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Messages - AsymBacGuy

#46
AsymBacGuy / Re: Why bac could be beatable itlr
April 08, 2025, 09:15:46 PM
Hi KFB!

Ouch, I guess it's just coincidental...a weird coincidence though.

Never investigated the ACV but I know you don't miss anything...


One should look at baccarat wagers just like shopping. Sometimes the wager is worth more than what we pay for it and sometimes wagers are selling for a price greater than their value. Optimally we should shop to pay $48 for a $52 dollar wager. Sometimes there are even better deals. However, often there may only be a half dozen or so good deals per shoe.

Can't agree more on that.

as.
#47
AsymBacGuy / Re: Why bac could be beatable itlr
April 07, 2025, 02:52:53 AM
At baccarat itlr the asymmetrical propensity will be slight superior than the symmetrical one, yet many shoes could produce long situations of sym patterns posing a real threat to any not carefully conceived plan. Remember that the HE is always burdening us.

So less is more, by any means. Meaning that lower is the amount of our bets better will be our "precision" of being more right than wrong. At the cost of missing some profitable situations that anyway itlr will save us a lot of money.

Suppose the core (discarding some initial and final hands) of the shoe A/B patterns went as: (AS=asymmetrical pattern= +1 and S=symmetrical pattern= -3), Big Road considered.

AS-AS-AS-AS-AS-AS-S-AS-AS-S-AS-AS-S-S-AS-S-S-S-AS

At the end this is a strong Symmetrical shoe as AS=12 (=+12) and S=7 (=-21). Total -9.
Yet AS clusters (3) are equal to AS isolated events (1); S patterns came out as isolated two times and double clustered one time (S-S) and only one time clustered more than two times in a row (S-S-S).

Another shoe:

AS-AS-S-AS-AS-AS-S-AS-AS-AS-AS-AS-AS-AS

AS= 12 (+12), S= 2 (-6).

Here this shoe haven't balanced the previous one (-9), now (+6) but at this shoe there are no "unexpected" distributions capable to be harmful to our plan.
AS= always clustered and S= always isolated.

Another shoe:

AS-AS-AS-S-AS-AS-AS-AS-AS-AS-AS-AS-AS-S-AS-S-(-1)

AS=13, S=3 plus -1 that is a total of +3.

Moreveor even here AS clusters are 3 and AS isolated events (at the end of the shoe) are just 1.

Let's see what happens by respectively running our random walk getting a different pace than the Big road succession.

shoe #1: AS-AS-S-AS-AS-AS-AS-AS-AS-AS-AS-AS-AS-AS-S (AS=13, S=2) that is +13 and -6

shoe #2: AS-S-AS-AS-S-S-AS-AS-AS-AS-AS-S-AS (AS=9, S=4) that is +9 and -12

shoe #3: AS-AS-AS-AS-S-AS-S-AS-AS-AS-AS-AS-(-1) (AS=10, S=2 plus -1) that is +10 and -7

Even though after having collected thousands and thousands of real live shoes data we've managed to set up the best performing random walk catching the most likely average card distribution, we'll see that, generally speaking, the least patterns to look for are those forming symmetrical patterns for long. Providing to assign the "asymmetrical/symmetrical" feature up to a point.

So to simplify the issue, symmetrical spots are:

1) ABAB or BABA

2) AABBA or BBAAB

3) AAA(...)-BBB(...) or BBB(...)-AAA(...)

Then, asymmetrical spots are:

1) ABB or BAA

2) ABAA or BABB

3) AABA or BBAB

4) AAA(...)BA or BBB(...)AB

5) AAA(...)BBA or BBB(...)AAB

Obviously a deep selected betting plan must take into account how many times any first or second level of asymmetry came out in a row or not, a thing we'll take care very soon.

as.
#48
AsymBacGuy / Re: Why bac could be beatable itlr
April 06, 2025, 08:53:35 PM
You're fine LP and thanks for your interest.

