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**www.Roulette.tools / Re: 98-unit parachute**

« **on:**June 05, 2019, 12:51:04 pm »

Hello Victor - I always use the binomial probability with parachute methods.

Where each location has a 50% chance to hit like the EC.

A EC has 50% with one attempt

A Dozen has 50% with two attempts

A Line has 50% with four attempts

A Split has 50% with twelve attempts

Look at this:

Half +1

Dozen +1

Dozen +0

Line +2

Line +1

LIne +0

Line -1

Split +10

Split +9

Split +8

Split +7

Split +6

Split +5

Split +4

Split +3

Split +2

Split +1

Split +0

SPlit -1

Now I know the binomial distribution work with the same probability as EC bets.

You only need to write down the results into groups of four and you will get sixteen different patterns to emerge.

Same as 4 EC bets.

Other solutions are to use eight patterns into groups of three.

A line has 50% to win with four attempts

The street has 50% to win with eight attempts

Single nr has 50% to win with twenty-five attempts.

Line+5

Line +4

Line +3

Line +2

Street +7

Street +6

Street +5

Street +4

Street +3

Street +2

Street +1

Street +0

Single +23

Singe +22

Single +21

Single +20

Single +19

Single +18

Single +17

Single +16

Sinlge +15

Single +14

Single +13

Singe +12

Single +11

Single +10

Single +9

Single +8

Single +7

Single +6

Sinlge +5

Single +4

Single +3

Single +2

Single +1

Single +0

Single -1

Same as 3 EC bets.

Now the patterns is same as EC where you get XXX XOO XOX OOO OXX OXO and so one.

Cheers

Where each location has a 50% chance to hit like the EC.

A EC has 50% with one attempt

A Dozen has 50% with two attempts

A Line has 50% with four attempts

A Split has 50% with twelve attempts

Look at this:

Half +1

Dozen +1

Dozen +0

Line +2

Line +1

LIne +0

Line -1

Split +10

Split +9

Split +8

Split +7

Split +6

Split +5

Split +4

Split +3

Split +2

Split +1

Split +0

SPlit -1

Now I know the binomial distribution work with the same probability as EC bets.

You only need to write down the results into groups of four and you will get sixteen different patterns to emerge.

Same as 4 EC bets.

Other solutions are to use eight patterns into groups of three.

A line has 50% to win with four attempts

The street has 50% to win with eight attempts

Single nr has 50% to win with twenty-five attempts.

Line+5

Line +4

Line +3

Line +2

Street +7

Street +6

Street +5

Street +4

Street +3

Street +2

Street +1

Street +0

Single +23

Singe +22

Single +21

Single +20

Single +19

Single +18

Single +17

Single +16

Sinlge +15

Single +14

Single +13

Singe +12

Single +11

Single +10

Single +9

Single +8

Single +7

Single +6

Sinlge +5

Single +4

Single +3

Single +2

Single +1

Single +0

Single -1

Same as 3 EC bets.

Now the patterns is same as EC where you get XXX XOO XOX OOO OXX OXO and so one.

Cheers