Hello everyone!
I have created a progression for all even chance (approximately) bets.
Not only does ride the waves of victory after victory but ALSO,that's VERY important,protects your profits by not placing everything back at risk.
So,let's see how it goes:

1) bet 2 units: if win +2 if lose -2

That's the ONLY real risk,the first level of betting,most of the time you will your first bet with a bit of luck and then you could capitalize your winnings RISK-FREE!

2) bet 1 units: if win +3 (total)/ lose +1

3) bet 2 units: if win +5 / lose +1

4) bet 3 units: if win +8 / lose +2

5) bet 4 units: if win +12 / lose +4

6) bet 5 units: if win +17 / lose +7

I wouldn't recommend you to proceed further than 6 consecutive wins,even a streak of 6 is hard to get,but since this progression is conservative,you won't risk at any point your winnings.
I have use it to play for hours without losing my bankroll,while waiting for the streak of 6 consecutive wins.
If you give it a try,you should notice that losses are small and wins becoming big by the time if you have the patience and disclipine.
Your comments would be welcome.

Dear readers,

this is a thread which requires your full attention in order to fully comprehend the hidden opportunity.

Let's start with the basic about the Law Of the Third:

In every 37 spins cycle there are 24 numbers which have appeared once or more and 13 sleepers
(numbers which haven't appeared within the last 37 spins)
Those are average numbers and deviations exist, for example I've seen up to 30 different numbers to show up within the 37 last spins and the least were 18 different numbers.
Those extremes are from my experience during gambling sessions and not from simulations.
In order to find the average we should determine the extremes,or in other words the limits, in that case 18 and 30 are the limits.

18 19 20 21 22 23 24 26 26 27 28 29 30 start by discarding the outer numbers from both sides:

First discarding 18 and 30
Second discard 19 and 29
Third discard 20 and 28
Fourth discard 21 and 27
Fifth discard 22 and 26
Sixth discard 23 and 25

And we conclude to 24 which is the average total of the appeared numbers within 37 last spins.
Another way to calculate the average is to add all the totals and then divide the total sum with the total of the averages,for example:

18 different numbers within the last 37 spins happened 1 time
19 different numbers within the last 37 spins happened 2 times
20 different numbers within the last 37 spins happened 3 times
21 different numbers within the last 37 spins happened 4 times
22 different numbers within the last 37 spins happened 5 times
23 different numbers within the last 37 spins happened 6 times
24 different numbers within the last 37 spins happened 7 times
25 different numbers within the last 37 spins happened 6 times
26 different numbers within the last 37 spins happened 5 times
27 different numbers within the last 37 spins happened 4 times
28 different numbers within the last 37 spins happened 3 times
29 different numbers within the last 37 spins happened 2 times
30 different numbers within the last 37 spins happened 1 times

[(1 x 18)+(2 x 19)+(3 x 20)+(4 x 21)+(5 x 22)+(6 x 23)+(7 x 24)+(6 x 25)+(5 x 26)+(4 x 27)+(3 x 28)+(2 x 29)+(1 x 30) / 49] =>

[(18+38+60+84+110+138+168+150+130+108+84+58+30) / 49]=>

1176 / 49 = 24

This means that if someone was betting one number for 37 spins, 24 times he/she would have won and 13 times he/she would have lost.
To calculate the total sum of lost bets is easy:
13 times multiplied by 37 (1 x 37) equals minus 481 units.

In order to find the total amount of won bets, we should again calculate the averages as we did above,let's see:
We start from the middle numbers within a 37 spin cycle and add 2 more numbers from both sides till we have a total of 24.
18th and 19th spins
17th and 20th spins
16th and 21st spins
15th and 22nd spins
14th and 23rd spins
13th and 24th spins
12th and 25th spins
11th and 26th spins
10th and 27th spins
9th and 28th spins
8th and 29th spins
7th and 30th spins
So we have 24 wins from different spins, now let's calculate the total amount of net profit.

29+28+27+26+25+24+23+22+21+20+19+18+17+16+15+14+13+12+11+10+9+8+7+6 = 420

But since we would lose 481 - 420 = -61 loss, therefore the definition negative expectation.

Do we agree so far?
Is everything clear?

