sorry for late reply, I was washing my hair.

Yes, you would just bet 2, so 9 numbers.

Progression is anyone's guess - experiment with it

BW

A      B

4   5
5   4
6   1
2   6
3   2
6   2  Column B is 1-0 up here
6   4  Column A has equalised! 1-1
5   1
4   4
5   6
2   4
6   2
2   3
6   5
5   2
5   3  2-1 to A
4   5
3   6
3   4  3-1
3   2
5   3
2   4
5   5
1   4
3   1
1   2
5   3
1   6
2   6 3-2
5   2
6   2 3-3
6   1 4-3
4   3
3   5
1   1
1   5 5-3
1   5 5-4
6   6
6   4 6-4
1   3
3   5
1   6
1   5 7-4
6   1
5   4
2   3 7-5
5   3
2   3
6   5
1   6

7-5, a difference of 2.

Never seen more than a difference of 3 in a 100 spin session.
Just wish there was a secure bet selection for this

Hi,

I've been looking at double streets in columns and how each side
tends to distribute very evenly.

I'll explain.

List the DS's in 2 columns like this:

A B
2 4
3 1
5 2
5 1   etc

So all I was looking for were the repeat one each side,
doesn't matter if they repeat once, twice whatever.

In each 100 spins, I noted how many repeats were on each
column, A and B.

Here are the results:

8/8
7/5
9/10
5/6
6/5
7/6
6/4
5/7

There were maybe another 500 spins where
there were no column had more than 3 more
repeats within 100 spins.

So how can we take advantage of this, that's the
question!

One way is to wait for one column to get a repeat, and then
bet the other column. The longest gap was 19 doing
this.

Any suggestions if there's any other way to exploit this
apparently nice distribution here?

Cheers[size=0.85em][/size]

This is a system based on splitting the layout into 4 sets of 9 numbers.

1-9
10-18
19-27
28-36

We mark them 1,2,3,4

Then as they appear, we note them in a 2x3 grid like this one for example:

2 4
3 3
2 3

Now this is similar to another system I posted here a while back, but groups
of 9 seem to behave better so give this a whirl.

Basically you wait for the first number to show

2

Then , going horizontally, left to right you bet for a repeat, or double, or twin.

2 3

No win, carry on - noting that you bet again for 2, because you are going for a vertical twin.

2 3
4

Still no joy, now bet numbers 3 and 4 = 18 numbers in total

2 3
4 4

win, start a new grid from scratch.

That's basically it. Don't count zeros. Some grids you will only bet 9 numbers, (or 3 streets)
others will be a mix of 9 and 18, so a little bit of progression  may be necessary, but it pulls itself
out of holes.

Here are some from real spins to show.

4 1
2 1 win

1 2
3 4
1 1 win

1 4
3 1
4 1 win

1 4
1    win

1 2
1    win

1 1 win

3 4
1 1  win

4 3
2 3 win

etc

BW

Great stuff A

Hopefully the profits are as easy peasy to attain as the system is to implement

I think that means yes!

Hi Yanks,


I really like your idea a lot - so much that I think it's strong enough and different enough from mine to be considered on it's own, so maybe you should publish it separately. I'm glad you were inspired to create it because it's looking solid. Of course, keep us updated of further developments.


Tomla,


As I said, it's a bit too boring to be a stand alone system so, yeah, would make a nice side line and see how you go. Post any results if you can mate. Cheers


BW

Quote from: shazwad on August 07, 2013, 11:57:19 AM
Just played on smartlive RNG as live was down and won 30 units. Most wins on 1st bet, a few on 2nd bet andtwice it went to 3rd bet, i.e 9-9. Played about an hour. Would be even safer if waited for three virtual lossess!

You're right shaz but that would test even the patience of the Easter Island stone monoliths.

I think 2 is just about right unless you have a bot. If a milder progression could be adapted, only 1 virtual loss may be used?

Thanks for the testing !

Agesta
Patience is part of this devilish game. With it this system is a goodun. As you found out it will most often win within 2. Cheers

Here's a 100 spin testing session :

[reveal= 100 Spin Test Session]

3
3
2
1
1
1
1
2
3
1
1
2
2
1 bet dozens 2,3
3 Win
3
1
1
1
1
3
2
1
3
1
1
2
3
2
1
2
2
1
1
1
1
1
2 bet dozens 1,3
1 Win
2
3
2
3
1
1
1
1
3
3
1 bet dozens 2,3
3 Win
1
3
3
1
3
2
1
3
2
1
2
3
3
2
2
3 bet dozens 1,2
3 Lost
3
3
2 bet dozens 1,3
3 Win
1
3
2
2
2
2
2
2
3
2
1
1
1
3
2
2
2
2
3
1
1
1
2
2
2
1 bet dozens 2,3
2 Win
2
[/reveal]

there's a typical session just to get your heads around the system.

Cheers,  BW

Quote from: TwoCatSam on August 05, 2013, 11:43:23 PM
Wiz

Second question:

Must we have this  1122?  What if we have 11221?  Does that start the search over again or will a 2 or 3 trigger a bet?

Sam

Don't have to have 1122, just any repeaters, could be 3322, 1133, 2211 etc


11221 would mean you then bet dozens 2 and 3 to stop the third repeaters in a row

Quote from: TwoCatSam on August 05, 2013, 11:40:29 PM
Wiz

Let me get this staight:

1
1
2
2

3...........Now we bet dozens 1 and 2; hoping 3 does not repeat?

Sam

Correct Sam

Hey, I got this one scratching around in my head - I'll cut to the system, nice and quick.
It's a double dozen strategy. It takes some waiting, but because it's in testing zone, I'm still looking into it and putting it out there for some comments etc and other input.
So we're looking for two consecutive lots of repeating dozens:
1
1
3
3  like so. Then we wait for a chop.
It may take more than one spin.

3
2 There we have it.

Now bet that dozen two won't repeat.
So essentially we are betting against long sets of repeating dozens.
Here, we are being ultra safe and waiting for 2 virtual losses.

I think looking at a few thousand, the worst I have seen is 5, but you're unlucky to go beyond 3, hence the 2 virtual bets to start off. The only problem is that you may only get 2-3 bets per 100 spins.
Fine if you have a bot or another system alongside it. You could, if you had a slightly safer progression than marty, only waitfor 1 virtual loss. Here's a brief sample.
1
2
1
1
3
2
2
1
1
1
3  bet here
2  win

BW

Yeah me being thick Chris

Please delete discard eliminate obliterate annihilate extinguish expel and finally vaporise

Good Day!

A new system for you to try out. I've been getting some strong results with this.

It's all about the finales

If two even finales show then bet once for an odd finale

If two odd finales show then bet once for an even finale

An example:

35 - odd finale
13 - odd finale, bet all even finales
12 - win
23 - odd
2   - even
36 - even, bet all odds
28 - loss retrack
16 - even
7   - odd
27 - odd, bet all evens
18 - win

This is an even chance method. Use whichever MM you feel comfortable with.

BW