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The Active Twins

Started by Buffalowizard, January 22, 2014, 01:25:13 PM

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Buffalowizard

This is a system based on splitting the layout into 4 sets of 9 numbers.

1-9
10-18
19-27
28-36

We mark them 1,2,3,4

Then as they appear, we note them in a 2x3 grid like this one for example:

2 4
3 3
2 3

Now this is similar to another system I posted here a while back, but groups
of 9 seem to behave better so give this a whirl.

Basically you wait for the first number to show

2

Then , going horizontally, left to right you bet for a repeat, or double, or twin.

2 3

No win, carry on - noting that you bet again for 2, because you are going for a vertical twin.

2 3
4

Still no joy, now bet numbers 3 and 4 = 18 numbers in total

2 3
4 4

win, start a new grid from scratch.

That's basically it. Don't count zeros. Some grids you will only bet 9 numbers, (or 3 streets)
others will be a mix of 9 and 18, so a little bit of progression  may be necessary, but it pulls itself
out of holes.

Here are some from real spins to show.

4 1
2 1 win

1 2
3 4
1 1 win

1 4
3 1
4 1 win

1 4
1    win

1 2
1    win

1 1 win

3 4
1 1  win

4 3
2 3 win

etc

BW

verrengia

Which progression do you advise??


Thanks

RoulettePlayer

Hi
It's roulette player, that system works, I tried it; it don't take long to win. Stay at 1 unit per street until you have to bet 6 street. In that case, double all the bets to insure a profit upon a win.
On a win, you balance increases according to the following formula. It's bet size multiplied by the number of empty spots on the board. Keep track of your last high balance anytime.
For example, if your last high balance was $50 and you current balance is $48, you are 20 units behind at 10 cents a bet. If you have to bet on 6 streets, you have 6 empty spots and in order to make a profit on a win, the bet size have to be 4 units. Your balance will increase by 4 multiplied by 6 empty spots for a total of 24 units. That brings you 4 units ahead.

If you don't understand, just try it for fun. Because sometime you bet on 3 streets and sometime on 6 streets, there is no fixed progression to follow. Use the formula to ensure a profit on a win.

Good luck


ludo8400


I have a problem....

What are you doing with this spins

4 - 12- 15- 21

1 2
2  ?

ludo8400

mogul397

Can you show an example of betting amounts and
profit/loss?

I notice some of your example the 4th is a win, presumably
meaning you bet both horizontal and vertical.

Show how the math would work Please?

ludo8400

@Mogul397

We cannot see in the first item from Buffalowizzard what to do, if the vertical and horizontal are the same?

ex.
1 2
2
What to bet after the 2 misses horizontal and vertical?

or we bet 1 and 2.?

What is your opinion?

kindly regards

ludo8400





mogul397

Quote from: ludo8400 on August 31, 2016, 12:02:49 PM
@Mogul397

We cannot see in the first item from Buffalowizzard what to do, if the vertical and horizontal are the same?

ex.
1 2
2
What to bet after the 2 misses horizontal and vertical?

or we bet 1 and 2.?

What is your opinion?

kindly regards

ludo8400

In his original description I think he says to bet both. And I was
hoping that he would clarify that and also show an example of
math for betting. The amounts, and so forth.

mogul397

Quote from: mogul397 on August 31, 2016, 12:35:47 PM
In his original description I think he says to bet both. And I was
hoping that he would clarify that and also show an example of
math for betting. The amounts, and so forth.

Below is his description.
First you get 2 and 3.  You bet vertically and bet "2".
You get the 4.  So for the bottom right spot, you are betting
4 (horizontal) and 3 (vertical).  9 numbers each, as he said.

It almost looks like you would have one vertical choice, followed by
a DOUBLE choice, followed by a vertical.  But I'd like to see how the
betting works out.



Then , going horizontally, left to right you bet for a repeat, or double, or twin.

2 3

No win, carry on - noting that you bet again for 2, because you are going for a vertical twin.

2 3
4

Still no joy, now bet numbers 3 and 4 = 18 numbers in total

2 3
4 4

ludo8400

@MOGUL 397
Yes but bufalowizard doesn't gave an answer on my question

ex.
9
12
16
24

So 1
horizontal 2

12
now vertical is 16=2

and we have
12
2

24 is next number but we can't play because we have not 2 niners but just one  : 2

regards
ludo8400

mogul397

You mean having 2 as both choices?
I understand.

I THINK you would just bet 2.

But it doesn't address the question of actual money bet.

Buffalowizard

sorry for late reply, I was washing my hair.

Yes, you would just bet 2, so 9 numbers.

Progression is anyone's guess - experiment with it

BW

ludo8400