Let's see how we could turn the negative expectation into positive without changing a thing in terms of probability, in fact with exactly the same results which have lead us to the negative balance above.

The average expectation is to get twice the wins for every loss, with my method you only need approximately 1 positive cycle for every negative cycle, which means that the proportion of 2 to 1 changed to 1 to 1.

Let me explain how this is possible, the only thing which I'm not going to reveal you here is the criteria which I'm using to select the betting number.
You could pick a random number, or your "lucky" number or anything else you like.

I start flat betting 1 number with 1 unit for 36 spins.
When the betting number appears, no matter in which spin, I re-bet the same number plus its neighbour regarding the wheel layout (right or left doesn't matter)

So now I'm flat betting 2 numbers with 1 unit each for the next 18 spins.
When one of the two betting numbers hits within eighteen spins, then I re-bet those two numbers and adding the other wheel neighbour, thus in total three numbers for the next 12 spins, always flat bet 1 unit each.

When one of the three betting numbers comes, I add one more neighbour,this time from the table layout.
So far we have 4 numbers to flat bet with 1 unit each for the next 9 spins.
Let's see if you keep on winning what happens:

5 numbers flat bet with 1 unit each for the next 7 spins
6 numbers flat bet with 1 unit each for the next 6 spins
7 numbers flat bet with 1 unit each for the next 5 spins
8 numbers flat bet with 1 unit each for the next 4 spins
9 numbers flat bet with 1 unit each for the next 4 spins
10 numbers flat bet with 1 unit each for the next 3 spins
11 numbers flat bet with 1 unit each for the next 3 spins

Eleven is the maximum numbers you could bet, this may happen if your first number was 17 for example, because 17 has 2 neighbours on the wheel's layout (like every number) and 8 neighbours regarding the table layout 13,14,15,16,18,19,20,21 (yes,the diagonals too).

What if someone is lucky enough and after adding all neighbours one by one continues to win?
In this case you start adding 1 unit each time you win to only 1 of your betting numbers, you should start from your first selection and continue with the same order.
The minimum total of betting numbers are 6, for example 34 has 2 neighbours at the wheel's layout (17,6) and 3 neighbours at the table (31,32,35)
All together with 34 are six numbers.

We have seen how it might proceed if you are lucky and win frequently, this is not so rare because sometimes the croupiers are hitting specific sectors/numbers frequently (more than their probability)
Personally I've reached two times the 6 numbers bet selection after not many trials, of course this is not always the case.
Let's see what happens when we eventually lose, when you lose during 2 numbers bet selection or more, then you just pick another number and start from scratch, which means flat bet 1 number for the next 36 spins.

There is only one exception, if you lose during 1 number bet selection, in that case you pick another number but this time the betting wouldn't be flat, each and every time our number fails to hit we would add some interest by adding 1 unit.
So the bet on our number would be like this:
1st spin 1 unit
2nd spin 2 units
3rd spin 3 units
4th spin 4 units and so on till your number eventually appears or till you have lost for 37 spins in a row.

If you lose for second consecutive time your 37 bet cycle,this means that somewhere ahead are 4 more winning cycles/rounds but you would only need 2 of them in order to overcome the 2 negative ones.
You change again the number and continue with the dynamic progression till your winning cycles/rounds equals your losing ones.

Let's calculate the losing and winning totals by betting with the dynamic progression instead of the flat bet.
Remember that the average expectation is to lose 13 times within 37 cycles/rounds, so the total loss will be:
[13 x (1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37)]=>
13 x 703 = -9139 units

Now let's calculate the total amount of profit:

[(7 x 35) - 21] + [(8 x 35) - 28] + [(9 x 35) - 36] +[(10 x 35) - 45] + [(11 x 35) - 55] + [(12 x 35) - 66] + [(13 x 35) - 78] + [(14 x 35) - 91] + [(15 x 35) - 105] + [(16 x 35) - 120] + [(17 x 35) - 136] +[(18 x 35) - 153] + [(19 x 35) - 171] + [(20 x 35) - 190] + [(21 x 35) - 210] + [(22 x 35) - 231] + [(23 x 35) - 253] + [(24 x 35) - 276] + [(25 x 35) - 300] + [(26 x 35) - 325] + [(27 x 35) - 351] + [(28 x 35) - 378] + [(29 x 35) - 406] + [(30 x 35) - 435] =>

