Here is something interesting I found well doing some research over the last few days.
I will paste in one of my 100 spin cards and then explain the system.
13 2A
11 1B (3C)
13 2A (3C)
31 3A (C) O
3 1C (B) O
18 2C (B) S
9 1C (B) S
4 1A (B) S
26 3B (2) O
26 3B (2) S
23 2B (C) O
3 1C (A) O
23 2B (A) S
34 3A (1C) O
15 2C (1) O
35 3B (1) S
33 3C (1) S
15 2C (1) S
14 2B (1) S
15 2C (1) S
31 3A (1) S
34 3A (1) S
6 1C (B) O
34 3A (B) S
20 2B (1C) O
9 1C (3A) O
23 2B (3A) S
7 1A (3) O
17 2B (3) S
14 2B (3) S
4 1A (3) S
4 1A (3) S
29 3B (C) O
22 2A (C) S
10 1A (C) S
14 2B (C) S
34 3A (C) S
33 3C (1) O
6 1C (2B) O
5 1B (2) O (RUN OF 3) WON
9 1C (2) S
36 3C (2) S
25 3A (2) S
36 3C (2) S
35 3B (2) S
22 2A (1) O
6 1C (3B) O
34 3A (B) O (RUN OF 3) WON
21 2C (B) S
2 1B (3A) O
19 2A (3) O
15 2C (3) S
24 2C (3) S
14 2B (3) S
25 3A (1) O
31 3A (1) S
32 3B (1) S
33 3C (1) S
3 1C (2) O
18 2C (A) O
24 2C (A) S
21 2C (A) S
26 3B (A) S
6 1C (A) S
23 2B (A) S
6 1C (A) S
24 2C (A) S
28 3A (B) O
11 1B (2C) O
24 2C (3A) O (RUN OF 3) WON
8 1B (3A) S
27 3C (A) O
36 3C (A) S
30 3C (A) S
25 3A (2) O
14 2B (1) O
11 1B (C) O (RUN OF 3) WON
28 3A (C) S
21 2C (1B) O
33 3C (1B) S
35 3B (1) O
13 2A (1) S
6 1C (3B) O
25 3A (B) O
4 1A (B) S
35 3B (2) O
32 3B (2) S
26 3B (2) S
11 1B (2) S
7 1A (2) S
15 2C (3) O
8 1B (3) S
29 3B (A) O
20 2B (A) S
27 3C (A) S
6 1C (A) S
10 1A (2B) O
2 1B (2) O
9 1C (2) S
13 2A (3) O
The number is to the left.
Then I assign the dozen/column. Example 13 = 2A. (2nd dozen / column A)
The ( ) contain the furthest back dozen and/or column.
So looking at the first few numbers from above....
13 2A
11 1B (3C).....BOTH 3 and C are the furthest back.....
13 2A (3C) .....BOTH 3 and C are still the furthest back......
31 3A (C) O......Now just the C is the furthest back........
3 1C (B) O......Now the B is the furthest back.......
18 2C (B) S......The B is still the furthest back......
You may be wondering what the O and S stand for?
If the furthest back stays the same, it is marked S.
If it changes, it is marked O.
The 'Run of Three' System is looking for three O's and then you bet for the S on the next result.
You can see that 4 bets appeared looking through my 100 spin card.
Here was the first one.
33 3C (1) O
6 1C (2B) O
5 1B (2) O (RUN OF 3)
9 1C (2) S
So you can see the three O's and now you would be looking for it to change to S.
This basically means that you want the 2nd dozen to remain missing in this case.
You would therefore bet dozen 1 and dozen 3.
Number 9 appeared (1C) which belongs to dozen 1 and is a winner.
All 4 bets were winners. Most of my cards are clear winners with this idea with very few losses at all.
cheers