This thread is made upon ideas, findings and a very deep interest about this complicated game where we didn't take anything as granted.
Therefore our strategies are mainly based upon statistical findings applied to volatile productions very often improperly labeled as "randomly distributed".

Whether is impossible to read randomness (providing each trial to be as perfectly independent from the previous one), we know that distributions sooner or later will take more likely distributions in relationship of the actual shuffling factor.

The problem of moderate/strong unrandomly shuffled shoes is that it's more difficult to spot an "average" key card distribution along with math advantaged hand ranges, in a sense high/low cards are more clumped than expected by running a true random model.

Of course if a given strategy works at perfect random or close to perfect random shoes, anything different than that (unrandom world prevails) might be attacked by a kind of opposite method. So maybe privileging more the SYMMETRICAL less likely feature.
But doing this we could find ourselves in the unwanted world of full uncertainty unless a same shoe is shuffled several times by the same biased procedure.

So players thinking that every shoe dealt in different circumstances will be distributed by the same random features actually commit a big mistake erasing a possible edge.

more later

as.
#49
AsymBacGuy / Re: Why bac could be beatable itlr
April 02, 2025, 04:57:44 AM
Believe me, you can't be wrong by properly exploting the asymmetry.

Say we want to adopt a multilayered progressive scheme.

We have three different fictional players betting for us.

#1 will constantly betting toward clustered asym spots up to a loss, then he'll wait for a new asym situation to restart the betting.

#2 will wait for a symmetrical spot to show up (sometimes it'll take quite a long time and that should give you the idea of what I'm talking about) then wagering toward one asym spot then stops its action letting #1 to restart the betting.
If he loses, #3 come in play.

#3 will wait for TWO asym spots to show up then wagering toward one asym spot then stops its action letting #1 to restart the betting.
If he loses, the action is stopped for every player (#1, #2 and #3) until a fresh asym spot shows up.
And so on.

After each player had lost three times in a row, we'll raise the bet for that specific player by a 10% or 20% amount knowing that the only harsh "enemy" spots making ALL three players to lose in a row are those forming one asym isolated spot followed by three (or more) symmetrical spots.

When such unlikely thing happens (all players losing) we have reasons to even double our standard bet then staying at this betting level until a full recover happened.

In fact asym-sym-sym-sym-...-asym situations coming out in a row are just an exception.

See you next week

as.
#50
AsymBacGuy / Re: Why bac could be beatable itlr
April 02, 2025, 02:17:23 AM
A personal test for bac randomness

Our group is made by frequentist probability lovers, in the sense that we like to collect data coming out from the same exact source and then building a probability theory.

Even the "same source" concept could be a volatile definition: think about shuffling machines operating at two alternate shoes lasting for a X time (number of shuffles per each shoe).
We've found important differences if the same shoe did undergo one or two shuffles or multiple shuffles.

Therefore if we want to exploit the "average" card distribution tool, we want to play at properly shuffled shoes.
Remember the comparison with black jack: low cards-neutral cards-high cards decks (in any LNH sequence) completely deny a card counter math advantage.
Of course such situation could easily happen for natural reasons, but we never know if it seem to appear for "too much" long.

At baccarat we've personally devised two valuable main tools to take care of in order to approximate whether a shoe is really randomly shuffled or not.

a) the math advantaged two-initial cards points losing "too many times" despite of their math propensity to win;

b) a higher than average ratio of hands resolved by 6 cards.

Of course those are the two main factors, there are other minor parameters to look for.

Realize that there's no way to win at baccarat itlr if our bets will get the inferior 2-card initial point as the number of drawouts will be underdog to get a long term edge.
Thus whenever the drawouts are coming out "too often", we theorized that that shoe was improperly shuffled. So unplayable.

Hands resolved by 6 cards is an additional factor to look for and is related to the high neutral card density (more than 30%) along with the 6s,7s,8s and 9s class (again more than 30%), then to  other less likely card combinations forming natural points as 5-4, 5-3, 4-4 or standing points as 5-A, 5-2, 4-3, 4-2 or 3-3.