(245 - 21) + (280 - 28) + (315 - 36) + (350 - 45) + (385 - 55) + (420 - 66) + (455 - 78) + (490 - 91) + (525 - 105) + (560 - 120) + (595 - 136) + (630 - 153) + (665 - 171) + (700 - 190) + (735 - 210) + (770 - 231) + (805 - 253) + (840 - 276) + (875 - 300) + (910 - 325) + (945 - 351) + (980 - 378) + (1015 - 406) + (1050 - 435) =>

224 + 252 + 279 + 305 + 330 + 354 + 377 + 399 + 420 + 440 + 459 + 477 + 494 + 510 + 525 + 539 + 552 + 564 + 575 + 585 + 594 + 602 + 609 + 615 = +11080

We deduct 9139 from 11080 and we find 1941 net profit, therefore the negative expectation has been turned into positive!
But wait, there are more good news!

Since always the first losing cycle/round costs us 36 units instead of 703, that's why you don't need the exact probability to happen (2 winning cycles for every 1 losing cycle), you need approximately equal winning/losing cycles.
I say approximately because you never know in which spin your number is going to appear, thus the net gain differs.
Let me put it this way,if after 2 losing cycles you have 2 winning ones, then you are in profit and re-start from 1 number flat bet with 1 unit for 36 spins.

But after 3 or more consecutive losing cycles you would need the same amount of winning cycles plus 1 more.
Even in such situation, you can be in the positive with worst results than what probability theory supports.
For example in order to overcome 3 losing rounds, I just need 4 instead of 6 which probability dictates as average.
Of course,the results could also be better than average!:-)

Just remember that in the first phase, while we flat bet, we try to find the possibility to win by frequent repeaters.
We build slowly and safely a net gain and we don't limit the possibility for more profits (sky is the limit!) but we limit the loss.

During any stage of the 1st phase (flat bet) the maximum amount we risk is 36 units or less, if you don't lose during the 1st (1x36) or 2nd stage (2x18) of the first phase, then you would be in the positive.
The longer you keep on winning with the flat bets, the more would be the profit, it's all about what happens first.

Under any circumstance you will know what to do next, I'd recommend a total bankroll of 2000 minimum, 6000 average and 10000 units maximum in order to overcome occasional distribution anomalies.

Angelo A.

What I'm about to present you crosses the boundaries of conventional thinking.
That's why requires a willingness to learn and achieve what have never been done before.

So if you feel that you already know enough and nothing new could fit in your brain together with what you already know, you may leave now, it would be better for all of us.

The "Pandora's Box" is an original and unique way to provide you an insight of the roulette number procedure.
What it seems random could be just a deception...
Random seems only when there is a gap of missing knowledge, this is where "Pandora's Box" comes, to fill your gap and make you see roulette from a new astounding angle!

My next post will provide you an analytic description and instructions.
Warning, this is not for beginners and "narrow minds".

History repeats - Everything changes, yet remains the same...
Constant Deja Vu Turns Your Life Into A Terrifying Time Loop

Now imagine living with the feeling of going in circles all day, every day.
No matter what you do, the moment you do it, you feel this jarring sense that you've done the exact thing you're doing and that you're living in a goddamned time loop.

It's kind of like Groundhog Day, only without the gift of knowing what's coming -- only after you experience the thing you say,
"Yep, I now remember doing this exact same thing."

Deja vu, as you experience it, is just a momentary glitch where your brain tells you that something you've just seen is actually being fed to you by your long-term memory.
It feels weird for five seconds and then you move on into a double deja vu experience
("I remember doing this before, and feeling like I had done it before").

Until slowly all of us will realize that we're all living our lives over and over, in a repeating cycle of circular time, with no escape.

[attachimg=1]

Calculations show that the theoretical other end of a black hole, a "white hole", is a time-reversed version of the black hole.
In other words, the black hole draws matter in and compresses it, while a white hole spews it forth.

This compression and expansion of matter is mathematically equivalent to the creation of a universe.
The implication is that each black hole in our universe may contain its own universe inside it.

