The main probability to get wins is about the first 4-step wagering, subsequent steps will just proportionally raise the probability to recover previous losses.

And we can safely assume that even adopting a "risky" progressive approach, the probability to lose our 150 unit bankroll is almost zero.

I'll prove this on my next post.

as. 
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Offline KungFuBac

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Re: Why bac could be beatable itlr
« Reply #264 on: February 19, 2021, 04:06:09 pm »
Congrats AsymBacGuy on your 1000 post above.  :applause:

This is a good thread /subtopic and I like the analogy with the outcomes profile in craps. I think you will agree there are many similarities when comparing craps to bac. A couple huge differences too(as u point out one above re: dependence)

I look forward to  your next post in the series.

Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #265 on: February 22, 2021, 10:57:24 pm »
Congrats AsymBacGuy on your 1000 post above.  :applause:

This is a good thread /subtopic and I like the analogy with the outcomes profile in craps. I think you will agree there are many similarities when comparing craps to bac. A couple huge differences too(as u point out one above re: dependence)

I look forward to  your next post in the series.

Thanks KFB! :-)

Yep, besides the dependency factor, I totally agree that craps and baccarat tend to work by similarities.

When a craps shooter bet the pass line he/she has 2:1 odds to win as there are 6 ways to form a winning seven and 2 ways to form an eleven (8 winning ways); a sudden loss comes from rolling a deuce (1 way), a three (2 ways) and a twelve (1 way) totaling 4 ways to lose. 2:1.
The casino's ploy to reduce a sure math edge for the don't pass bettor derives from transforming a losing twelve for the pass bettor to a push.

After this very first roll not producing a sudden win or loss, the pass line bettor is underdog to win as in relationship of the number established his/her odds to win are 5:6 (six or eight), 4:6 (five and nine) and 3:6 (four and ten).

Thus basically there are two distinct asymmetrical probabilities to get outcomes on either pass or don't pass sides: a sudden win getting 2:1 (pass line) and 3:8 odds (don't pass line); after that the don't pass line is hugely favorite to win at various degrees.

In essence, the above mentioned multilayered betting scheme relies upon the difficulty to first roll sevens and elevens in series greater than 4 per each consecutive shooter.
Of course it could happen that such 7s/11s will be mixed with number repeaters, anyway it's very very very very unlikely to get four consecutive players winning 16 rolls in a row without showing at least one or a couple of immediate 7/11 wins.

At baccarat from one part math propositions are more intricated to grasp, from the other one there are additional factors that might orient our bet selection.

We know that "sudden win or loss" are determined more likely by the fall of strongest key cards (8s and 9s) on the initial two initial cards of a given side, then the side getting the higher two initial card point is hugely favorite to win the hand.

Of course such probabilities are symmetrical (thus undetectable) but the finiteness of the shoe and the key card liveness or shortage along with simple statistical features will help us to define how much such factors are going to produce valuable deviations from the expected line.
As there's no way a perfect key card balancement is going to act along any shoe dealt (even though many not key card situations can produce strong deviated spots), we can infer that most part of random walks are not going to form back to back outcomes totally insensitive to the previous card distribution.

Simply put, the vast majority of shoes dealt are surely affected by a kind of finite dependency deviating from the expected values.

Tomorrow practical examples about that.

as. 
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Offline KungFuBac

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Re: Why bac could be beatable itlr
« Reply #266 on: February 25, 2021, 04:42:56 pm »
Thx Asymbac

Your statement above:
"...As there's no way a perfect key card balancement is going to act along any shoe dealt (even though many not key card situations can produce strong deviated spots), we can infer that most part of random walks are not going to form back to back outcomes totally insensitive to the previous card distribution..."

In the following example: How is your decision tree designed? In other words what trumps all the thoughts/ideas running through your mind if you were required to wager the very next hand following: P:89 B:44 Bwins; P:98 B:35 Bwins.  So obviously P is getting the cards it wants, yet B is winning with the cards it wants/needs. What say you?

I know there could be dozens of things to consider. Im asking what would typically be at the top of your list that would over rule all the lower level considerations on the decision tree.