Card distributions not forming those situations AT BOTH SIDES for long are relatively rare and when they're not (that is they are coming out too often) we could assume a kind of randomness bias.

Paradoxically it's better to move around a strong good or strong bad choice than navigating into a more undefined world where too many cards will dictate the actual result.
That's because an overalternating shifted world will be the least situation to happen.

as. 
#51
AsymBacGuy / Re: Why bac could be beatable itlr
April 01, 2025, 09:03:56 PM
IMO at baccarat the only reason why we could win is because of the more likely card distribution ranges.
The actual results do not necessarily be the by product of more likely card distribution ranges as (beyond the natural variance) there still exists the important factor regarding the shuffling more or less randomness.

Our data had taught us that a perfect randomness or a slight defect of randomness will go to our favor as best represents the "more likely card distribution" ranges.

Bad shuffled shoes need too much complicated algorithms to be resolved (approximated) and of course we never know how "bad" a shoe is shuffled and more importantly the more probable patterns to look for.

In poor words, we'll win a lot or lose a lot when shoes are badly shuffled with 0 impact of skills, whereas perfect random or near perfect random shoes will give us plenty of informations to draw on.

more later

as.   
#52
AsymBacGuy / Re: Why bac could be beatable itlr
March 31, 2025, 04:02:34 AM
At baccarat the definition of asymmetry and symmetry is particularly intricated for several reasons:

- the model is slight asymmetrical at the start (B>P)

- the model is affected by a huge first-step asymmetrical distribution of cards, specifically of key cards

- the model is affected by a huge second-step asymmetrical distribution of third(s) card(s)

- the model is finite and dependent, meaning that each situation (hand dealt) won't cross through the exact same parameters.

Overall and simplifying the issue, we might infer that symmetrical events are just "incidents" made along the way.
After all statistics give us plenty of examples where asymmetry will lead over the symmetry, the latter now intended as a steady expected probability happening for long.

Actually at baccarat there's no symmetry involved other than by coincidental factors and when some low levels of asymmetry are surpassed, more often than not a slight subtle force will shift the results in order to deny a kind of "balanced" results.

Therefore the rule to follow is expecting "low levels of asymmetry": whenever this rule seems to be "violated" best action to make is staying still (no betting) or to wager that the lowest levels of asymmetry will remain as silent.

After all we have strong reasons to think that cards are randomly arranged to get more asymmetrical patterns than symmetrical patterns and when this isn't true is just for a temporary and coincidental short term effect.

Examples of typical asym or sym patterns

ABAA = asym
ABA  = sym

AABBB = asym
AABBA = sym

AAABA or AAABBA = asym
AAABBB = sym

Overall we could accept the idea that asym=sym, yet we should be more interested about how many sym events will shift into asym events or vice versa and, more importantly, at which level of asymmetry or symmetry. Per every shoe played.

Now we might use a formula based upon that asym-asym > asym-sym; sym-asym > sym-sym for the most probable asymmetry/symmetry levels of apparition (0, 1 and 2).

We know that an asym/sym/asym sequence lasting for long is the least occurence to happen and the same is about long sym/sym successions.
The remaining probability world is what we should be interested to focus about as proportionally taken (remember the 0.75 probability to happen) asym/asym..., sym/asym and sym-sym/asym patterns are way more probable to naturally come out so maybe enticing (I've sayed "maybe" as a simple flat betting scheme will get the best of it) a multilayered progressive scheme actioned by one or more two losing sym sequences happening at different sections of the shoe.

Assigning a 0.75 general winning probability to a asym/sym independent model, the average expected W/L ratio is 3:1, so unbeatable for the vig or P asymmetrical probability.
In reality baccarat slightly endorses the asym patterns formation in the way that each asymmetry level will be more probable than the symmetry counterpart.
Naturally the sure asymmetry will make coincidental symmetrical patterns along the way, that's why  we have to restrict their appearance by assigning or not them to a more likely sequences category.