Consequently, our own universe should itself be inside a black hole, which in turn would be inside its own universe as well.
It's like a never-ending series of Russian nesting dolls or this:

[attach=8]

''Don't try bending its will, it's impossible, instead see yourself bending within it''
Ezekiel 1:1–3:27

''Now it came to pass in the thirtieth year, in the fourth month, on the fifth day of the month...
Then I looked, and behold, a whirlwind was coming out of the north, a great cloud with raging fire engulfing itself;

...also from within it came the likeness of four living creatures and this was their appearance:
each one had four faces, and each one had four wings.

...a wheel was on the earth beside each living creature with its four faces.
The appearance of the wheels and their workings was like the color of beryl, and all four had the same likeness.
The appearance of their workings was, as it were, a wheel in the middle of a wheel.

[attachimg=3]

When they moved, they went toward any one of four directions;
As for their rims, they were so high they were awesome; and their rims were full of eyes, all around the four of them.
When the living creatures went, the wheels went beside them; and when the living creatures were lifted up from the earth, the wheels were lifted up.
Wherever the spirit wanted to go, they went, because there the spirit went; and the wheels were lifted together with them, for the spirit of the living creatures was in the wheels.

[attachimg=4]

D'evils code
Revelation 13:18

One who understands can calculate the number of the beast, for it is a number that stands for a person, his number is 666*.

0+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36 = 666 

Revelation 21:17

The angel measured the wall* using human measurement, and it was 144* cubits thick.

wall = limit

4 * 36 = 144 (4 cycles)

[attachimg=5]

Encrypted mnemonics

''Round like a circle in a spiral, like a wheel within a wheel
Never ending or beginning on an ever spinning reel

Like a snowball down a mountain, or a carnival balloon
Like a carousel that's turning running rings around the moon
Like a clock whose hands are sweeping past the minutes of its face

And the world is like an apple whirling silently in space
Like the circles that you find in the windmills of your mind!

Like a tunnel that you follow to a tunnel of its own
Down a hollow to a cavern where the sun has never shone

Like a door that keeps revolving in a half forgotten dream
Or the ripples from a pebble someone tosses in a stream

Like a clock whose hands are sweeping past the minutes of its face
And the world is like an apple whirling silently in space
Like the circles that you find in the windmills of your mind!

Keys that jingle in your pocket, words that jangle in your head
Why did summer go so quickly? Was it something that you said?

Lovers walking along a shore and leave their footprints in the sand
Is the sound of distant drumming just the fingers of your hand?

Pictures hanging in a hallway and the fragment of a song
Half remembered names and faces, but to whom do they belong?

When you knew that it was over you were suddenly aware
That the autumn leaves were turning to the color of her hair!

Like a circle in a spiral, like a wheel within a wheel
Never ending or beginning on an ever spinning reel

As the images unwind, like the circles that you find in
The windmills of your mind!''

[attachimg=6]

Everything or nothing?

''For after all what is man in nature?
A nothing in relation to infinity, all in relation to nothing, a central point between nothing and all and infinitely far from understanding either.
The ends of things and their beginnings are impregnably concealed from him in an impenetrable secret.
He is equally incapable of seeing the nothingness out of which he was drawn and the infinite in which he is engulfed.''

B. Pascal

[attachimg=7]

Instructions:

Every third bet raise each position by 3 units.

Continue to do so till you broke or till the bank breaks.

I wish you enjoy it as I did!;-)[attachimg=1]

INTRODUCTION

First of all, for those who don't know what the initials R.N.G. mean is: Random Number Generator.
RNG is a program and like any other program, which has been created by humans, has vulnerabilities because is in the human nature to generates faults.
The purpose of this manual is to exploit those "vulnerabilities" by interpreting properly the signs we are receiving while gambling online and offline.With a different perspective, the same outcomes would produce different results...
Imagine roulette as transmitter and you the receiver, the "contact" would fail only if you wouldn't "decode" the "messages".
Thus it's a constant update of the statistical data, or the "signs" if you prefer.#In order you to be Up-to-date you should have 100 % concentration on the time of action and keep a record till you stop gambling.
Roulette has no memory but the repetition of certain patents is totally irrelevant with memory.

