+ Register

[21 Aces]

I think you can have the exact same shoe displaced if the 2nd cut you place on the shoe is at the exact right spot and the burn cards add up to the exact number of hands to displace as well which (given 11 burn cards) could be a play of 6 cards and a play of 5 cards.

The cut for shoe #2 can be anywhere and result in displacement if the cut and burn cards fall right in place such that the shoe is displaced.  Any other cut will cause a completely new shoe.

I am in the 'baccarat card shoe preparation is completely fair barring intentional rigging' camp.

[alrelax]

Here is an industry informative article from a Casino Trade Journal from 2010 describing in detail how the card manufacturers do the 'pre-shuffles', FYI.  It is not a informal type of regime with no security or checks and balances, etc. 

[Blue_Angel]

Let's say the cut is at hand 25 of shoe 1.  Now you cut it at a different location.  It may cut exactly at the end of a hand for that exact shoe (let's say this cut is after hand 33). Now you have the exact same hands of the shoe, but just displaced by 8 hands.  If the cut does not strike and displace exactly this way (at the end of a hand of the first shoe), then you have an entirely new shoe.

The most likely outcome of additional cuts is NOT to strike precisely for a displacement of the original shoe, but to create a new shoe that results in entirely different outcomes.  The only ways a house can rig the shuffle is to rig the shuffling machine some way, add or remove cards they believe will result in less high payout bets or more difficult outcomes, or create a shoe by hand with certain progressions they select.

You are wrong, depending on where the cut circumvents the decks, till that point everything would be the same and since after the cut, the remaining cards are not being dealt nothing would change except the total of dealt hands.
If I'm not mistaken the cut reduces the playing cards from the 8 decks by 20% up to 50%.
Never all 6 or 8 decks are being dealt, thus it's not changing results but how many hands will be dealt.
On other hand, the shuffle rearranges the order of the cards, therefore results will be different due to shuffling and not because of the cut.
Think of it this way, all cards can produce all possible results (bankers,players,ties), therefore are "neutral" and the only thing which makes the difference is only their order.
The shuffler could be rigged but what's the point when the player can bet either side and the casino doesn't know which in advance?!
Exception could be if they observe by the cameras the betting action and control the device remotely in real time.
It's possible but not necessarily true.

[Blue_Angel]

@21Aces,


Higher payouts? In Baccarat?
The only higher payout is for the tie, is this what you meant?
Could you define your interpretation of harder sequence?
Do you know any specific sequence which is harder for any bet selection?


As long as everybody can bet anything the casino will take its cut from the total action regardless of which side will prevail.
That's the greatest success of the casino, to set players against each other in order to have sufficient wagers on all possible outcomes, that's how house percentages work, but just imagine what would happen if all players would bet continuously the same side...a real gamble not only for the players but the casinos too!