I know, that's all rattlesnake.sh.it.
Fortunately. 

as.
#53
AsymBacGuy / Re: Why bac could be beatable itlr
March 30, 2025, 08:56:59 PM
Hi lp!

Actually things are much more complicated as I talked about A and B events and not about mere B or P hands.

For example a BBBBBB or BBBBBBBBBBBB or PPP or PPPPPP patterns should be considered as asymmetrical (or symmetrical) in relationship of the previous pattern and not by their shape alone.
Therefore BBBBBB could be either an asymmetrical or a symmetrical pattern by what came out previously.
The same about blue/red derived roads or any other random walk you want to utilize.

Then, since each shoe is a world apart, levels of confidence should be approximated by the number and ranges of asymmetrical or symmetrical situations just happened.
Low symmetrical patterns are a general rule, but the actual route must be carefully defined as just one hand could transform an asymmetrical pattern or sequence into a symmetrical pattern or sequence; obviously such thing might happen by an opposite fashion, anyway not constituting the propensity we're really wanting to exploit.

More later

as.
#54
AsymBacGuy / Re: Why bac could be beatable itlr
March 24, 2025, 09:59:55 AM
We're deadly sure that the asymmetry/symmetry issue is the main tool to extract an advantage from.
Simplyfing:

S-S = stop the betting

S= what to bet next depends about the previous As/S texture

As-S= bet As

S-As= bet As

As= almost always bet As

As-As= caution, sky's the limit but what we have secured should remain in our pockets.

So any hand dealt is a new hand my a$$, cards are arranged to make more probable asymmetrical situations than symmetrical ones.
Situations seemingly belonging to a kind of steady symmetrical world are just springing from incidents, natural variance or weird unlikely card distributions.

Now a careful multilayered progressive plan cannot be wrong as:

First level of confidence:

As-As > As-S

S-As > S-S

Second level of confidence:

Any S-S happened previously somewhat reduces the S-As propensity at a new pattern.

Any As-As and S-As events happened previously endorse the As-As and S-As propensity at a new pattern.

Third level of confidence:

- As-As coming out clustered twice previously is not a good indicator to bet again towards another As-As pattern;

- S-S coming out clustered twice is a good indicator that the next S will be followed by As and not S.

- S-As coming out clustered twice is an excellent indicator that next pattern will be of the same shape (that is that S will come out as isolated again).

To provide a vulgar example say the shoe went as:

BB
PP
BBBBBB
PPPPP
B
P
BB

Such fragment will form a S-S-S sequence (BBPP, BBB../PPP.., BP).
Run the derived roads and such symmetry will go down the toilet.
In fact only the sr will form one symmetrical pattern. Everything else will produce asymmetrical patterns either at sr and at the remaining roads.

as.
#55
AsymBacGuy / Re: Why bac could be beatable itlr
March 24, 2025, 08:50:45 AM
As long as cards are asymmetrically distributed along any shoe dealt (100% of the times),

As clusters > S clusters and As isolated events < S isolated events.

Unlikely distributions, incidents and natural variance will make the overalternating mood as the least probable happening so possibly inverting the above propositions.

Therefore sometimes S clusters will predominate over As clusters; at a lesser degree S isolated events will be more restricted in their appearance than average so privileging S clusters.
That further denies the overalternating mood appearance.

When in doubt go either for low/moderate levels of asymmetry better by trying to by pass the lowest losing levels or tell the casino to wait for inferior players action by not betting a fkng nothing.