ABOUT RNG

The programmers have decided that they would let the RNG do all the dirty work.
The game of roulette will use the next RNG on the list to determine how the path is created.
If the path ends in a vertical direction (upwards or downwards), the RNG will be any number from 19 through 36 which means HIGH.
If the path is horizontal (leftwards or rightwards), the RNG will be any number from 1 through 18
(LOW, including number 0).
If the last two numbers generated a path with direction from up to right, right-up, left-down,down-left, left-up, up-left, right-down and down to right, then this means NO BET!
Note that this doesn't pinpoint the exact number.

Just imagine roulette wheel as a compass,with its top on the number Zero, now split the wheel in four parts, upper, down, left and right.
Take the last two numbers and connect them with a line on the wheel...how is the direction you've just created?
Towards what direction?
Maybe sounds complicated and confusing, but it's really easy and like every other thing in life, it could be a habit after some practice.
So how can we exploit this theory to predetermine pseudo-random numbers?
To fully manipulate the RNG sequence, we need to make a list of numbers.
I will designate the letter L to represent the range of 0-18 (whenever the reconstructed RNG path makes a vertical path) and the letter H to represent the range of 19-36 whenever the reconstructed RNG path makes a horizontal path).
Once we have written down our first RNG, press the spin button to generate another one.
Make another loop (spin) like the previous example and record the next RNG.
(Remember that the RNG sequence is pre-determined)
Take a look at this example:H - L - H - L - L - H - H - H - L - L
Depending on the situation, you may want to make this list shorter or longer.

But before that, let's see how the RNG is actually used in roulette.
What is the RNG used for?
One of the more prominent uses of the RNG is in calculating hit rate.
When betting, both your prediction and the opposite outcome will have a hit rate, the percentage or likelihood that a wheel's section will hit or miss.
While the RNG does NOT calculate these predetermined stats (those are based on actual odds),
it does determine a number that will be used to see if your bet will succeed or not.
Let's use the example we had earlier only this time, we'll make up numbers to better illustrate it.
H   L   H   L   L   H   H   H   L   L
24 18 32 14 15 33  31 27  12  4
You can use RNs (Random Numbers) the same way you found them, by forcing the game to reconstruct a path with two possibilities.
If you wish to use 2 RNs (Random Numbers) in a list, make a loop (spin) until the path is made (up to down or left to right and vice versa), press spin again, make another loop until the path is remade, press spin, then bet accordingly.
The game uses the previous numbers in the sequence and averages them to determine hit rate odds.
If this number is smaller than a bet's hit rate percentage, the prediction will hit (succeed).
If this number is equal to or larger than your bet's hit rate percentage, the bet will miss (fail).
When predicting correctly the game will use 3 RNs, two for updating outside bets odds and one for the numbers.
If you loose, the game will only use the 2 RNs for updating hit rate odds.
Any predicted straight up number hit will use 4 RNs.The RNG is also used when your units are growing, once you gain 100 units, the stats will be updated.
When updating, the odds may increase and/or decrease accordingly any of the six possible stats (outside bets).
The game will use the next 6 RNs (random numbers) in the RNG sequence to determine the odds that each stat's (outside bets) odds will go up and/or down.
The order of the level-up/down sequence is LOW,EVEN, BLACK, HIGH, ODD, RED.
It's slightly different than the order presented in the table layout (which is LOW, EVEN, BLACK, RED, ODD, HIGH from the left to right).
Let's say you won your bet, how many numbers you should calculate to determine next spin's hit rate (odds)?
If you answered 3, you are right.
For example the last three outcomes were 24 plus 36 plus 7 to get 22.33 % (24 + 36 + 7 = 67 / 3 = 22.33)
Since 22.33 % is smaller than approximately 50 %, an outside bet (low/high,black/red,even/odd) will be successful.
Skipping 2, 3, 4 or 6 RNs (Random Numbers) will produce the hit rate odds of the next spin.
You get the picture now?This is the idea behind the linear congruential generator (pseudo-random-number-generator).

