Normally we consider baccarat outcomes just in form of BP hands (I omit Ties for simplicity)
There are many ways to register BP results.
Asian players like to place BP results in orizontal lines whereas european players tend to utilize a vertical registration.
Then there are many "complex" forms of classification (for reference see WOO site) and naturally no one will give profitable betting spots to the player.
Every classification will act as an "on-off" pc work. We either register B or P. Period.
I mean nobody cares about HOW such opposite results have come out.
Since I strongly think the game is beatable for its asymmetrical nature, let's try to concentrate more about this important topic.
To get an asymmetrical hand (AS), a hand capable to mathematically shift the 50/50 results, some conditions must be fulfilled. Then we should consider the actual outcomes of every AS hand per any single shoe.
A. Player side must draw
B. Banker side must have 3, 4, 5 or 6 point.
We know that on average this situation comes about 8.6% of the times.
For every AS situation produced, Banker side will get a 15.7% mathematical (on average) edge.
That means that after any AS hand, on average Banker will win 57.85% of the times and Player the remaining 42.15%.
Besides what some magic system sellers j.erks have stated claiming a 70% or more edge for the player by unkown reasons, the best mathematical undeniabale average edge a baccarat player could have is right based upon this 57.85-42.15 proposition decurted by the B tax.
That is a player capable to bet Banker side only or mostly when an AS hand wil take place will destroy the game.
The rest, mathematically speaking, is a totally worthless speculation.
Average apparition of an AS hand per any single shoe.
Assuming 70 BP decisions per any shoe, on average we'll expect to get an AS situation nearly one time over 8.14 hands.
Obviously, per every single shoe this ratio almost never will fit this ratio, as any card distribution will produce countless combinations.
For example, when Banker shows a lot of 3,4,5 or 6 points and Player simultaneously won't draw (6,7,8 or 9) no AS hand could arise and the same happens whenever Player must draw having the Banker a 0, 1, 2, 7, 8 or 9 point.
So a separated registration of those two A and B conditions' apparition will make a very different scheme differently than a mere BP registration. And that's just the first step.
Summary of the first step.
Player will draw an average of 50.3% of the times and that is the first condition to get an AS hand, so this situation will mostly follow a 50/50 proposition, yet understanding that bac is a dependent card game; at the same time to have an AS hand first condition fulfilled, Banker must have a 3, 4, 5 or 6 point and such event will happen less probably than the opposite bunch of B outcomes including 0,1,2,7,8 and 9 points knowing that 0 will be the most likely outcome over any other possible result by a multiplied 1.5 value.
Thus and independently of the P draw/no draw situation, on the B side we'll get the AS probability of 1,1,1,1 vs the opposite probability of 1,1,1,1.1, 1.5. Wholly considered the ratio is 4/6.5.
In a word, to get an AS hand any card distribution must precisely intersect a 50.3% average P probability spot with a 38% average B probability.
Since baccarat is a finite and card dependent process game, we could get some help studying certain statistical deviations.
Next time I'll talk about the second step, that is the AS actual outcomes acting per every shoe.
as.
There are many ways to register BP results.
Asian players like to place BP results in orizontal lines whereas european players tend to utilize a vertical registration.
Then there are many "complex" forms of classification (for reference see WOO site) and naturally no one will give profitable betting spots to the player.
Every classification will act as an "on-off" pc work. We either register B or P. Period.
I mean nobody cares about HOW such opposite results have come out.
Since I strongly think the game is beatable for its asymmetrical nature, let's try to concentrate more about this important topic.
To get an asymmetrical hand (AS), a hand capable to mathematically shift the 50/50 results, some conditions must be fulfilled. Then we should consider the actual outcomes of every AS hand per any single shoe.
A. Player side must draw
B. Banker side must have 3, 4, 5 or 6 point.
We know that on average this situation comes about 8.6% of the times.
For every AS situation produced, Banker side will get a 15.7% mathematical (on average) edge.
That means that after any AS hand, on average Banker will win 57.85% of the times and Player the remaining 42.15%.
Besides what some magic system sellers j.erks have stated claiming a 70% or more edge for the player by unkown reasons, the best mathematical undeniabale average edge a baccarat player could have is right based upon this 57.85-42.15 proposition decurted by the B tax.
That is a player capable to bet Banker side only or mostly when an AS hand wil take place will destroy the game.
The rest, mathematically speaking, is a totally worthless speculation.
Average apparition of an AS hand per any single shoe.
Assuming 70 BP decisions per any shoe, on average we'll expect to get an AS situation nearly one time over 8.14 hands.
Obviously, per every single shoe this ratio almost never will fit this ratio, as any card distribution will produce countless combinations.
For example, when Banker shows a lot of 3,4,5 or 6 points and Player simultaneously won't draw (6,7,8 or 9) no AS hand could arise and the same happens whenever Player must draw having the Banker a 0, 1, 2, 7, 8 or 9 point.
So a separated registration of those two A and B conditions' apparition will make a very different scheme differently than a mere BP registration. And that's just the first step.
Summary of the first step.
Player will draw an average of 50.3% of the times and that is the first condition to get an AS hand, so this situation will mostly follow a 50/50 proposition, yet understanding that bac is a dependent card game; at the same time to have an AS hand first condition fulfilled, Banker must have a 3, 4, 5 or 6 point and such event will happen less probably than the opposite bunch of B outcomes including 0,1,2,7,8 and 9 points knowing that 0 will be the most likely outcome over any other possible result by a multiplied 1.5 value.
Thus and independently of the P draw/no draw situation, on the B side we'll get the AS probability of 1,1,1,1 vs the opposite probability of 1,1,1,1.1, 1.5. Wholly considered the ratio is 4/6.5.
In a word, to get an AS hand any card distribution must precisely intersect a 50.3% average P probability spot with a 38% average B probability.
Since baccarat is a finite and card dependent process game, we could get some help studying certain statistical deviations.
Next time I'll talk about the second step, that is the AS actual outcomes acting per every shoe.
as.