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PINWHEEL, TEST SIM PLEASE...

Started by BEAT-THE-WHEEL, September 05, 2016, 01:03:43 PM

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Denzie

Did some testing with small units.
using the dozens coz not enough time to place bets for the pinwheel.
Did very good actually.
I used 1-3-9 and if lost then 5-15-45 and if lost 15-75-225
Didn't got to the third section though.
won very easily. If I would waited LL then I would leave the first section.  :)

BEAT-THE-WHEEL

Dear Sputnik and Denzie,
With respect,


Thanks for your replies,
and ideas.

Appreciate them.

Please elaborate.
[waiting for your reply].

Thanks.
================
The PINWHEEL,
is
Sensei Kimo Li's brainchild,
[not mine]...

and the,
"bet 4attempts,
after trigger,
for single dozen",
and,

The ,
variance avoidance strategy,
are Albalaha's, and Kattila's ideas.
[also not mine]


and ,
The
'win more than the cut losses',
a well known ideas...

===============

Sensei Kimo Li,
deduced that,
if a wheel,
being divided
into three equal pies,
[albeit green],
the probability
for each 12numbers,
to hit in next 3spins,
is 33%, for each pie.

But in short three spins,
they will not
always up to the math 33%,
but in long term,
and since the casino,
painstakingly,
making sure their wheel,
as balance, as possible,
then,
the three pies
will have almost equal hit...
33/33/33, albeit zero.
=========================
I deduced that,
  since there are
27possibilities,
for matrix3, of dozens,
albeit green,

we can filtered,
out the possibility
of 2dozens,
or three dozens,
in next three spins.

thus we wait for ,
two different dozens,
to hit,
and the next,
third spin,
must,
have one
of the three dz...
or the pesky green.

thus,
if,


If first two spin.
two same dozens,
or a zero hit,
we don't bet,

if two different
dozens hit,
we may,

1]bet all
three dozens will hit...
in three spins,
as a row of matrix3.
[single dozen bet]

2]bet,
ONLY two dozens
hit in next three spins...
[double dozens bet.]

Then,
in long term spins,
we may see,
a very stable result,
that always,
hit,
within math expectation.

eg,
in
100rows of matrix3,
there will 'always',
66/33, albeit zero.

when three different
dozens hit, in a row,
of matrix3,
it is labeled,
pw111...

and you can see, pw111,

'always', near 33%,
and by using pw111,
as trigger,
as we know,
pw111,
as 33% probability hit,
albeit green
always clustering,
then after a pw111,
hit,  a pw111,
may hit,
in next 4rows of matrix.
why?

33/100=1/3, albeit green,
then, if they clustering,
then there will always chances,
it may hit in next four rows, of matrix3.

Thus the RISK, is when,
pw111, hit less, than 30%,
then, it has chance, to
fail to hit in next four rows,
of matrix3.

if you think like this,

ie.
in an ,
'over-simplified' simulation,
of single dozen game...

if there 30red balls
and 70 black balls,
in a box,

red=+2
black=-1

[as a single dozen bet]

take out one,
and cast aside,
only bet the red ball.
how will you bet???

Sputnik


I come to one conclusion, after finding a solid selection method based upon certain principals i don't anymore share selections and keep them for my self.
Don't know how you implement Kimo Li's work - i took Contact with Kimo Li and he was at the beginning helpful and polite - but after my third email i got no more response.

This made me thinking about many things.
First i thinking about buying his book and assume i will get no slection criteria from it - but i will learn his way to divide the Wheel into different sections based upon his methodology.
Is it Worth 25 Euro - maybe.

Then i took a look at his site which is very nice and where he is Selling spreadsheets for his different methods - price around 10 Euro is ok.
So with his book and teaching and with his spreadsheet some one could search for patterns and signatures to follow or play.

This made me Think about how rare there is to buy a roulette book which include selection criterias.
Most books is only about Money management streategys and progression, same old story with all roulette books with some exceptions.

Could also see Kimo Li Selling some work for around 200/300 Euro each.
Maybe they list all clustering combinations, but i don't belive they come with when and why to bet which is the core about any gambling method.

I have not yet decide if i am going to buy Kimo Li book - because i got a bad vibe when he stop replying to my last email - maybe this is something about Three first lessons are for free and then stop.
Could also see he is Selling lessons - but then i get confused - if he does not talk and teach about selection criteria - then why would i want to get or buy lessons from Kimo Li.