ROULETTE WHEELS
My theory is a careful calculation and not a guesswork based on hunches and telepathy.
Furthermore it's much more simpler, easier and faster than any other VB method out there, thus more practical and better.
A small note for those who don't know what the initials VB mean is: Visual Ballistics.
A big number (corresponding to the circumference of the wheel) times a big number (the number of trips made around the wheel before the ball comes to rest) yields a very big number (the total distance that the ball travels).
Adding this distance to the starting point (the release point of the ball) determines exactly where the ball will end up.
Taking the remainder of this total with respect to the wheel circumference determines the final position of the ball, by subtracting off all the loops made around the wheel by the ball.
Once you clock the rotor's speed you won't have to re-calculate it because rotor's speed is stable.
Croupier's or if you prefer, ball's speed is slightly different on every spin.
Since we can't bet during the last rotation of the ball before it rests on one of the 37 pockets, we have to take the average speed of the current croupier.
Therefore we have to update/re-calculate the ball's speed with every new croupier or whenever we think it's necessary.In order to time the rotor and the ball, it's much better to use a digital timer because even fractionsof the second do count towards a significant difference on the outcome.
Therefore you can't perform this calculation so precisely in your mind, the easiest and better way of a digital timer is strongly recommended.
Watch closely the spinning rotor, watch for the zero,or any other number of your choice, to start and pass a specific point A of the wheel,this point could be a deflector.
Zero is easier to mark because of the green color.When zero reaches that specific point A (deflector), push your timer's stop button immediately.
That concludes the timing of the rotor, from my experience, it's usually around 1.2 seconds for a full rotation (from point A back to the same point A).
The rotor's speed won't change, so now you must focus on timing the ball which is harder.
Like you did for timing the rotor, the same way you will time the ball, watch closely where the croupier is releasing the ball on the wheel, start timing from that number till the ball returns to the same number after the first rotation around the wheel's rim.
Not every croupier is throwing the ball with the same power, neither is exactly the same power from spin to spin.
An average release power is 14 full rotations, when you have a croupier who from the time he/she releases the ball till the time the ball lands in one of the 37 pockets, makes 14 full rotations which is equal with an average time of 0.8 seconds per rotation.
The time of the first rotation is the fastest till the time of the last before it falls, which is the slowest.
So not every rotation is the same speed but we need the average, in order to achieve this you need to time the first and last spin, add the two durations and divide the sum by two.
Now you have the average time per rotation, multiply this duration by the total number of rotations and you have the total rotation time of the ball.Like I said the release power is not the same, that's why you need to time the croupier from 5 up to 10 spins before you place your first bet.
This way you will have the average timing of your croupier.
Next thing to do is to divide the total rotation time of the ball by the rotors spinning time.
For example the croupier is throwing the ball with such power which makes the ball rotating 14 times before it lands and this happens 7 out of 10 times, 2 times makes 13 rotations and 1 time 15, the calculation would be the following:
14 (rotations) x 0.8 (average secs/rotation) = 11.213 (rotations) x 0.9 (average secs/rotation) = 11.715 (rotations) x 0.7 (average secs/rotation) = 10.5(11.2 x 7) + (11.7 x 2) + (10.5 x 1) / 10(78.4 + 23.4 + 10.5) / 10112.3 / 10 = 11.23
This is the average timing of your croupier, in order to pre-determine where the ball will fall, you should divide the average timing of your croupier by the rotors time.11.23 / 1.2 = 9.35
This means that the ball will land 35 % further from the release point.
If you wonder what means 35 % further, then consider that the wheel has a total of 37 numbers,so the 100 % is 37 numbers, how much would be the 35 % ?35 % is something more than the 1/3(one third) of the wheel, if we divide 37 by 3 equals 12.33, thus approximately 13.
Which means 13 numbers after the releasing point, when saying after I mean towards the ball's direction and not towards the rotor's.
Due to the deflectors it's strongly advisable to place your bets on 12 numbers, 3 numbers before the number we found from the aforementioned calculations plus 9 numbers after the same number (including the pinpointed number)
When you win, you will earn two times your bet (net profit) or three times your bet accumulated profit (including your bet).
The way you bet it's totally up to you, to bet on twelve numbers is just my suggestion, you may bet as many or as few numbers you wish, with or without any betting progressions.
Like I said from the beginning, my aim is to reveal you a way of determining the outcome and not to tell you HOW MUCH but WHERE to bet.
The quantity is better being determined by your budget / bankroll.