Quote from: 3Nine on August 18, 2016, 11:53:54 PM
Ok, you're still not seeing it.

VdW is not needed - at all.

I'm seeing it mate... is it a red, is it a black? No - its super VdW man!

Just the defining element?

Yeah, it's not about gaining edge per se... I wish I could give a clue - not that I'm under oath or anything... what's an important thing in video editing? OH NO, I've given away too much... 

I think VdW can win on R/B, but something else is needed to really understand it's potential.



I thought very hard about this for many months, but in the end I wasn't able to guess the answer by chance.. it was only after several tests and coaching from one of Priyanka's best students that I finally stumbled across the secret. However, the answer is here in Priyanka's quotes from RouletteForum.cc. If you do get to discover it then you will be shocked. Nothing is really random!

QuoteIMO as the outcomes are always 50/50, that 1 spin you skip that leads to a loss might as well lead to a win. You don´t know if you´re losing pears or apples until they have just hit.

what is the significance of this statement?
You have made a beautiful point there psimoes. You will never know if you are losing pears or apples until they have just hit. If and if only there is a way. But here i would like to remind that Vdw is a versatile theory. It can be used in a number of ways. The simplified statement is if you are having two colours, then there is no way of colouring from 1 to 9 without creating an arithmetic progression of the same colour. As many have pointed out, it doesn't increase the probability of the next spin to be a certain colour. So there is no usability there.

However, can we use it beyond colours? Yes. Let us explore some possibilities to understand how versatile this is without considering the usability of this theorem.

Example 1
Consider the spins 15, 21, 23, 26, 15, 25, 33, 16, 28, 23, 14. Translating this to colours it will read B, R, R, B, B, R, B, R, B, R, R. Now let's read the outcome as whether the colour was same as previous colour (S) or different from previous colour (D). The above sequence will read D, S, D, S, D, D, D, D, D, S. We know that within 9 of these events there will be at least one arithmetic formation with D or with S.

Example 2
Same set of spins. Consider the outcomes as whether current dozen is different(D) or equal (S) to the previous dozen. The sequence will read S, S, D, D, D, S, D, D, D, S. We know that within 9 of these events there will be at least one arithmetic formation with D or with S.

Example 3
Same set of spins. Consider the outcomes as where the dozens could be expressed in a clock with a clockwise movement taking us from dozen 1 -> dozen2 -> dozen 3-> dozen 1. The relation between two dozens could be expressed as either Clockwise(CW) or Counter clock wise(CCW), denoting the shortest distance to reach the next dozen. If both dozens are same then it is considered CW. The sequence for the same set of spins will now read – CW, CW, CW, CCW, CW, CW, CCW, CW, CCW, CW.   We know that within 9 of these events there will be at least one arithmetic formation with CW or with CCW.

I know there will be lots of questions around so what? What is the applicability in roulette. Sorry, I don't have an answer. It is yet to be seen, but I have an inkling that this versatility could be put to use somehow when we are having two variables that do not essentially have a 50-50 probability appearing, but could or might give an advantage when lining up in a VdW sequence.
http://www.rouletteforum.cc/index.php?topic=17014.75 (read a bit more about it here)