Cheers

BEAT-THE-WHEEL

don't buy, don't pay, a single cent

BEAT-THE-WHEEL

Gentlemen,
Never ever pay a single cent,
for anyone for anything here.
I already revealed the basic.

Below I post, a very "easy",
pinwheel result,
for your contemplation,
Since matrix3,
has bilions of permutation,
and thus, some are easy,
and some are difficult,
and you may visualize,
a few simple strategy to win,
the keyword is the "PW111".
Take some time to
understand the basic first,
for those who has passion,
and enthusiasm,
they will "found",
some simple trigger,
and cut losses,
where profit
larger than  losses,
in short, medium, or long term.


Spielbank Hamburg
Tisch 0001
Gewinnzahlen:
=========  =====ABC
   9A 1A 12A       300 
  27C 31C  30C     003   
  7A 4A  13B       210 
10A  8A  33C       201
8A 16B 28C        111   
  14B 12A 15B      120
  16B  7A 21B      120
10A 31C   25C      102
20B  28C  9A       111   
35C  34C 29C       003   
35C   32C 6A      102
19B  7A  9A       210
29C  28C   36C    003   
26C  23B 32B      021
15B  33C   25C    012
10A  1A 35C       201
31C  6A   9A      201
32C 1A 21B        111 
24B  8A  24B      120
  30C 34C10A      102   
  32C 29C 17B     012 
   7A 23B 23B        120
20B  10A    3A       210 
28C  11A   12A       201
24B   25C  14B       021   
2A 28C   21B        111
   5A 33C 26C         102
  34C 22B  35C        012
   9A  9A 14B         210   
- 2A  28C 6A          201
28C 15B   14B         021
13B  16B 13B          030 
33C   34C 24B        012
17B  34C 16B         021
26 C 29C   1A        102
10A  31C    7A       201
   3A 21B 13B        120
22B   9A 26C         111
  23B  34C 30C       012
20B  26C  28C        012
3A 15B   19B        120
  36C 18B 36C        012
20B   3A 18B         120
22B  24B   32C       021
28C  22B   32C       012
11A  33C  24B         111
24B  35C  13B         021
   5A 31C  6A         201
26C  18B 8A           111
8A  34C  3A          201
  23B 27C 29C         012
22B  19B  14B         030
   1A 35C  16B        111
6 A 2A   12A         300   
15B   9A 17B            120
13B  2A  15B            120
  16B 34C 25C           012
   5A 35C  2A           201
4 A  7A 13B            210
  18B 15B  8A           120
  18B 8A   21B          120
   1A 8A  21B           210
  23B 31C  33C          012
4A   3A 17B            210
35C  27C 14B            012
  18B 24B   7A          120
4A  22B  14B           120
   1A  9A  7A           300 
28C  21B 30C          012
6A  17B  24B         120
   1A 32C 2A            201
2A  7A 26C             201
35C 15B 28C             012
17B  1A 30C             111
   9A 23B 19B           120
   7A 33C   21B         111
  23B 34C 7A            111
   7A 20B  23B          120
4A  11A  33C           201
13B  20B   19B          030
22B  4A  4A             210     
24B  19B 31C            021
  25C  1A  3A           201
35C   19B 21B           021
  12A 19B  7A           210
  12A 23B 32C           111 
31C  24B   7A           111
  32C 20B 31C            012
29C  16B 16B             021
  19B 17B  24B           030 
  23B 13B  13B           030 
20B  21B 5A              120
   7A 4A  31C            201
15B  12A 9A              210
  36C 20B  10A         111[x13 times]
   
====
nb being deleted.

BEAT-THE-WHEEL

You will noticed
That the pw111,
Will also series!

So what are you to do with this ?

The keyword is ,
Trigger...and . Safe.

Gizmotron

Hey, if it's the single dozen, 12 numbers, that you are going after then that one is simple. When a dozen sleeps the other two dozens have a 50/50 chance of winning. It's the same for streaks of singles in the dozens too. You just bet one of the possible two that are the choice for another single. So your trigger is a sleeping dozen or a stretch of singles. You also get the very rare repeating dozen too. These characteristics happen all the time. You just have to watch for them. Nobody knows when things will change. You just have to know that when a sleeping dozen wakes up that that trend is done. The same goes for the singles and the long repeaters. Change always happens. It's good to know what it changes to. So you observe. I teach the double dozens bets in my school but the single dozen is just as interesting. Kimo's sets of dozens are just a few of what can be created, memorized, and exploited. You just have to observe. So in those times you have a 50/50 chance and a two to one payoff. That's an interesting mix.
"...IT'S AGAINST THE LAW TO BREAK THE LAW OF AVERAGES." 

