Cambridge English Dictionary

coincidence definition:
1. an occasion when two or more similar things happen at the same time,
especially in a way that is unlikely and surprising:
2. chance or luck:
3. an occasion when two or more things ...

Hi,
Say, every morning , when you walk toward your workplace,
you cross path with the sweet young girl....,

that's not coincidence,
because you deliberately timed your walking pace to
coincide to cross path with her...

Say, one day,
while at a traffic light, you see a Honda stoping at the red light,
followed by a Toyata, then a VW, and a Chevy. ..

Then, the next day, at around the same time, at the same red,
traffic light, you noticed, a Honda, Toyota, VW, and a Chevy...
Wow!
What a coincidence!

Will the next day, at the same time and traffic light,
the same sequence of Honda,Toyota, VW, Chevy....happen again?

Or, after a few day passed, at that traffic light, you see a Honda,
then a Toyota happen to stop behind it...
then...will the next car be a VW...
then followed by a ...Chevy?

Now, all the mathboys and experts shrieking. .
."The probability still the same, no matter what!"

Of course the probability, remain the same...

But the question, is, will the COINCIDENCE ,
meet with the same COINCIDENCE ..again?

It same like coincidentally, wise,
will "red" hit 100 time in the next 100 spins..?
(.the probability is 50/50 minus green , shriek the mathboys...)

the REDS hit 10in row, then 10in row again,
that 20red, is coincidence, but for coincidence of "10-in-row",
to hit ten of 10in row, is just impossible!

or will the green zero, hit 10 in row?
(the probability 1/37, again, shriek the mathboys)
zero hit twice, is coincidence, hit 3, is coincidence of coincidence,
4 is rare, but 10in row?

Mathboys. .. say.."yes!"
But in coincidence theory,
it may not hit in your life time, because it highly unlikely...

likewise,


in next 12spin, DS, you see six different ds hit, then another six different ds hit,
will next 6spins produce six different ds....again?!
(again, the mathboys shrieking, its 1/6 minus zero!!!!)
BUT THE COINCIDENCE HIGHLY UNLIKELY! or never in your lifetime...

or if you see dozen..123, then 123again, then....will next be 123...again?

if we wanna win, after all the lung collapsing debating with the mathboys...
we should think in term of coincidence vs coincidence term..

.this is where the "probability of coincidence", a different perspective setting.

Seems that even matrix strategy will revert to  edge, and can't win in long term, thus we need to depend on luck

Thanks Stringbeanpc,
Seems that there no way to beat them.

Thanks Stringbeanpc,

Do you mean if someone could avoid betting the matrix (as you described),
then the edge will be distorted?
(To 75%....)


and since we can't avoid them, then the edge of 2.7 green, and 1/27possibilities,  still remain....

So when you intend to bet Single dz only,
You wait for   " only 3dz/3spins.."

Say
123...now bet matrix also 3dz/3spins matrix.bet the last, third spin.
321...win...

123,
323...lose 1u.

123
111...no bet
132...win

123
222 no bet
121  ..lose 1u.

123
333
132..win
123..no bet
321 ..no bet  ...wait for virtual break, start anew....

There no edge, whatsoever,  but, the highly stable, (perceived), is helpful...

As we already know,
Apart from zero green,
There will...

Three different dz in 3spins
Only 2dz in 3spins,
3same dz in 3spins,
And 3zero in 3spins...

3different dz in 3spin=33% minus green, and 66% for other formations.


Single vs Series.
3different dz in 3spins, will repeat once, twice, thrice to infinite, but the most seen , rarely, up to six repeat.


Thus..
×××,
123,
×××.... (a single , of 3different dz in 3spins)
123,
321...twice...(a series of 2)
Xxx.

321,
123
231,..series 3.

321,
123,
213,
231....series 4, and so on to infinite...

Thus the simplest is SINGLE VERSUS SERIES (regardless of how many repeat)

The probability of single/series=66/33% minus green.

The probability of series of 2,  become series3=33% minus green.

"only 1dz or only 2dz/3spin ", also can single and series.

123,
121,...a single.
231...

231,
121,
323...series of two....
321....

123,
323,
311,
212,...series of 3,
132...

The probabilty of "non 3dz/3spins   "...single=33%    , series= 66%....minus green.

So how to bet?
When you see 3dz/3spins, you may bet...

123  that 3dz/3spins matrix.


Bet next matrix, may 3dz/3spins, or "non 3dz/3spins"

One of the advantage, they are stable, meaning they highly LIKELY, to hit
Within Math Expectation.

@stringbeanpc,
Thanks for your posting..
111   211   311
112   212   312
113   213   313

121   221   321
122   222   322
123   223   323

131   231   331
132   232   332
133   233   333

Three Same Dozens 3 out of 27
111
222
333

Three different dozens 6 out of 27

123   213   312
132   231   321

Two dozens 18 out of 27
&&&&&&&&&&&&&&&&&&&&&&&

As we know, its always 33% vs66% minus green probability.

But as the only2dz in matrix aka pinwheel,
If we forego the 111, 222, 333 matrix,
And only bet the formation of matrix consist of "only 2dz in 3spins"
Then the probability is 24probability,

Then 18/24=75%
Why 24, as we left out the 111, 222, 333.

