Hi
It's roulette player again. Ihave a very powerful way to bet on street.
It requires a $152.30 minimum bankroll with 10 cents minimum bet on streets.
It's a slow bankroll building strategy that requires a lot of patience
The trigger is that you spin without betting and mark down in which street the number came.
From street 1 to 12 reading the board from left to right. You wait until the number shows up in 9 different streets in the previous 9 spin. It's hard enough to do because there is a lot of repeats before it happens.
When you meet the condition of your trigger, you are on your way to a profit. You will see why.
You bet 10 cents on each of you 9 different streets and 10 cents on the 0 for a total of $1.00 Most of the time, you will win on the next spin because there is a big chance the number will fall in one of your selected streets. You make 20 cents profit on any street you bet on and $2.60 if the 0 hits.
The only way to loose is if the number shows up in a new different street. You then go in the second step of your progression. You bet 70 cents on the steet where the ball landed in the last spin and also the same amount on each of the first 9 streets. So you bet on 10 streets and 30 cents on the 0 for a total of $7.30. At this point the chance of a repeat is even bigger and you win. You make 10 cents profit on any street and $2.50 profit if the 0 hits. Very rarely, you will loose as this point. If it's the case, you bet on the 11th different street where the number showed up. You go on the last step of your progression, you bet $12.70 on the last street where the ball landed in the last spin and also the same amount on each of the streets that you bet before and $4.30 on the 0 for a total of $144. I never seen a lost at this point because the odds of having the number falling in all 12 different streets in 12 consecutive spins is 1/18613.92623. I used a random number generator in Excel which generates many sets of spins per second and that never happened. The best I have seen is 11 differents streets in 12 spins and not very often. That's why you need the third step of your progression.
So try it for fun and make sure you understand this strategy in full before trying it for real money. Good luck with this. I attach also the Excel file for that particular progression. All the formulas are in place for you, I did the hard part. You can change the amounts in each steps for bigger profit but you need a bigger bankrool. Right now my bankroll is $133 just playing the powerful pattern breaker strategy. I am only $20 away to have enough for playing this streets system.
Good luck
Rouletteplayer[smiley]aes/money.png[/smiley]
It's roulette player again. Ihave a very powerful way to bet on street.
It requires a $152.30 minimum bankroll with 10 cents minimum bet on streets.
It's a slow bankroll building strategy that requires a lot of patience
The trigger is that you spin without betting and mark down in which street the number came.
From street 1 to 12 reading the board from left to right. You wait until the number shows up in 9 different streets in the previous 9 spin. It's hard enough to do because there is a lot of repeats before it happens.
When you meet the condition of your trigger, you are on your way to a profit. You will see why.
You bet 10 cents on each of you 9 different streets and 10 cents on the 0 for a total of $1.00 Most of the time, you will win on the next spin because there is a big chance the number will fall in one of your selected streets. You make 20 cents profit on any street you bet on and $2.60 if the 0 hits.
The only way to loose is if the number shows up in a new different street. You then go in the second step of your progression. You bet 70 cents on the steet where the ball landed in the last spin and also the same amount on each of the first 9 streets. So you bet on 10 streets and 30 cents on the 0 for a total of $7.30. At this point the chance of a repeat is even bigger and you win. You make 10 cents profit on any street and $2.50 profit if the 0 hits. Very rarely, you will loose as this point. If it's the case, you bet on the 11th different street where the number showed up. You go on the last step of your progression, you bet $12.70 on the last street where the ball landed in the last spin and also the same amount on each of the streets that you bet before and $4.30 on the 0 for a total of $144. I never seen a lost at this point because the odds of having the number falling in all 12 different streets in 12 consecutive spins is 1/18613.92623. I used a random number generator in Excel which generates many sets of spins per second and that never happened. The best I have seen is 11 differents streets in 12 spins and not very often. That's why you need the third step of your progression.
So try it for fun and make sure you understand this strategy in full before trying it for real money. Good luck with this. I attach also the Excel file for that particular progression. All the formulas are in place for you, I did the hard part. You can change the amounts in each steps for bigger profit but you need a bigger bankrool. Right now my bankroll is $133 just playing the powerful pattern breaker strategy. I am only $20 away to have enough for playing this streets system.
Good luck
Rouletteplayer[smiley]aes/money.png[/smiley]