Sputnik


My understanding or what i assume is that the pinwheel method is 12 number bet.
I don't Think that is a good advice to wait for a sleeping dozen and then play a 50/50 situtation - is not working - but feel free to show an example.

Cheers

Gizmotron

Quote from: Sputnik on September 24, 2016, 03:54:05 PM
My understanding or what i assume is that the pinwheel method is 12 number bet.
I don't Think that is a good advice to wait for a sleeping dozen and then play a 50/50 situation - is not working - but feel free to show an example.


I don't either. I would prefer to win every time the dozen sleeps.


Example:




| 1  2  3 | A  B  C | 0  3  6 | P |
|       X |    X    | X       | P | -- 32
| X       |    X    |    X    | P | -- 11
|       X |       X |    X    |   | -- 33
| X       | X       |    X    |   | -- 7
| X       |    X    | X       |   | -- 8
|       X |       X |       X |   | -- 27
|-------------------| X       | P | -- 37
| X       | X       |    X    |   | -- 7
| X       | X       | X       | P | -- 10
|       X | X       |       X |   | -- 25
|       X | X       |    X    | P | -- 28
|       X | X       |    X    | P | -- 28
|       X |    X    | X       | P | -- 26
|       X | X       |       X | P | -- 31
|       X | X       |       X | P | -- 34
| X       |       X | X       |   | -- 3
|       X |    X    | X       |   | -- 35
| X       | X       |    X    | P | -- 1
| X       |       X |    X    |   | -- 12
|       X | X       |       X | P | -- 34
|    X    |    X    | X       | P | -- 23
|    X    |    X    | X       | P | -- 23



See the sleeper in the first grouping, 123's? That's an opportunity. One side of the non sleeper hits 8 times while the other hits 11 times. There's always that imbalance to guess at. But if you bet both dozens you get a perfect split every time.


Does it begin to make sense to you?




"...IT'S AGAINST THE LAW TO BREAK THE LAW OF AVERAGES." 

Sputnik


I don't understand when and why you bet - i add 100 random bits from random org - maybe you can show with them how to bet one dozen with a 50/50 situation.

Many thanks ...

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Gizmotron

Quote from: Sputnik on September 24, 2016, 05:40:39 PM
I don't understand when and why you bet - i add 100 random bits from random org - maybe you can show with them how to bet one dozen with a 50/50 situation.


Here is how. You don't need a 100 spin list to understand it. Let's say that you can in fact see a sleeping dozen. Say the first dozen from the sections on the table layout are not hitting at all. That's the 1 through 12, the low dozen. Say they haven't hit for six spins in a row and that they are going to continue not to hit for the next ten spins, just for the sake of argument and demonstration.


Got that so far?


So that implies that the other two sections, 13 to 24, and 25 to 36 are going to hit for the next ten spins, just for the sake of demonstration purposes that is. If you only place a bet on one of those two remaining sets, say the 25 to 36 set, just for the sake of argument, then you have a 50% chance of winning as long as the 1 to 12 set is still sleeping, that's means not hitting, just for the sake of demonstration that is.


So do you understand how a 50 / 50 bet could pay two to one from that?


If not, then please ask someone else at this forum to make it clear to you.
"...IT'S AGAINST THE LAW TO BREAK THE LAW OF AVERAGES." 

Sputnik


I understand that one dozen sleep and two remain - but i can not see it so common that you get 5, 10, 15, 20 to sleep on regular basis which make it hard to take advantage.
Also the selection criteria picking the right 12 numbers remain with a 50/50 situation.

My Point from the beginning was that this is a bad selection criteria - my opinion.

Cheers

Gizmotron

Quote from: Sputnik on September 24, 2016, 06:44:07 PM
I understand that one dozen sleep and two remain - but i can not see it so common that you get 5, 10, 15, 20 to sleep on regular basis which make it hard to take advantage.
Also the selection criteria picking the right 12 numbers remain with a 50/50 situation.