Thx in advance,

Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #267 on: February 26, 2021, 12:04:43 am »
Hi KFB!!

I like very much your "decision tree" words.

First, let's consider your example.
Obviously a banker bettor would be very happy to win those hands and conversely a player bettor quite disappointed.
Nonetheless itlr such specific spots are EV- for Banker bettors and EV+ for Player bettors.
As a standing 7 on P side is favorite to win (and payed 1:1) whereas a winning natural on B side is payed 0.95:1.

If you were to know exactly the first card of the next hand, which side would have you bet?
I guess Player's.
And naturally whenever an asymmetrical hand do not come out within a range validly surpassing the math expectancy, no Banker bet is EV+. 

Since we can't know how cards are distributed but we surely know the average card distribution impact, definitely some ranges of distribution will be slight more likely than others.
The more we're going deeply in the process of classifying the actual results, better will be the long term profitability.

Let's take a very simple approach made on big road.

We'll bet toward getting at least one of the 1-1, 1-2, 2-1 patterns at Banker side, thus our play won't be affected by the vig as our bets will be placed only at Player side.
Anytime a 1 or 2 comes out at B side, we'll bet toward those three patterns. We'll stop the bet until we'll get one unit profit per shoe by utilizing a steady 1-2 progression.

Of course itlr we'll be in the negative as B>P then B1 < B2 < B3+.

That's ok.

But how many times we'll get two or more consecutive set of losses without getting at least one winning pattern we're looking for?

as.
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Offline KungFuBac

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Re: Why bac could be beatable itlr
« Reply #268 on: February 27, 2021, 05:13:39 pm »
Thx  AsymBacGuy for your elaborate response.

This is good: "And naturally whenever an asymmetrical hand do not come out within a range validly surpassing the math expectancy, no Banker bet is EV+."


"...We'll bet toward getting at least one of the 1-1, 1-2, 2-1 patterns at Banker side, thus our play won't be affected by the vig as our bets will be placed only at Player side.
Anytime a 1 or 2 comes out at B side, we'll bet toward those three patterns. We'll stop the bet until we'll get one unit profit per shoe by utilizing a steady 1-2 progression.
. .."


     Can you clarify re: stop the bet until one unit of profit per shoe...etc.

Thx

All The Best,

Offline AsymBacGuy

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Re: Why bac could be beatable itlr
« Reply #269 on: March 02, 2021, 11:09:23 pm »
Thank you KFB!!

Any baccarat player needs to find the spots where his/her bets are EV+ as the idea to restrict the negative expectancy by utilizing some kind of progressions or balancement factors are completely wrong both theoretically and practically.
I could be the best disciplined person in the world but a EV- bet remains a EV- bet.
We can't do anything about that mathematically, yet we can do a lot statistically.

Along any BP finite succession, whatever considered, some spots are EV+ at the Banker side and some spots are EV+ at Player side.
This way of thinking totally contrasts with the common concept that every bet is EV- no matter what.

At baccarat, 91.4% of the outcomes are simply following a coin flip probability, just 8.6% of the results are Banker oriented.
Those coin flip situations mainly rely upon the key card distribution, they are not perfect independent spots, yet one side is payed 1:1 and the other one 0.95:1.

Thus a slight dependent coin flip probability tends to provide many "limited" random walks (as key cards are limited both in number and distribution) where a given event is more likely than the counterpart.
Just on 91.6% of the results, of course.

The remaining 8.6% of the outcomes hugely favor Banker side, providing a neutral card distribution, meaning that third cards must belong to a "random" world where each rank is equally probable.

Really?

No fkng way.

A baccarat shoe is formed by a sure asymmetrical rank card distribution, we can't estimate precisely which cards will help a side or not, but we can get a clearer picture whenever we'll consider many kind of  back to back probabilities as the asymmetrical features will dilute more and more up to the point where a reversed strenght will take place.
Even though it could happen to disregard the fact that one side is math advantaged over the other one.

Tomorrow about the B single-double attack.

as. 
Next to edge sorting it's me