If properly executed and by choosing the right random walks,  this plan is equal or superior than the edge sorting technique.

as.
#56
AsymBacGuy / Re: Why bac could be beatable itlr
March 24, 2025, 03:03:12 AM
Asymmetry/symmetry considerations about bac successions

Symmetrical situations are slight less likely than asymmetrical situations and of course asymmetrical situations cannot stand for long most of the times.
More precisely asymmetrical situations will come out more probably (so more clustered) than symmetrical situations, anyway we have to respectively approximate at best the asym/sym appearance by setting up a "cutoff" value as just one hand might easily change a more natural (expected) flow into a moderate/strong deviation pattern. Obviously we're way more interested to avoid moderate/strong symmetrical distributions than stopping the asymmetrical counterpart.

Suppose we have two fighting A and B events (patterns, situations) forming an original succession and several derived sub successions.

We might empirically consider as symmetrical (s) those patterns:

1s) ABAA.. and BABB..

2s) AABBA and BBAAB

3s) AAA..BBB.. and BBB..AAA..

On the other end we'll get the asymmetrical (a) patterns counterpart being:

1a) ABB or BAA

2a) AABA or BBAB and AABBB.. or BBAAA..

3a) AAA..BA or AAA..BBA and BBB..AB or BBB..AAB

Once a pattern had surpassed the 2-step level we have taken as a "cutoff" value and dictating whether a pattern is either labeled as asymmetrical or as symmetrical, we're not interested to know what the fk happens next, unless a new opposite category shows up.

Now we have transformed a BP succession into an Asym/Sym sequence that is slight less likely to produce strong overalternating moods, especially if we are taking care of the different 1-step and 2-step probability situations.

That means that asymmetrical or symmetrical spots are more probable to produce clusters at any side of the spectrum and when they're not the asymmetrical subtle force itlr will deviate the results by forming low-level more likely ranges.

What is really interesting to notice after thousands and thousands of real live shoes tested is that whenever a given precise Asym/Sym pattern level hadn't shown up so far, we should consider it as a kind of "not existent" pattern so increasing the probability of other patterns coming out.

As a side note we've found particularly useful to read and study the Yerkes-Dodson law (1908) as without the use of a software baccarat remains a strong human challenge vs a "machine".

as.
#57
AsymBacGuy / Re: Why bac could be beatable itlr
March 23, 2025, 09:56:29 PM
Hi lovepreaks!

Basically 5-card hands are the core of the asymmetry whereas 4-card and 6-card hands constitute the symmetry. Of course we are interested about the "ranges" of such different situations transformed into actual results so we're obviously forced to consider asymmetry and symmetry at the real BP sequence and derived successions.

It's a fact that at baccarat the least distribution to show up is a kind of "overalternating" mood of two fighting opposite events; an example is when consecutive doubles come out in a row thus the CFS is 1 per every two hands dealt (+-+-+-..).
The most part of the remaining distributions are made of univocal distributions getting low/moderate levels of deviation (++, +++ or -- and ---).

When complex patterns are considered, better will be the prediction as whenever many hands are needed to produce a pattern, the overall asymmetrical strenght will get rid of both some "incidental results" and natural variance.

Progressively wagering B after P and PP is not an option that I recommend as those are patterns too easy to come out so lacking the "complex" requisite.   
   
I have lost a lot of money by betting purely based on emotions

We all did.
Casinos prosper about players' emotions a lot more than by exploiting the math edge.

Baccarat is a strict technical game where successions are somewhat "biased" by more likely ranges that have nothing to do with mere math; it's up to us to define what are the more probable ranges intervening in the process and without any doubt in many instances best move to take is to stay still.

More later

as.
#58
AsymBacGuy / Re: Why bac could be beatable itlr
March 19, 2025, 04:12:23 AM
BTW, thanks for your interest in reading my pages and keeping to read this wonderful site.
400k views are a very good accomplishment, thanks.

If anyone has a bit of hope to beat this game (and taking back the money lost), well, you are in the best place to get some hints. By far. And, more importantly, for free.

There are very illustrious players posting here: Alrelax and KFB. Both are very experienced players and at baccarat experience and proper knowledge is everything.

We know that as long as a verified math propensity isn't devised and proved, well we're talking about bighorn.stuff, but that's an advantage for us.
At baccarat we can play mathematically "wrong" and betting thousands by being labeled as clowns, no problem with that.