6/24=25%...?

doesn't this sort of distorted edge, since we not bet the 111, 222, 333,
Instead of 66/33%....if we bet from the begining of 3spins, but 75% for 2dz/3spins???

Simply mean, if you bet, and lose, lose, lose, lose....you lose tens of chips, if you really have faith that your systems could outmaneuver the extreme variance, then if you wait the "lose", to go , you save the br, virtually, and continue to bet the progression, and when 33%+1hit,
You win more than 1u...

Again, OVERSIMPLIFIED EXAMPLE, so you could understand, how to avoid variance and edge

That labby, is just OVERSIMPLIFIED EXAMPLE, so you could understand.

If posive and negative always move in wave, albeit unpredictable,
We move in after extreme hit and start to bet when the line SEEMS to stabilized,
("SEEMS", why seems ,b cause we can't predict...thus seems...)

And any positive 33%+1hit produce profit.

Thus if you bet virtually HALFWAY!  after the extreme, and you "save", the unhit br....

Then again, oversimplified example.  So you could understand.

Thanks Magician and Alrelax for your views.

The variance, simply mean, the winning hits, too few, to produce a profit.
We can't predict when the EXTREME will arrive and go...
Thus we simply WAIT, for it to present itself, and go...How?
We can't predict when it will go, we simply wait till the outcome seem to hit within math expectation,
but then again, the extreme may arrive again! Thus we take the risk, that the extreme won't back2back.

In any system, you see variance come and go  in a WAVE...

If you bet any system, FLATBET,
and chart the result in a single line, you see the line moving like a snake being beaten, up and down, pointing SOUTHEAST,
due to the edge.

The up is positive variance, and down is negative variance, and the dropdown like cliff is EXTREME .
It the extreme causing us losing all our br...

If we know that variance never failed to present itself in wave, why not JUST WAIT FOR IT TO GO, WHY TAKE THE RISK!?

Gentlemen,
Since the first casino open stall, thousands of systems that people devised can't beat the casino, and the math prof.  shrieking their lung out since, that we can't have edge, or win and beatthe casino's holy grail, that namely roulette, they say we can't even win, if the wheel have no green!

Maybe we should leave the betselection and move to other plane, that avoiding extreme variance in the progression itself.

We know that, when extreme in bet selection, hit, the winning hit keep sleeping and our progression keep snowballing till we bust our br,
thus if we wait for the extreme in selection, and virtual bet the progression, till the selection stabilized,  then we bet the progression halfway, we already "save",  a bundle of our br, and proceed to win.

This way , we already avoid the edge, and avoid the debacle of busting our br.

In oversimplified example,
Labby win when 33%+1,
When we bet from the start virtually with 1u, as the 1st bet, we wait for extreme variance, and when it seem to stabilized,  we bet the labby halfway, thus the winning is more than 1u, and if losing extreme keep coming, the cut losses, is not vis a vis, and out of context , or out of sync mathematically. ?...
What your opinion?

Thanks Kattila for your view, it  very interesting,  for the concept of dozen.


Since double dozen and single dozen , hit by extreme variance, we lose when we bet them with deadly progression.

Thus we mut think out a way to
AVIODING EXTREME VARIANCE...IN THE PROGRESSION ITSELF.

not avoiding extreme variance in BETSELECTION...
but avoiding extreme variance in the.....PROGRESSION!!!


VIRTUAL BET the progression, and bet the progression in the halfway.

This way, hopefully, we win more than lose amount...imho.

People ask,
How to bet SINGLE DOZEN IN MATRIX OF 3DZ.

we bet when first and second matrix are TWO DIFFERENT DOZENS, and bet the third as SINGLE BET.

say,
Permutation of 3different-dz, may SINGLE VERSUS SERIES-OF 2, 3, 4, 5, 6..INFINITE

Thus, when a single permutation  hit, we bet it may produce a series...

123, bet next 3spins, will 3different dz , again
321, bet the third spin=1dz....hit...
The probability=33%, minus green, thus a long day wait to bet.

Thanks Albalaha for your post.

Though the probability for 3different-dz/ 3spin, will produce no edge whatsoever,
I think the coincidence of a combo to repeat itself, may due to another theory,
Probability-of - coincidences,  perhaps?

If we see a rather rare coincidence,
Say,
123, follow by...
111....then after a while...

123, followed again, by,
111....then after a while...

123...hit, will the next three spins, be
111....again?

Though the probability remain unchance, and has no edge, but the repeat of coincidence, remain highly unlikely.


The same , as to ds,
If we see, six different ds in six spins,
Will the next six spins has six different ds...again?
Though the probability remain the same , but the coincidence highly unlikely....

say,
If we see five different ds in 6spins,
123455...will the next 6spins produce...
123455....again?

Thus, if you see...
123...there be three possibilities....

If you bet any ,two dozen, then if it "only two different dz in 3spins,",.. you win...and
If it "3 different dz in 3spins"...you win...

Lose when only one dz hit, that you choose not to bet....