My Point from the beginning was that this is a bad selection criteria - my opinion.

Cheers


That's an OK opinion I guess. In 300 spin sessions I see 15 usually happen twice. I see 10 from 10 to 20 times. Course I 'm looking at 4 groups with three each for a total of 12 individual dozens when I look. So it's not good enough for you to have the casino be your personal ATM machine a few times in a 300 spin session. OK, to each their own.


I want it all so I never just pick 12, I always pick 24. That way it's 100% at half the win amount and twice the risk. You will see that it balances out. It all comes out to a net win of one for each win and you get twice as many losses with a 12 number bet. One dozen or two dozens it makes very little difference if you are hunting singles and sleepers. To ignore the opportunities because they don't happen enough is unwise.
"...IT'S AGAINST THE LAW TO BREAK THE LAW OF AVERAGES." 

Sputnik


I don't feel that the periodic sequense on a rolling basis is an issue.
This does not mean you have to bet on going and force your self facing the losing sequense.

This is the LW-Registry for the 100 trails i posted above - you did not need to show exaclty how and where you bet just show the strike ratio - but it does not matter now as you admit playing 24 numbers.

W W L W

Perfect for Regression Up & Pull
This is how the hole LW-Registry look like ...

W L W L L W L L L

W W L W W W L W L L W L L L

L W W L W

Cheers


Gizmotron

I see 13 losses and 13 wins. With bets at 2 to 1 payoffs on wins, that's far beyond spectacular. What's your secret?


Look what my Artificial Intelligence machine just did this morning:




| 1  2  3 | A  B  C | 0  3  6 | P |
| X       |       X |    X    | P | -- 12
|    X    | X       |       X |   | -- 22
|    X    | X       |       X |   | -- 19
|       X |       X | X       |   | -- 36
|    X    | X       |       X |   | -- 22
| X       | X       |    X    |   | -- 7
|       X |    X    |    X    |   | -- 29
| X       |       X |    X    | P | -- 3
|    X    |       X |       X |   | -- 21
| X       |    X    |       X | P | -- 5
|       X |       X |       X |   |  # 33 --  -- ( B & C to win next) @ 1 -- Sleepers
|       X | X       |       X |   |  # 34 --  -- Lost  -- -24 -- ( 3's & 6's to win next) @ 1 -- Sleepers
|-------------------| X       | P |  # 37 --  -- Lost  -- -48 -- ( 1 & 3 to win next) @ 1 -- Sleepers
| X       | X       | X       | P |  # 1 --  -- Won -- -36 -- ( A & C to win next) @ 1 -- Sleepers
|    X    |    X    |       X | P |  # 17 --  -- Lost  -- -36 -- ( A & B to win next) @ 0 -- Sleepers
|    X    |       X |       X |   |  # 21 --  -- Lost  -- -36 -- ( 1 & 2 to win next) @ 0 -- Sleepers
| X       |       X |    X    | P |  # 3 --  -- Won -- -36 -- ( A & B to win next) @ 0 -- Singles
|    X    |    X    |       X | P |  # 17 --  -- Won -- -36 -- ( B & C to win next) @ 0 -- Sleepers
|    X    |       X |       X | P |  # 18 --  -- Won -- 12 -- ( B & C to win next) @ 4 -- Sleepers
|       X |    X    |    X    |   |  # 29 --  -- Won -- 60 -- ( B & C to win next) @ 4 -- Sleepers
|    X    |       X |    X    |   |  # 15 --  -- Won -- 108 -- ( B & C to win next) @ 4 -- Sleepers
|    X    |       X |       X | P |  # 18 --  -- Won -- 156 -- ( B & C to win next) @ 4 -- Sleepers
|    X    |       X |       X | P |  # 18 --  -- Won -- 204 -- ( B & C to win next) @ 4 -- Sleepers
| X       |    X    |       X | P |  # 5 --  -- Won -- 252 -- ( B & C to win next) @ 4 -- Sleepers
|       X | X       |       X |   |  # 34 --  -- Lost  -- 156 -- ( 3's & 6's to win next) @ 4 -- Sleepers



It's still not selecting the best single yet, but that will be fixed soon enough.


This was a win streak. There in no way to get this kind of a result consistently.
"...IT'S AGAINST THE LAW TO BREAK THE LAW OF AVERAGES."