After all, not every baccarat supervisor will be 100% certain that the game is unbeatable.
And they are right. 

as.
#59
AsymBacGuy / Re: Why bac could be beatable itlr
March 19, 2025, 03:30:42 AM
That's good Al, we'll wait for your link :thumbsup:

HERE: ((With reasoning, not armchair quarterbacking).

https://betselection.cc/actual-baccarat-shoes/think-and-be-smart/msg72689/#msg72689

Baccarat results are distributed by a kind of an on/off model but the average card distribution is not, meaning that some distributions are more likely than others.
That means that in the short/intermediate terms a slight but constant force will polarize the results by more likely ranges that of course will be "almost" neutralized by those not average shoes deviating at various levels from the norm.

In a nutshell our betting options are restricted into three different categories:

a) A pattern or two patterns are going to be clustered at least one time (a1); then we'll get a2, a3, etc. clustered scenarios;

b) A pattern is going to be isolated (I), that is followed by an opposite pattern;

c) A pattern or (more unlikely) two patterns had never shown up so far (N).

We've seen that average shoes will more likely include a1, a2, a3 and I patterns, whatever arranged (permutation issue); N is the pivotal factor to get most of our edge as an asymmetrical world is destined to get "silent" the remaining elements so endorsing the probability that all possible other patterns will come out.
Now we shouldn't be worried about the precise pattern's shape (a1, a2, a3 or I) coming out, we'd just try to get rid of the pattern that had never shown up so far, meaning that it's just a "level" consideration to be made and obviously it's better to wait a given pattern to be built before thinking to place a bet.

By doing this we're limiting the randomness world and exploiting an average asymmetrical card distribution as "silent" elements will let the remaining patterns to be more clustered than average.

Obviously up to a point as low numbers (I, a1, a2 and a3) will be slight more probable than huge numbers.

Notice that even if casinos virtually want to deal "all patterns" being balanced, such thing comes out at our favor as now pattern ranges are more limited than average.

So the main group of fatal mistakes to do are chasing what didn't appear so far and hoping that a given univocal pattern will come out "too" long.

Examples.

Shoe #1 (many hands were discarded at the start of the shoe--precious hint).

I-I-I-I-I-I-a3-a3-I-a1-I-a1.

Think of every element coming out, not knowing what will come out next: Are we going to bet towards a2?

Shoe #2.

a2-a1-a1-a3-I-a1-I-I-I-a1-I.

In this shoe every element had come out, anyway just one deviated pattern happened (a3) and at the intermediate/final portion of the shoe only low number patterns happened (I or a1).

When in doubt go either for the silent pattern to prolong its absence or towards low numbers (that is anything but a a3).

Mix every possible pattern whatever you want, itlr either one or two silent patterns will happen for a decent time or, more likely, low numbers (I and a1 OR a1 and a2) will come out clustered at least one time.

Such propensity doesn't work ALL OF THE TIMES but MOST OF THE TIMES, so capable to reach and surpass the famous B 51.3% and P 50.1% probability cutoff values worth of playing a sure fkng indeniable EV+ game.

See you next week

as.
#60
AsymBacGuy / Re: Why bac could be beatable itlr
March 18, 2025, 09:55:32 PM
Al wrote:

I have capitalized very nicely as well as missing the opportunities being presented because I was desiring something and not realizing at the instant time, what being presented cannot be changed to what I desired, etc.

Yep, as humans we make plenty of good plays and a greater amount of mistakes, that's why almost nobody will lose the expected EV- but way more than that.


What are we really going to exploit?

Once seated we should have a clear vision of what we're going to do. 

Each bet remains EV-, no mechanical plans can beat it, let alone a mere trend following strategy or other human shoe's compliance approaches.

Maybe a mix of the two could be helpful but the main issue we should be focused at is the classification of the actual shoe needing several factors to be ascertained.

More later

as.